# Mixed Quantitative Aptitude Questions Set 134

Directions(1-5): What will be the value in place of question mark “?” in the following questions.

1. 0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
0.01731
0.03027
0.01235
0.03027
0.01626
Option D
0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
? = 0.0003 – 0.00003 + 0.03 = 0.03027

2. 17 × 25 – 240 +? ÷ 41 = 354
7266
8890
6929
6000
7254
Option C
17 × 25 – 240 +? ÷ 41 = 354
? /41 = 354 – 425 + 240
⇒ ? = 41 × 169
⇒ ? = 6929

3. 3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
100.5
112.6
105.5
124.8
120.5
Option D
3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
?/ 0.8 = 156
⇒ ? = 124.8

4. 1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
1.11
1.46
2.03
1.51
2.21
Option B
1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
? = 0.81 + 0.49 + 0.16 = 1.46

5. 39% of 450 + 51% of 340 – 40% of 255 =?
211.5
246.9
200.6
215.5
220.6
Option B
39% of 450 + 51% of 340 – 40% of 255 =?
? = 39/100 × 450 + 51/100 × 340 – 40/100 × 255
= 246.9

6. Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, then find the price of third variety per kg.
178.9
175.5
166.5
150.7
162.8
Option B
Let price of third variety was Rs. A per kg
Let respective amounts of these tea were x kg, x kg and 2x kg.
126x + 135x + 2Ax = 153 × 4x
⇒ 2A = 351
⇒ A = 175.5 rupee per kg

7. One fill pipe A is 3 times faster than second fill pipe B and takes 32 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
10
12
15
18
14
Option B

Let, pipe A takes x minutes to fill the cistern.
Then, pipe B takes 3x minutes to fill the cistern
3x – x = 32
⇒ x = 16 minutes
3x = 48 minutes
So, both pipes can fill the cistern in ( 48×16/48+16) minutes = 12 minutes

8. A vessel contains mixture of milk and water in which water concentration is 30%. If 20% water and 30% milk is taken out and replaced with equal quantity of water, then quantity of water increases by what percent of the initial quantity of water in the mixture.
50%
90%
70%
80%
60%
Option C
Let vessel contains 100 L .
So required % = 30/100 × 70/30 × 100 = 21/30 × 100 = 70%

9. The marked price of a radio is Rs 480. The shopkeeper allows a discount of 10% and still gains 8%. If no discount is allowed, find his gain percent.
25%
15%
13%
20%
10%
Option D
M. P. = Rs 480/-
Discount = 10%
S.P. = 90/100 × 480 = Rs 432
P% = 8%
C.P. = 100/108 × 432 = 400
If no discount is given then S.P. = M.P. i.e. S.P. = 480
P% = S. P. −C. P./C. P. × 100
= 480 – 400/400 × 100 = 80/400 × 100 = 20%

10. The ratio of income of A, B and C is 3 : 7 : 4 and the ratio of their expenditure is 4 : 3 : 5 respectively. If A saves Rs 300 out of Rs 2400, find the savings of C.
500
457
575
620
550
Option C
Salary of A = 3x = Rs 2400
Salary of B = 7x = Rs 5600
Salary of C = 4x = Rs 3200
Expenditure of A, B and C = 4y, 3y & 5y respectively.
Saving of A is 300
Expenditure = 4y = (2400 – 300) = 2100
𝑦 = 2100/4 = 525
Expenditure of B = 3y = 1575
Savings of B = 4025
Expenditure of C = 5y = 2625
Savings of C = 575