- A, B and C alone can do a work in 8 days , 12 days and 6 days respectively. Find how many days they take together to complete work ?
6 days8 days2 2/3 days4 days3 daysOption C

LCM of 8 , 12 and 6 = 24

total work = 24

efficiency of A = 24/8 = 3

efficiency of B = 24/12 = 2

efficiency of C = 24/6 = 4

time taken = 24/9 = 2 2/3 days - P and Q alone can do a work in 30 days and 20 days respectively. P works for 15 days and left the work, remaining work done by B. Find how many days required to complete the remaining work ?
10 days8 days20 days18 days16 daysOption A

LCM of 30 and 20 = 60

total work = 60

efficiency of P = 60/30 = 2

efficiency of Q = 60/20 = 3

P completed work in 15 days = 15 * 2 = 30

time taken by Q to complete remaining work = 60 – 30 /3 = 10 days - A can complete 40% of work in 8 hours and while B alone can do the same work in 24 hours. Find the time taken by A and B together to complete the 60% of the work ?
5 2/3 days8 3/5 days4 days6 6/11 days8 daysOption D

A alone can do all work = 8/40 * 100 = 20 days

LCM of 20 and 24 = 120

efficiency of A = 120/20 = 6

efficiency of B = 120/24 = 5

time taken by A and B together to complete 60% of the work = 120/11 * 60/100 = 6 6/11 days - A and B alone can do a piece of work in 12 hours and 15 hours respectively. If they do the work alternatively for 1 hours each starting with A, then find how many hours will the work be completed ?
5 hours3 hours8 1/5 hours12 1/4 hours13 1/4 hoursOption E

LCM of 12 and 15 = 60

total work = 60

efficiency of A = 60/12 = 5

efficiency of B = 60/15 = 4

work completed in 2 hours = 5 + 4 = 9 works

(2 * 6) hours = (9 * 6) work

12 hours = 54 works

A works in another hours = 5 work

remaining 1 work completed by B = 14 hours

total time = 12 + 1 + 1/4 = 13 1/4 hours - A, B and C alone can do a piece of work in 3 days. If A alone can do in 6 days and C alone can do it in 18 days, how long will B alone take to complete the work ?
8 days9 days18 days6 days4 daysOption B

LCM of 3, 6 and 18 = 18

total work = 18

efficiency of A, B and C = 18/3 = 6

efficiency of A = 18/6 = 3

efficiency of C = 18/18 = 1

efficiency of B = 6 – ( 3 + 1 ) = 2

B alone can do the work = 18/2 = 9 days - P and Q undertook to do a piece of work for rs.3500. P alone can do it in 12 days and Q alone in 20 days. If they finished the work with the help of R in 6 days. What is share of R ?
800700850650725Option B

LCM of 12, 20 and 6 = 60

efficiency of P = 60/12 = 5

efficiency of Q = 60/20 = 3

efficiency of P, Q and R = 60/6 = 10

efficiency of R = 10 – ( 5 + 3 ) = 2

share of R = 3500 * 2 / 10 = 700 - Rita and Gita can do a piece of work individually in 40 days and 60 days respectively. If they work on alternate days starting with Gita, then in how many days will the work get finished ?
28 days24 days17 days48 days46 daysOption D

LCM of 40 and 60 = 120

efficiency of Rita = 120/40 = 3

efficiency of Gita = 120/60 = 2

starting with Gita work completed in 2 days = 5

time required to complete total work = 24 * 2 = 48 days - A and B can do a work in 12 days. B and C can do the same work in 20 days. A and C can also do the same work in 30 days. If they all work together in how many days will they complete the work ?
10 days14 days12 days13 days15 daysOption C

LCM of 12, 20 and 30 = 120

efficiency of A and B = 120/12 = 10

efficiency of B and C = 120/20 = 6

efficiency of A and C = 120/30 = 4

A + B + B + C + A + C = 10 + 6 + 4 = 20

2(A + B + C) = 20

A + B + C = 10

time 120/10 = 12 days - 8 men or 12 women can finish a work in 25 days. How many days will 6 men ad 11 women can finish the same work ?
15 days14 days28 days30 days32 daysOption A

8 men = 12 women

men/women = 12/8 = 3/2

total work = 8 * 3 * 25 = 600

time required = 600 /(6 * 3 + 11 * 2) = 600/40 = 15 days - A, B and C can complete a job in 9 days, 10 days and 15 days respectively. A, B and C start the work together and after 2 days B and C leave the work. Find how many days taken by A to complete the remaining work ?
6 days18 days14 days4 days8 daysOption D

LCM of 9, 10 and 15 = 90

efficiency of A = 90/9 = 10

efficiency of B = 90/10 = 9

efficiency of C = 90/15 = 6

A, B and C complete work in 2 days = 2(10 + 9 + 6) = 50

remaining work = 90 – 50 = 40

time taken by A to complete remaining work = 40/10 = 4 days