**Directions(1-5):** Find the wrong term of the following series.

- 3, 4, 9, 28, 113, 565, 3397
9113565284Option C

*1+1

*2+1

*3+1

*4+1

*5+1

*6+1

566 in place of 565. - 4, 6, 12, 30, 60, 315, 1260
126063151260Option B

*1.5,*2,*2.5,*3,*3.5,*4

90 in place of 60. - 1, 730, 975, 1054, 1081, 1090, 1093
105473010811090975Option E
- 9.2, 10.6, 7.6, 12.4, 6, 14, 4.4
11.212.513.910.614.6Option D

+1.6,-3.2,+4.8,-6.4,+8,-9.6

10.8 in place of 10.6. - 200, 196, 192, 180, 160, 130, 88
196200180130160Option A

Double difference

198 in place of 196. - A man invested Rs. 8000 in a scheme giving 20% p.a. compound interest for two year. The interest received from this scheme is 400% more than the interest on some other amount from another scheme giving 8% S.I. for 4 year. Find the total amount invested in both schemes.
11,00010,20012,50015,20012,120Option B

CI earned in 2 years = 8000[(1+20/100)^3 – 1] – 8000

= 3520

Let amount invested in another scheme is Rs.P.

3520 = 500% of P*8*4/100

=>P – [3520*100]/[32*5]=>P = 2200

Total investment = 8000+2200 = 10,200 - Radius of a cylinder is equal to the side of an equilateral triangle having area cm² and height of the cylinder is equal to the perimeter of the triangle. Then find the volume of cylinder.
1782*pi1126*pi1536*pi1440*pi1661*piOption C

Radius of cylinder = side of equilateral Δ

(3)^1/2/4 a^2 = 16(3)^1/2

a² = 64

=>a = 8 cm

And, height of cylinder = 3 × 8 = 24 cm

Volume of cylinder = πr²h

= π × 8² × 24

= 1536 π cm³ - Sum of present ages of A and B is 41. Age of A 2 year hence is equal to age of C, 1 year ago. Age of A, 4 year hence is equal to age of B 1year ago and ratio of present age of A and D is 3 : 4. Find the difference of age of C and D.
25743Option E

A + B = 41 …(i)

C -1 = A + 2

C = A + 3

And

A + 4 = B – 1

⇒ B = A + 5 …(ii)

From (i) + (ii)

A = 18 years

B = 18 + 5 = 23 years

C = 18 + 3 = 21 years

D = = 24 years

Required difference = 24 – 21 = 3 years - The surface area of a spherical part of a hemispherical bowl with a flat circular detachable cover, excluding the cover, is 616 sq cm. The area of the cover is 38.5 sq cm. What is the volume of the bowl?
2636.122302.151928.612172.122032.69Option E

2*pi*r*r = 616

=>r^2 = 616/2*7/22

=>r^2 = 98

Volume = 2/3 *pi*98*7(2)^1/2 = 2032.69 cm^3 - In one litre of mixture of alcohol and water, 30% is water. The amount of alcohol that must be added to the mixture, so that the part of water in the mixture becomes 15%, is:
14521000110012341340Option B

300/(1000+x)*100 = 15

=>x = 1000 ml