Quantitative Aptitude: Data Interpretation Questions for IBPS PO Prelims Set 68

Directions (1-5): A company has 4 offices – P, Q, R, and S in different cities. Each office has 5 departments – A, B, C, D, and E. The company has decided to keep same % of employees in each of the 5 departments in each office. (In each office number of total number of employees vary)

1. In office P, there are total 6300 employees, what is the total number of employees in its A and D departments?A) 2691
   B) 2987
   C) 2365
   D) 2898
   E) 2765
   
   View Answer

     Option D
   Solution:
   Total number of employees in its A and D departments = (26+20)/100 * 6300 = 2898
2. In office P, there are total 6500 employees. Office Q has 20% more employees than in office P. What is the difference between the employees in E department of office Q and the employees in B departments of office P?A) 672
   B) 724
   C) 546
   D) 598
   E) 627
   
   View Answer

     Option  C
   Solution:
   P = 6500, Q = 120/100 * 6500 = 7800
   in E in Q = 22/100 * 7800 = 1716
   in B in P = 18/100 * 6500 = 1170
   Required difference = 1716 – 1170 = 546
3. Total number of employees in offices P and R is 13,600. The difference between the employees in departments E and D in offices R and P respectively is 304. Find the total number of employees in departments D and E in offices P and R respectively.
   A) 3265
   B) 2864
   C) 2756
   D) 2891
   E) 3167
   
   View Answer

     Option B
   Solution:
   22/100 * x – 20/100 * (13600 – x) = 304
   Solve, x = 7200
   So employees in office R = 7200, in P = 13600-7200 = 6400
   So total number of employees in departments E and D in offices R and P = 22/100 * 7200 + 20/100 * 6400 = 2864
4. In office Q, total number of employees in departments A and B is 2860. Also in office S, total number of employees in departments C and E is 2664. Find the total number of employees in offices Q and S.
   A) 13,900
   B) 15,600
   C) 14,300
   D) 13,400
   E) 15,200
   
   View Answer

     Option  A
   Solution:
   In Q = 2860 * 100/(26+18) = 6500
   In S = 2664 * 100/(14+22) = 7400
   So required total = 6500 + 7400 = 13,900
   
5. Total number of employees in departments E, B, and C in offices P, R and S respectively is 2924. Also total number of employees in offices P and S is 10600. If total number of employees in departments P, R and S is 16200, find the number of employees in department R.
   A) 5800
   B) 5200
   C) 4900
   D) 4500
   E) 5600
   
   View Answer

     Option  E
   Solution:
   Employees in P = x, in S = y
   So x + y = 10600
   22/100 * x + 18/100 (16200 – x – y) + 14/100 * y = 2924
   4x/100 – 4y/100 + 2916 = 2924
   Solve, x – y = 200
   x + y = 10600
   Solve, x = 5400, y = 5200
   So in R = (16200 – 5400 – 5200) = 5600
   

Directions (6-10): Study the following bar graph and answer the questions that follow:
The following bar graph shows the percentage of students passing in various standards in a school. Maximum marks for each subject of every class is same.

6. If the number of boys and girls passing in standard 5th are same, then what is the ratio between the number of boys and number of girls in standard 5th?
   A) 3 : 7
   B) 3 : 4
   C) 2 : 5
   D) 4 : 7
   E) 1 : 5
   
   View Answer

     Option B
   Solution:
   In 5th standard, let no. of boys = x, girls = y
   Number of boys passing = 0.8x
   Number of girls passing = 0.6y
   0.8x = 0.6y
   x/y = 3/4
7. In 7th standard, 44% of the total students got passed. If total number of boys in 7th standard is 200, then what is the total number of girls in 7th standard?
   A) 50
   B) 78
   C) 67
   D) 45
   E) 58
   
   View Answer

     Option  A
   Solution:
   Let the total no. of girls in 7th standard = xTotal no. of boys passed = 200*0.4 = 80
   Total no. of girls passed = x*0.6 = 0.6x
   So, passed % of students = (80+0.6x)/(200+x)
   Now, 44/100 = (80+0.6x)/(200+x)
   Solve, x = 50
   
8. If the total number of boys and girls in each standard is 150 and 120 respectively, then what is overall pass percentage of the school?
   A) 75%
   B) 81%
   C) 73%
   D) 69%
   E) 63%
   
   View Answer

     Option D
   Solution:
   Total number of students = 6 * (150+120) = 1620
   So overall pass % = [150(0.8+0.8+0.4+0.9+0.7+0.7) + 120(0.6+0.7+0.6+0.6+0.8+0.6)]/1620 * 100 = (645+468)/1620 * 100 = 69%
   
9. If the ratio between the number of boys and the number of girls in standard 9th is 4:1, then what is the ratio between number of boys passed and number of girls passed in standard 9th?
   A) 8 : 3
   B) 8 : 5
   C) 7 : 2
   D) 9 : 4
   E) 7 : 1
   
   View Answer

     Option  C
   Solution:
   Let there are 400 boys and 100 girls in 9th
   Number of boys passed = 0.7*400 = 280
   Number of girls passed = 0.8*100 = 80
   Required ratio = 280 : 80 = 7 : 2
   
10. Assuming data in question 8, if the over-all average marks of boys is 50 and that of girls is 60, then what is average marks of the students in the school?
    A) 49.13%
    B) 30.66%
    C) 52.17%
    D) 42.02%
    E) 54.44%
    
    View Answer

      Option  E
    Solution:
    Required average marks = (50*150 + 60*120)/(150+120) = 14700/270 = 54.44%
    

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