- Two dices are rolled down simultaneously, then find the probability of getting sum of results on both dices more than 8.
2/154/191/85/183/20Option D

possible cases=(3,6), (4,5), (4,6), (5,4), (5,5)

required probability=10/36=5/18 - A bag contains 6 blue balls and 8 pink balls. If a ball is drawn randomly from it, then find the probability of getting either pink ball or blue ball.
4511/42/5Option C

required probability=6/14+8/14=14/14=1 - In a box there are 4 red balls and 3 blue balls. If two balls are drawn at random, then find the probability of that none is blue.
2/52/75/84/154/18Option B

required probability=(4C2)/(7C2)

=4*3/7*6=2/7 - A basket contains 5 white balls , 4 red balls, 2 blue balls and 3 yellow balls. If four balls are picked at randomly. What is the probability that 2 are blue and 2 are red ?
5/10028/96812/10058/9506/1001Option E

required=(2C2)*(4C2)

=(2*1/2*1)*(4*3/2*1)=1*6

total=14C4=14*13*12*11/4*3*2*1

=7*13*11

probability=1*6/7*13*11=6/1001 - When two dices are thrown simultaneously, then find the probability that sum is a prime number which is less than 8 ?
12/3820/3620/3513/3615/48Option D

prime numbers=2,3,5,7

possibility of 2=(1,1)

possibility of 3=(1,2), (2,1)

possibility of 5=(1,4), (4,1), (3,2), (2,3)

possibility of 7=(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)

required=1+2+4+6=13

total=6^2=36

probability=13/36 - When two coins are tossed simultaneously, then find the probability of getting at least one head.
4/53/48/97/122/15Option B

probability=3/2^2=3/4 - If from a pack of 52 cards, 1 cards is drawn at randomly, find the probability of the card is an ace.
2/151/134/152/258/18Option B

required=4C1=4

total=52C1

probability=4/52=1/13 - Two cards are drawn at random from a pack of 52 cards. What is the probability that both are the queen cards ?
2/2214/2255/2281/2218/125Option D

required=4C2=4*3/2*1=12/2=6

total=52C2=52*51/2

probability=6/26*51=1/221 - In how many ways letters of the word ‘LAPTOP’ be arranged such that consonants always come together ?
5075407280Option D

required ways=3!*4!/2!=72 ways - A bag contains 4 red balls and 8 balls. If two balls are taken out from the bag, then find probability of at least one ball being red ?
40/8548/6555/6435/6640/86Option D

favorable cases=(1 blue and 1 red) or ( 2 red)

probability=(4C1)*(8C1)/(12C2)+(4C2)/(12C2)

=(4*8/12*11/2*1)+(4*3/2*1/12*11)

=(4*8/11*6)+(2*3/12*11)=16/33+1/22

=32+3/66=35/66