**Directions(1-5): **Find the missing term ‘?’ of the following series.

- 18,10,12,21,46,?
809010012070Option D

*0.5+1

*1+2

*1.5+3

*2+4

*2.5+5

? = 120 - 6,12,24,?,74,116
3544304054Option B

+2*3

+3*4

+4*5

+5*6

+6*7

? = 44 - 2033,?,2054,2075,2103,2138
19982112204019052000Option C

+7*1

+7*2

+7*3

+7*4

+7*5

? = 2040 - ?,7,8,18,76,616
1517191310Option D

13*0.5+05

7*1+1

8*2+2

18*4+4

76*8+8

? = 13 - 219,?,225,249,309,429
220188190200219Option E

+1^3-1

+2^3-2

+3^3-3

+4^3-4

+5^3-5

? = 219 - A room of dimensions 12*8*6 in meter has one door of dimensions 2*1.5 m , two windows of dimensions 0.5*0.4 m and one more window of dimension 1*0.5 m. Find the cost of applying paint on the four walls along with the ceiling of the room btu excluding the door and window at Rs.40/m^2.
Rs.14848Rs.15515Rs.12550Rs.14400Rs.13284Option E

Area of four walls along with ceiling

= 2*(12+8)*6 + 12*8 = 336 m^2

Area of door = 2*1.5 = 3 m^2

Area of all windows = (2*0.5*0.4)+(1*0.5) = 0.9 m^2

Area to be painted = 336 -3.9= 332.1 m^2

Required cost = 332.1*40 = Rs.13284 - Aditya bought a bike for Rs.5x. He spent Rs. x on its repair. He marked the bike 60% above the total cost he spent on the bike. He sold the bike the Rajnish after two consecutive discounts of 10% and 25%. In this transaction, Aditya made a profit of Rs.2400 . Find the value of x.
40005000700060008000Option B

Total CP = 5x+x = 6x MP = 1.6x*6x = Rs.9.6x

SP = 0.90*0.75*9.6x = 6.48x

Profit = 6.48x â€“ 6x = 2400

=> x = 5000 - A man goes â€˜xâ€™ km downstream and returns back upstream to its original place in 12 hours. The speed of boat in still water is thrice the speed of stream and difference between downstream speed and speed of boat in still water is 4 km/hr. Find the value of x.
70 km66 km56 km64 km60 kmOption D

Speed of boat in still water = 3*4 = 12 km/hr.

Downstream speed = 12+4 = 16 km/hr.

Upstream speed = 12-4 = 8 km/hr.

x/16+x/8 = 12

=> x= 64 km - An old member of a musical band was replaced with a new member. It was found that the new average of the band of 6 members is the same as it was 4 years ago. Find the difference between the ages of the replaced member and the new member.
1815242027Option C

Let the total present age of the remaining 5 members be x.

Let the present age of the old member who is replaced be O.

Age of the new member be N and the average age 4 years ago be A.

(x+N)/6 = A —-(1)

(x+O-24)/6 = A —–(2)

From (1) and (2), we get

x+N = x+O-24

=> O â€“ N = 24 - In how many different ways the letters of the word â€˜LEVERAGESâ€™ be arranged that vowels always occupy the odd positions?
1700 ways2400 ways2200 ways1900 ways2800 waysOption B

Vowels and consonants can be arranged = (4!/3!) * 5!

= 4*120

Vowels can be arranged in five different positions = 5

Total number of ways = 120*5*4 = 2400 ways