**Directions(1-5): **What approximate value will come in place of question mark ‘?’ in the following questions.

- 25.6% of 250 + √? = 119
21102255302529953030Option C

250 × 25.6 100 + √? = 119

⇒ 64 + √? = 119

⇒ √? = 119 − 64 = 55

⇒ ? = 55 × 55 = 3025 - [30% 𝑜𝑓 {(80% 𝑜𝑓 850) ÷ 34}] = ?
86954Option B

? = [ 30/100 × {( 80/100 × 850) ÷ 34}]

= [ 30/100 × {680 ÷ 34}] = [ 30/100 × 20] = 6 - 65% 𝑜𝑓 240+ ?% 𝑜𝑓 150 = 210
5261445836Option E

65/100 𝑜𝑓 240 + ?/ 100 𝑜𝑓 150 = 210

⇒ 156 + 1.5 ×? = 210

=> ? = [210−156]/1.5 = 36 - 1425 + 8560 + 1680 ÷ 200 = ?
77888595911088009993Option E

? = 1425 + 8560 + 1680 ÷ 200

= 1425 + 8560 + 1680/200

= 9985 + 8.4 = 9993.4 == 9993 - ? % of 800 = 293 – 22% of 750
1218161410Option C

[800 ×?]/ 100 = 293 − 750 × 22/100

=> 8 × ? = 293 − 165 = 128

=> ? = 128/8 = 16 - The retail price of a water geyser is Rs. 1265. If the manufacturer gains 10%, the wholesale dealer gains 15% and the retailer gains 25%, then the cost of the product is:
Rs. 800Rs. 900Rs. 600Rs. 400Rs. 500Option A

Cost price = 100/110 × 100/115 × 100/125 × 1265

= Rs. 800 - A pipe can fill a cistern in 6 hrs. Due to a leak in its bottom, it is filled in 7 hrs. When the cistern is full, in how much time will it be emptied by the leak?
47 hrs.40 hrs.50 hrs.42 hrs.38 hrs.Option D

In one hour 1/ 6 – 1/ 7

= 1/ 42 of the cistern is empty.

The whole cistern will be emptied in 42 hrs. - Ram travels a certain distance at 3 km/h and reaches 15 minutes late. If he travels at 4 km/h, he reaches 15 minutes earlier. The distance he has to travel is:
6 km7 km8 km9 km4 kmOption A

Let D be the required distance

So, D/3 − D/4 = 15+15/60

D = 6 km - A sum is invested for 3 years at compound interest at 5%, 10% and 20% respectively. In three years, if the sum amounts to Rs. 16,632, then find the sum.
Rs.14,000Rs.16,000Rs.10,000Rs.12,000Rs.18,000Option D

Let, P be the sum.

16632 = P (1 + 5/ 100) (1 + 10 /100) (1 + 20/ 100) 16632

16632 = P × 21/20 × 11/10 × 6/5

P = Rs.12,000 - A father’s age is three times the sum of the ages of his two children, but 20 years hence his age will be equal to the sum of their ages. Then, the father’s age is:
10 years30 years50 years40 years20 yearsOption B

Let the father’s age be x years and age of his children be a and b years (𝑎 + 𝑏) = 𝑥/3

And (𝑎 + 𝑏) + 20 + 20 = 𝑥 + 20

=> 𝑥/3 + 20 = 𝑥

=> 𝑥 = 30 years