- Two dice are rolled randomly. Find the probability to get sum is 10. 2/5142/91/125/8Option D

Required = (6 , 4 ) , (4 , 6) , ( 5, 5) = 3

total = 6 * 6 = 36

probability = 3/36 = 1/12 - Two dices are rolled out together, then what is the probability of getting a number of one dice greater than the number of other dice ? 2/31/63/81/85/6Option E

Non-favorable events = (1 , 1) , (2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) , (6,6) = 6

total = 6 * 6 = 36

probability of non-favorable events = 6/36 = 1/6

probability of favorable events = 1 – 1/6 = 5/6 - If 2 cards is drawn at randomly from 52 cards, then find the probability of getting both are red cards. 13/2826/10528/10825/102none of theseOption D

Required = 26C2 = 26 * 25/2 = 13 * 25

total = 52C2 = 52 * 51 / 2 = 26 * 51

probability = 13 * 25 / 26 * 51 = 25 /102 - In how many ways, we can arrange the letters of the word ‘LIGHT’ ? 8428140160120Option E

Ways = 5! = 5 * 4 * 3 * 2 * 1 = 120 - In how many different ways, we can arrange the letters of the word ‘MOUSE’ , so that the middle position is always occupied by ‘S’ ? 2524484268Option B

Ways = 4! = 4 * 3 * 2 * 1 = 24 - How many ways 6 books can be selected from 14 different books , if two particular books are always selected ? 495480231384520Option A

Available objects = 14 – 2 = 12

Ways = 12C4 = 12 * 11 * 10 * 9/4 * 3 * 2 * 1 = 495 - A bag contains 2 white balls, 3 pink balls and 2 black balls. 2 balls are drawn randomly. What is the probability that there is no black balls ? 8/2110/211/83/56/11Option B

Required = 5C2 = 5*4/2 = 10

total = 7C2 = 7 * 6 / 2 = 21

probability = 10/21 - When two coins are tossed simultaneously, then find the probability of getting at least one tail. 533/41/42/5Option C

Required = ( 1 head , 1 tail ) , ( 2 tails) = (2C1) + (2C2) = 2 + 1 = 3

total = 2^2 = 4

probability = 3/4 - A bag contains 4 red balls, 2 blue balls and 2 green balls . If two balls are drawn randomly from the bag , then find the probability of getting both balls of different color. 2/75/85/748Option C

probability = 4C1 * 2C1 / 8C2 + 4C1 * 2C1 / 8C2 + 2C1 * 2C1 / 8C2

(4 * 2 * 2)/ 8 * 7 + (4 * 2 * 2)/ 8 * 7 + (2 * 2 * 2) / 8 * 7 = 2/7 + 2/7 + 1/7 = 5/7 - A group of students sitting around a rectangular table, find probability of 2 specified students sitting together. 3/82/78/73/86/11Option B

Favorable cases = 6! * 2!

total cases = 7!

probability = 6! * 2! /7! = 2/7