Quantitative Aptitude: Data Interpretation Questions Set – Set 88

Directions(1-5): Study the following line graph carefully in which x-axis represents the year and the y-axis represents the number of students(in hundreds) in three specific colleges A , B and C.

  1. What was the average number of students in college C ?
    1000
    4500
    2000
    3000
    2200
    Option C
    Required Numbers = (1000+500+2000+1500+2000+5000)/6
    = 12000/6 = 2000

     

  2. What was the ratio between the total number of students in college B in the year 2005 and 2007 together and in college A in the year 2006 and 2010 ?
    4:9
    7:12
    11:13
    5:17
    10:19
    Option B
    Ratio = (2000+1500) : (1500+4500) =35:60 = 7:12

     

  3. What was the average number of students in school B in the year 2006, 2008 and 2010?
    4000
    5000
    6000
    2000
    3000
    Option E
    Required average numbers of students = 9000/3
    = 3000

     

  4. What was the difference between the total number of students in the year 2007 and 2009 in all the three colleges ?
    3500
    1250
    1560
    4500
    1000
    Option A
    Total number of students from all the three colleges in the year 2007
    = (2000+2000+1500) = 5500
    Total number of students from all the three colleges in the year 2009 = (2000+3000+5000) = 9000
    Required difference = 9000 – 5500 = 3500

     

  5. Total number of students in the college C in the year 2005 and 2009 was approximately what percentage of the total number of students in college A in the year 2008 and 2010 ?
    43%
    20%
    40%
    50%
    33%
    Option A
    Number of students in college C in the year 2005 and 2009 = (2000+1000) = 3000
    Number of students in college A in the year 2008 and 2010 = (2500 + 4500 ) = 7000
    Percentage = ( 3000*100)/7000 = 43%(approx.)

     

Directions(6-10): Study the table carefully and answer the following questions.

  1. What is the cost of flooring and cost of fencing of parallelogram?
    Rs.10550 and Rs.800
    Rs.950 and Rs.500
    Rs.10,500 and Rs.1400
    Rs.11,500 and Rs.600
    Rs.12,200 and Rs.650
    Option C
    Area of parallelogram = (20*15) = 300 sq. m
    Cost of flooring = 300 * 35 = Rs. 10,500
    Perimeter of parallelogram = 2(20+15) = 70 m
    Cost of fencing = 70*20 = Rs.1400

     

  2. What is the ratio of the area between circle and triangle ?
    77:24
    61:30
    70:53
    55:37
    None of these
    Option A
    Area of circle = pi*r*r = 154 sq.m
    Area of triangle = ½*8*12 = 48 sq. m
    Ratio = 154:48 = 77 : 24

     

  3. What is the cost of flooring rectangle ?
    Rs.5,460
    Rs.6,650
    Rs.4,230
    Rs.4,440
    Rs.6,656
    Option E
    Area of rectangle = 208 sq.m
    Cost of flooring = 208 * 32 = Rs.6,656

     

  4. Find the difference between the cost of fencing of circle and cost of flooring of square?
    Rs.52,250
    Rs.61,490
    Rs.78,680
    Rs.63,550
    Rs.42,000
    Option C
    Difference = cost of flooring of square – cost of fencing of circle
    Required difference = (40*40*50)- (44*30) = 80,000 – 1320
    = Rs.78,680

     

  5. By what percent the area of rectangle is more or less than the area of parallelogram?
    22.25%
    30.67%
    20.12%
    15.6%
    33.33%
    Option B
    Required % = (300-208)*100/300 = 30.67%

     


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