**Directions(1-5):** What will be the value in place of question mark “?” in the following questions.

- 0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
0.017310.030270.012350.030270.01626Option D

0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?

? = 0.0003 – 0.00003 + 0.03 = 0.03027 - 17 × 25 – 240 +? ÷ 41 = 354
72668890692960007254Option C

17 × 25 – 240 +? ÷ 41 = 354

? /41 = 354 – 425 + 240

⇒ ? = 41 × 169

⇒ ? = 6929 - 3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8

100.5112.6105.5124.8120.5Option D

3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8

?/ 0.8 = 156

⇒ ? = 124.8 - 1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
1.111.462.031.512.21Option B

1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?

? = 0.81 + 0.49 + 0.16 = 1.46 - 39% of 450 + 51% of 340 – 40% of 255 =?
211.5246.9200.6215.5220.6Option B

39% of 450 + 51% of 340 – 40% of 255 =?

? = 39/100 × 450 + 51/100 × 340 – 40/100 × 255

= 246.9 - Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, then find the price of third variety per kg.

178.9175.5166.5150.7162.8Option B

Let price of third variety was Rs. A per kg

Let respective amounts of these tea were x kg, x kg and 2x kg.

126x + 135x + 2Ax = 153 × 4x

⇒ 2A = 351

⇒ A = 175.5 rupee per kg - One fill pipe A is 3 times faster than second fill pipe B and takes 32 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
1012151814Option B
Let, pipe A takes x minutes to fill the cistern.

Then, pipe B takes 3x minutes to fill the cistern

3x – x = 32

⇒ x = 16 minutes

3x = 48 minutes

So, both pipes can fill the cistern in ( 48×16/48+16) minutes = 12 minutes - A vessel contains mixture of milk and water in which water concentration is 30%. If 20% water and 30% milk is taken out and replaced with equal quantity of water, then quantity of water increases by what percent of the initial quantity of water in the mixture.

50%90%70%80%60%Option C

Let vessel contains 100 L .

So required % = 30/100 × 70/30 × 100 = 21/30 × 100 = 70% - The marked price of a radio is Rs 480. The shopkeeper allows a discount of 10% and still gains 8%. If no discount is allowed, find his gain percent.
25%15%13%20%10%Option D

M. P. = Rs 480/-

Discount = 10%

S.P. = 90/100 × 480 = Rs 432

P% = 8%

C.P. = 100/108 × 432 = 400

If no discount is given then S.P. = M.P. i.e. S.P. = 480

P% = S. P. −C. P./C. P. × 100

= 480 – 400/400 × 100 = 80/400 × 100 = 20% - The ratio of income of A, B and C is 3 : 7 : 4 and the ratio of their expenditure is 4 : 3 : 5 respectively. If A saves Rs 300 out of Rs 2400, find the savings of C.
500457575620550Option C

Salary of A = 3x = Rs 2400

Salary of B = 7x = Rs 5600

Salary of C = 4x = Rs 3200

Expenditure of A, B and C = 4y, 3y & 5y respectively.

Saving of A is 300

Expenditure = 4y = (2400 – 300) = 2100

𝑦 = 2100/4 = 525

Expenditure of B = 3y = 1575

Savings of B = 4025

Expenditure of C = 5y = 2625

Savings of C = 575