Directions(1-10): Read the sentence to find out whether there is an error in it. The error, if any, will be in one part of the sentence. The number corresponding to that part will be your answer. If the given sentence is correct as given, mark option E, i.e. “No error” as the answer. Ignore the errors of punctuation. Government borrowings…

Read More# Author: Shubhra

## Quantitative Aptitude: Simplification Questions Set 108

Directions: What will come in place of question mark(?) in the following questions ? 440÷20*510÷17+25 ? 785 685 585 675 none of this Option B solution: 22*30+25 =685 71.40% of 63-√1296+20=? 29 39 30 31 25 Option A solution: 5/7*63-36+20 =65-36 =29 2/5*15/8*16/21*8/28*56 = ? 32 80 128 64 none of this Option solution: 2/5*15/8*16/21*8/28*56 =8*8 =64 …

Read More## Sentence Rearrangement for Upcoming Exams – Set 62

Directions(1-10): In the given question, a statement has been divided into five segments, each of which is denoted by (A), (B), (C), (D) and (E). Rearrange all the segments to form a coherent statement. A) bickering over ballot accessB) that have been aC) sticking point for yearsD) fanned the flames of partisanE) The coronavirus outbreak has EDABC DEBAC DBCEA BDCAE…

Read More## Quantitative Aptitude: Problems on Ages Set 18

Ratio of the ages of A and B is 2:3 and the sum of the squares of their ages is 208 years . Find the age of B 4 years ago. 6 4 9 8 none of this Option D Let, their ages be 2x and 3x years . (2x)^2+(3x)^2 =2084x^2+9x^2 =208x^2=16x=4 Age of A = 8Age of B= 124…

Read More## Mixed English Questions for upcoming Exam — Set 407

Directions(1-5): In the given question, four words are numbered 1, 2, 3 and 4. Of these, the positions of two words may be incorrect and need to be exchanged to make the sentence correct. Find the two words which need to be exchanged. In case the given sentence is correct, your answer is (E) i.e. No correction required. He wasn’t…

Read More## Quantitative Aptitude: Quadratic Equations Questions Set 73

x^2-4x+4=0y^2-9y+18=0 x>y x< y X≥Y x≤y X=Y or no relation Option B 1. x^2-4x+4=0 x^2-2x-2x+4=0 x=2,22. y^2-9y+18=0 y^2-6y-3y+18=0y=6,3 x^2-x-12=0y^2-y-6=0 x>y x< y X≥Y X≤Y X=Y or no relation Option E 1. x^2-x-12=0x^2-4x+3x-12=0x=4,-32. y^2-y-6=0y^2-3y+2y-6=0y=3,-2 x^2+7x+10=0y^2+12y=35=0 x>y x< y X≥Y X≤Y X=Y or no relation Option C 1. x^+7x+10=0x^2+5x+2x+10=0x= -5,-22. y^2+12y+35=0y^2+7y+5y+35=0y= -7,-5 25x^2=625y^2-10y+25=0 x>y x< y X≥Y X≤Y X=Y...

Read More## English: Phrase Replacement/ Sentence Improvement Set 111

Directions(1-10): In the given question, a part of the sentence is given in brackets. Below the sentence, alternatives to the bracketed part are given as (A), (B), (C) and (D), which may help improve the sentence. Choose the correct alternative out of the given five options. In case the given sentence is correct, your answer will be option (E), i.e.,…

Read More## Quantitative Aptitude: Mensuration Questions Set 14

The perimeter of an equilateral triangle is equal to the perimeter of a square whose diagonal is 9√2 cm. Find out the area of the equilateral triangle ? 48√3 60√3 30√3 36√3 20√3 Option D side of square=9√2/√2=9let the side of equilateral triangle be x cm.3x=4*9 x=12 area of equilateral triangle= √3/4*12*12=36√3 If ratio of height and radius of…

Read More## Mixed English Questions for upcoming Exam — Set 406

Directions(1-2): In the following question, a word is given along with its usage in sentences given in the options. Choose the option in which the use of the given word is contextually and grammatically correct. Suggest The Minister established a commission to suggests improvements in the educational system. Economic indicators suggest that a recovery is on the way. The consultant…

Read More## Quantitative Aptitude: Time, Speed and Distance Set 23

A train running at the speed of 90 kmph passes a pole in 10 sec, in how much time the train can cross 350m long another train B, which running opposite direction with the speed of 180 kmph. 10 sec 8 sec 12 sec 15 sec 20 sec Option B length of the train=90*5/18*10=250 mspeed of train=90*5/18=25 m/secspeed of another…

Read More