# Quantitative Aptitude: Time, Speed and Distance Set 4

Time Speed Distance Questions NIACL, SBI PO, IBPS PO, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

1. A man covers a distance in four equal parts. He covers first part with speed of 60 kmph, second part with 80 kmph and third part and fourth part with 120 kmph and 80 kmph respectively. Find the average speed of his journey.
A) 60 kmph
B) 80 kmph
C) 120 kmph
D) 100 kmph
E) None of these
Â  Option B
Solution
:
|—–x——|——-x——–|——-x——-|——-x——-|
60Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  80Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  120Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  80
Let x= 240 km (LCM of speed)
Time= 240/60 +240/80 +240/120 +240/80=4+3+2+3=12 hours
Avd speed=total distance/ total time=240*4/12= 80 kmph
2. A thief steals a car at 8 PM and starts driving at a speed of 80 kmph. The theft came into light at 9 PM and police started to chase him at 9 PM at a speed of 100 kmph. At what time will he be caught?
A) 2 AM
B) 3 AM
C) 12 PM
D) 1 AM
E) None of these
Option D
Solution
:
Thief has moved 80 Km in 1 hour, So distance=80 km
Time= Distance/ relative speed=80/(100-80)= 4 hour
9 PM+4= 1AM
3. A train starts from P at 8 PM and reaches Q at 11 PM. Another train starts from Q at 6 PM and reaches P at 11 PM. Find at what time they will meet each other?
A) 9:7.5 PM
B) 8:7.5 PM
C) 10:7.5 PM
D) 9:7.5 PM
E) None of these
Option A
Solution
:
Time (A:B)=3:5 => Speed(A:B)=5:3
Let distance=150 km
Speed A= 50 kmph ; Speed B=30 kmph
B starts 6 PM, in 2 hours i.e (till 8 PM when A starts) it will move2*30=60 km
remaining = 150-60=90 km
Time= distance/relative speed=90/80= 1 hour 7 mins 30 sec
hence time=8 PM + 1 hour 7 mins 30 sec= 9:7.5 PM
4. If a person goes to school fro his home at a speed of 4 kmph, he reaches 10 minute late. If he goes at a speed of 6 kmph he reaches 10 mins early. Find the distance between school and home
A) 5 km
B) 8 km
C) 6 km
D) 4 km
E) None of these
Option D
Solution
:
Direct Formula Distance= [Speed 1*Speed 2/(S1-S2)]* [(Late + Early)//60]
=4*6/(6-4)*[(10+10)/60]=4 km
5. A man takes 7 hours 30 mins in walking to a certain distance and riding back. He would have gained 3 hours 10 mins by riding both ways. How long he would take to walk both ways?
A) 600 mins
B) 640 mins
C) 680 mins
D) 580 mins
E) None of these
Option B
Solution
:
7 hour 30 mins â€“ 3 hours 10 mins =4 hours 20 mins(When riding both ways)
=> 2 hour 10 mins riding in one way
ride+walk= 7 hour 30 min —(i)
ride= 2 hour 10 min –(ii)
Diff (i)-(ii)=walk one way=5 hour 20 min
walk 2 way= 10 hour 40 mins=640 mins
6. In covering a distance the speed of A and B are in the ratio 4:5. A takes 40 mins more than B to reach the destination. The time taken by A to reach the destination is?
A) 2(1/3) hours
B) 4(1/3) hours
C) 3(1/3) hours
D) 5(1/3) hours
E) None of these
Option C
Solution
:
Speed (A:B)=4:5
Time (A:B)=5:4
Time diff=5-4=1
1=40 min
5=200 mins= 3(1/3) hours
7. Two person cover some distance at a speed of 35 kmph and 40 kmph respectively. Find the distance if one person takes 15 minute more than the other.
A) 60 km
B) 50 km
C) 80 km
D) 70 km
E) None of these
Option D
Solution
:
Speed (A:B)=35:40=7:8
Time(A:B)=8:7 ->Diff=1
1=15
8=120 min=2 hour
Distance=35*2= 70 km
8. Two busses start at same time from two stations and move towards each other at the rate of 30 kmph and 35 kmph respectively. When they meet one bus has traveled 60 km more than the other. Find the distance between the two bus stations.
A) 780 km
B) 720 km
C) 680 km
D) 750 km
E) None of these
Option A
Solution
:
The bus with higher speed moves 35-30=5 km more than the other in 1 hour
means it will move 60 more in 60/5=12 hours
Hence distance=30*12+35*12=780 km
9. A train crosses a pole in 20 seconds and a platform in 45 seconds. If the length of platform is 500 meters find the sum of length of train and platform
A) 800 m
B) 900 m
C) 1000 m
D) 950 m
E) None of these
Option B
Solution
:
Train : Platform= 20 : 25
25=500
20=400
total length=900 m
10. A train overtakes two persons who are walking in the same direction in which the train is moving, at the rate of 2 kmph and 4 kmph respectively and passes them completely in 9 seconds and 10 seconds respectively. Find the length of the train.
A) 50 m
B) 40 m
C) 60 m
D) 70 m
E) None of these
Option A
Solution
:
x/(y-2)*18/5=10 ——(i)
x/(y-4)*18/5=9 â€“(ii)
solve and get x=50 m

## 6 Thoughts to “Quantitative Aptitude: Time, Speed and Distance Set 4”

1. destiny Casimiro

last
(s-2)*9===(s-4)*10
9s-18====10s-40
s===22km/h
(22-4)*5/18*10
==50

2. Jellyfish

8/10 ty
Que3 explain pls…

3. didu ka cutuuuuu;)))))))

tyyy;)))

4. sachin shukla@ my turn 2017

ty

5. ravi

@shubhra mam
Time= distance/relative speed=90/80= 1 hour 7 mins 30 sec
hw to change 90/80 ==in hour min and sec

1. AmRITa @ bank po

Let 5min.by dividing 60 get hr and by multiplying 60 get second.5/60=1/12hr
5*60=300sec