# Mixed Quantitative Aptitude Questions Set 108

Directions(1-5): Find the missing term ‘?’ of the following series.

1. 18,10,12,21,46,?
80
90
100
120
70
Option D
*0.5+1
*1+2
*1.5+3
*2+4
*2.5+5
? = 120

2. 6,12,24,?,74,116
35
44
30
40
54
Option B
+2*3
+3*4
+4*5
+5*6
+6*7
? = 44

3. 2033,?,2054,2075,2103,2138
1998
2112
2040
1905
2000
Option C
+7*1
+7*2
+7*3
+7*4
+7*5
? = 2040

4. ?,7,8,18,76,616
15
17
19
13
10
Option D
13*0.5+05
7*1+1
8*2+2
18*4+4
76*8+8
? = 13

5. 219,?,225,249,309,429
220
188
190
200
219
Option E
+1^3-1
+2^3-2
+3^3-3
+4^3-4
+5^3-5
? = 219

6. A room of dimensions 12*8*6 in meter has one door of dimensions 2*1.5 m , two windows of dimensions 0.5*0.4 m and one more window of dimension 1*0.5 m. Find the cost of applying paint on the four walls along with the ceiling of the room btu excluding the door and window at Rs.40/m^2.
Rs.14848
Rs.15515
Rs.12550
Rs.14400
Rs.13284
Option E
Area of four walls along with ceiling
= 2*(12+8)*6 + 12*8 = 336 m^2
Area of door = 2*1.5 = 3 m^2
Area of all windows = (2*0.5*0.4)+(1*0.5) = 0.9 m^2
Area to be painted = 336 -3.9= 332.1 m^2
Required cost = 332.1*40 = Rs.13284

7. Aditya bought a bike for Rs.5x. He spent Rs. x on its repair. He marked the bike 60% above the total cost he spent on the bike. He sold the bike the Rajnish after two consecutive discounts of 10% and 25%. In this transaction, Aditya made a profit of Rs.2400 . Find the value of x.
4000
5000
7000
6000
8000
Option B
Total CP = 5x+x = 6x MP = 1.6x*6x = Rs.9.6x
SP = 0.90*0.75*9.6x = 6.48x
Profit = 6.48x – 6x = 2400
=> x = 5000

8. A man goes ‘x’ km downstream and returns back upstream to its original place in 12 hours. The speed of boat in still water is thrice the speed of stream and difference between downstream speed and speed of boat in still water is 4 km/hr. Find the value of x.
70 km
66 km
56 km
64 km
60 km
Option D
Speed of boat in still water = 3*4 = 12 km/hr.
Downstream speed = 12+4 = 16 km/hr.
Upstream speed = 12-4 = 8 km/hr.
x/16+x/8 = 12
=> x= 64 km

9. An old member of a musical band was replaced with a new member. It was found that the new average of the band of 6 members is the same as it was 4 years ago. Find the difference between the ages of the replaced member and the new member.
18
15
24
20
27
Option C
Let the total present age of the remaining 5 members be x.
Let the present age of the old member who is replaced be O.
Age of the new member be N and the average age 4 years ago be A.
(x+N)/6 = A —-(1)
(x+O-24)/6 = A —–(2)
From (1) and (2), we get
x+N = x+O-24
=> O – N = 24

10. In how many different ways the letters of the word ‘LEVERAGES’ be arranged that vowels always occupy the odd positions?
1700 ways
2400 ways
2200 ways
1900 ways
2800 ways
Option B
Vowels and consonants can be arranged = (4!/3!) * 5!
= 4*120
Vowels can be arranged in five different positions = 5
Total number of ways = 120*5*4 = 2400 ways