Quant Questions Bank PO

Quantitative Aptitude: Quadratic Equations Set 26

35 Comments / Banking Quiz, Quantitative Aptitude / By

 

Quadratic Equations Practice Sets for IBPS PO, NICL, NIACL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.

Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

  1. I. 3x2 – 8x – 28 = 0,
    II. 3y2 – 44y + 140 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option D
    Solution: 
    3x2 – 8x – 28 = 0
    3x2 – + 6x – 14x – 28 = 0
    Gives x = -2, 14/3
    3y2 – 44y + 140 = 0
    3y2 – 30y -14y + 140 = 0
    Gives y = 14/3, 10
  2. I. 2x2 – 27x + 81 = 0,
    II. 3y2 – 50y + 168 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option E
    Solution: 
    2x2 – 27x + 81 = 0
    2x2 – 18x – 9x + 81 = 0
    Gives x = 9/2, 9
    3y2 – 50y + 168 = 0
    3y2 – 36y – 14y + 168 = 0
    Gives y = 14/3, 12
  3. I. 2x2 – 3x – 54 = 0,
    II. 3y2 – 32y + 80 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option E
    Solution: 
    2x2 – 3x – 54 = 0
    2x2 – 12x + 9x – 54 = 0
    Gives x = -9/2, 6
    3y2 – 32y + 80 = 0
    3y2 – 12y – 20y + 80 = 0
    Gives y = 4, 20/3
  4. I. 3x2 – 14x – 24 = 0,
    II. 3y2 + 32y + 64 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option A
    Solution: 
    3x2 – 14x – 24 = 0
    3x2 – 18x + 4x – 24 = 0
    Gives x = -4/3, 6
    3y2 + 32y + 64 = 0
    3y2 + 24y + 8y + 64 = 0
    Gives y= -8, -8/3
  5. I. 4x2 + x – 18 = 0,
    II. 4y2 – 11y – 45 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option E
    Solution: 
    4x2 + x – 18 = 0
    4x2 – 8x + 9x – 18 = 0
    Gives x = -9/4, 2
    4y2 – 11y – 45 = 0
    4y2 – 20y + 9y – 45 = 0
    Gives y= -9/4, 5
  6. I. 3x2 – 26x + 48 = 0,
    II. 3y2 + 4y – 32 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option C
    Solution: 
    3x2 – 26x + 48 = 0
    3x2 – 18x – 8x + 48 = 0
    Gives x = 8/3, 6
    3y2 – 25y + 52 = 0
    3y2 – 12y – 13y + 52 = 0
    Gives y = -4, 8/3
  7. I. 4x2 + 39x + 77 = 0,
    II. 4y2 – y – 33 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option D
    Solution: 
    4x2 + 39x + 77 = 0
    4x2 + 28x  + 11x + 77 = 0
    Gives x = -7, -11/4
    4y2 – y – 33 = 0
    4y2 – 12y + 11y – 33 = 0
    Gives y = -11/4, 3
  8. I. 3x2 + 7x – 40 = 0,
    II. 3y2 – 38y + 112 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option B
    Solution: 
    3x2 + 7x – 40 = 0
    3x2 + 15x – 8x – 40 = 0
    Gives x = -5, 8/3
    3y2 – 38y + 112 = 0
    3y2 – 24y – 14y + 112 = 0
    Gives y = 14/3, 8
  9. I. x2 = 1849,
    II. y = √2116
    A) x > y
    B) x < y
    C) x ≥ y
    D) x ≤ y
    E) x = y or relationship cannot be determined
    View Answer
    Option B
    Solution:
    x2 = 1849
    x = -43, 43
    y = √2116
    y = 46 (root is always positive)
    -43……….43………….46
    If
    a2 = 1849, then a = -43, 43
    and if a = √1849, then a = 43
  10. I. x2 – 565 = 1284,
    II. y = √1521
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option E
    Solution:
    x2 = 1849
    x = -43, 43
    y = √1521
    y = 39
    -43……….39………..43

Click here for more Quadratic Equations Practice Sets

 

 

35 thoughts on “Quantitative Aptitude: Quadratic Equations Set 26”

        1. Shubhra

          x = -9/4, 2
          y = -9/4, 5

          when u put on number line

          -9/4……….2………..5

          Now when x = 2 and y = -9/4
          x > y.

          and when x = 2 and y = 5
          x < y

          So are you able to find relationship ?

  3. Ravi Upadhyay

    thnxx… ab to sari quiz dunga…. sb section ki quiz dega re tumhara faizall…. wrna faizal berojgaaar reh jayga is br bhi…

      1. Prabakar

        Mam..Im not much fortify in quantz…Well i preparing only,,Simplication,,quadratic,di,numberseries,,,PRofit and loss,partnership,si anda ci…..The rest others is not coming to me..whatever i tried hard..is it enough /? mam..?

        1. Shubhra

          for prelims, they are sufficient
          but not for mains
          because now DI is also asked from word problems

          u need to do other chapters as well, do time and work, boats and streams

          boats and streams is very easy

  6. "Mission 2017" 'sandeep'

    mam ek request h apse timer ke sath quiz de toh jada bettr ho jayege fir hope aap ispe thoda soche thnx mam:))

      1. karthik

        plz check once 2nd question mam

        x = 9/2, 9 = (4.5, 9)
        y = 14/3, 12 =(4.66, 12)

        so here y>x, but answer “e”
        plz…

  14. excursion bateau marinique

    I believe that avoiding refined foods would be the first step to be able to lose weight. They will taste very good, but prepared foods include very little vitamins and minerals, making you take more simply to have enough power to get with the day. Should you be constantly feeding on these foods, transitioning to whole grain products and other complex carbohydrates will let you have more energy while eating less. Interesting blog post.

Comments are closed.