- A can do a piece of work in 25 days. If B is 20% more efficient than A, then in how many days three – fifth of the work is completed by A and B working together ?
2 3/4 days8 1/5 days4 days6 9/11 days6 11/14 daysOption D

Let efficiency A = 5

efficiency of B = 5 *6 /5 = 6

total work = 25 * 5 = 125

3/5 of the work = 3/5*125 = 75

time = 75/5+6 = 6 9/11days - A can do 1/5 of the work in 5 days and B can do 1/4 of the work in 6 days. If they earned total rs.4900, then how much money will A get ?
24004800250032001450Option A

A can do total work = 5 * 5 = 25 days

B can do total work = 4 * 6 = 24 days

LCM of 25 and 24 = 600

Total work = 600

efficiency of A = 600/25 = 24

efficiency of B = 600/24 = 25

A get = 4900 * 24/49 = 2400 - P, Q and R can do a piece of work in 20 days, 30 days and 40 days respectively. If they started the work together but after 6 days P left the work and remaining work done by Q and R together, they in how many days total work will be completed ?
14 days12 days20 days16 days6 daysOption B

LCM of 20, 30 and 40 = 120

total work = 120

efficiency of P = 120/20 = 6

efficiency of Q = 120/30 = 4

efficiency of R = 120/40 = 3

they completed the work together in 6 days = (6 + 4 + 3)6 = 78

remaining work = 120 – 78 = 42

time taken by Q and R together to complete remaining work = 42/4+3 = 6 days

total time = 6 + 6 = 12 days - A group of 25 men is supposed to do a work in 30 days. After 15 days 5 more men is employed and the work is employed in 1 day before the scheduled time. If 5 more men were not employed, then in how many days it have been delayed ?
23.21.92.51.8Option E

work completed by 25 men in 15 days = 25 * 15 = 375

now total men = 25 + 5 = 30

work completed before 1 day

total work = 375 + 30 * 14 = 795

If 5 men is not employed,

time taken by 25 men to complete work = 795/25 = 31.8

work will be delayed = 31.8 – 30 = 1.8 day - A and B can do a piece of work in 18 days and 24 days respectively. If they work in alternative day starting with A, then in how many days the work is completed ?
22 2/520 4/820 1/23/43Option C

LCM of 18 and 24 = 72

Total work = 72

efficiency of A = 72/18 = 4

efficiency of B = 72/24 = 3

A and B work in alternate day.

A and B completed work in 2 days = 4 + 3 = 7

10(2 day) = 10(7 work)

20 day = 70 work

A completed 4 work in 1 day so, 2 work completed in 1/2 day.

total time = 20 + 1/2 = 20 1/2 day. - A and B can do a piece of work in 25 days and 30 days respectively and they start working together for 10 days. After 10 days A left the work and C joins and the remaining work in completed by B and C together in 5 days. Find the days in which C can do the work ?
50 days40 days46 days32 days58 daysOption A

LCM of 25 and 30 = 150

total work = 150

efficiency A = 150/25 = 6

efficiency of B = 150/30 = 5

A and B completed work in 10 days = (6 + 5) 10 = 110

remaining of work = 150 – 110 = 40

B and C completed in 5 days = 40/5 = 8

efficiency of C = 8 – 5 = 3

C alone completed total work = 150/3 = 50 days. - A and B can do a piece of work in 20 days and 30 days respectively. They start working together after some days A left the work and remaining work completed by B in 15 days. Find in how many days A left the work ?
2064128Option B

LCM of 20 and 30 = 60

efficiency of A = 60/20 = 3

efficiency of B = 60/30 = 2

B alone work for 15 days = 15 * 2 = 30 work

Time taken to do remaining by A and B together = 30/3+2 = 6 days

After 6 days A left the work. - A can do 80% of a work in 20 days. A and B together can do the remaining work in 4 days. Then in how many days B alone would take to do the total work ?
1201305040100Option E

A work done = 20*5/4 = 25 days

Remaining work = 1/5

time taken by A and B to do total work = 5 * 4 = 20 days

LCM of 25 and 20 = 100

efficiency of A = 100/25 = 4

efficiency of A and B = 100/20 = 5

efficiency of B = 5 – 4 = 1

Time taken by B to do total work = 100/1 = 100 days - P and Q can do a piece of work in 20 days and 40 days respectively. They start the work but Q leaves the work 8 days before the completion. Find how many days is required to complete the work ?
48121420Option B

LCM of 20 days and 40 days = 40

Total work = 40

efficiency of P = 40/20 = 2

efficiency of Q = 40/40 = 1

work done by P in 8 days = 8 * 2 = 16 days

Remaining work = 40 – 16 = 24 work

Time taken by P and Q remaining work = 24/2+1 = 8 days - A and B undertake to complete a work for rs.3000. A and B can do a piece of work on 12 days and 15 days respectively and with the help of C they complete the work in 4 days. Then how much money C get ?
12001320184015401450Option A

LCM of 12, 15 = 60

Total work = 60

efficiency of A = 60/12 = 5

efficiency of B = 60/15 = 4

total efficiency of A, B and C = 60/4 = 15

efficiency of C = 15 -(5 + 4) = 6

share of C = 3000 * 6/15 = 1200