- Sivam invested some money in a scheme at the rate of 20% for 3 years. If he withdraws 40% of total amount and left remaining amount is rs.2304. What is total money which he invested at earlier.
25002400350032004200Option B

Let principal = 100x

SI = 100x * 20/100 * 3 = 60x

Total amount = 100x + 60x = 160x

remaining = 160x * 60/100 = 96x

96x = 2304

x = 24

He invested = 100x = 2400 - Simple interest on rs.2750 for 2 years at certain rate of interest is rs.120 more than simple interest on rs.1500 for 3 years at same rate of interest. What is the rate of interest ?
12%14%15%13%18%Option A

Let rate of interest = R%

(2750*R/100*2) – (1500*R/100*3) = 120

55 R – 45R = 120

10 R = 120

R = 12% - Simple interest on a certain sum of money at rate of 20% for 2 years is two times of the compound interest on rs.5000 for 2 years at the rate of 14% per annum. What is the sum on simple interest ?
8340800012000749014000Option D

Rate of compound interest after 2 years = 14 + 14 + 14 * 14/100 = 29.96%

compound interest = 5000 * 29.96/100 = 1498

simple interest = 1498 * 2 = 2996

Let principal on simple interest = x

2996 = x * 20/100 * 2

x = 7490 - A man invested an amount of rs.4800 for 3 years a certain rate of simple interest become rs.7248. If the rate of interest increases by 3%, what amount will rs.5000 becomes in 2 years ?
72006320845082406830Option A

Simple interest = 7248 – 4800 = 2448

2448 = 4800 * 3 * 12/100

R = 17%

Now rate of interest = 17 + 3 = 20%

Amount = 5000 * 120/100 * 120/100 = 7200 - In how many years a sum will become four times itself at the rate of 12% per annum in simple interest ?
12 years24 years25 years26 years20 yearsOption C

Let the principal = x

Amount = 4x

Simple interest = 4x – x = 3x

3x = x * 12/100 * T

T = 25 years. - A deposited rs.6800 in a bank at 8% per annum for 5 years simple interest. B deposited rs.8000 at 20% per annum for 2 years in compound interest. What is difference between compound interest and simple interest.
850240836800840Option D

Simple interest = 6800 * 8/100 * 5 = 2720

By using successive,

20 + 20 + 20 * 20/100 = 44%

compound interest = 8000 * 44/100 = 3520

Difference = 3520 – 2720 = 800 - A certain sum in simple interest becomes rs.6600 in 4 years and becomes rs.7400 in 6 years, then find the rate of interest.
4%8%20%14%18%Option B

Simple interest for 2 years = 7400 – 6600 = 800

simple interest for 1 year = 400

simple interest for 4 years = 4 * 400 = 1600

sum = 6600 – 1600 = 5000

1600 = 5000 * R/100 * 4

R = 8% - The difference between compound and simple interests on a sum for 2 years at 15% per annum is 450. Find the sum.
1200025000200003800035000Option C

CI – SI = PR^2/100^2

450 = P * 225/10000

P = 20000 - The population of a town increased by 25% p.a. If the present population is 50000. Find the population of town 3 years ago.
2560024480325402400030340Option A

Let the population of town 3 year ago = x

x * 5/4 * 5/4 * 5/4 = 50000

x = 50000 * 64/125

x = 25600 - What is difference between compound interest and simple interest for 2 years on a principal of rs.4000 at the annual rate of 25% ?
340125250350300Option C

Simple interest = 4000 * 25/100 * 2 = 2000

Rate of compound interest after 2 years = 25 + 25 + 25 * 25/100 = 56.25%

compound interest = 4000 * 56.25/100 = 2250

difference = 2250 – 2000 = 250