 # Mixed Quantitative Aptitude Questions Set 148

Directions(1-5): Find the wrong term of the following series.

1. 3, 4, 9, 28, 113, 565, 3397
9
113
565
28
4
Option C
*1+1
*2+1
*3+1
*4+1
*5+1
*6+1
566 in place of 565.

2. 4, 6, 12, 30, 60, 315, 1260
12
60
6
315
1260
Option B
*1.5,*2,*2.5,*3,*3.5,*4
90 in place of 60.

3. 1, 730, 975, 1054, 1081, 1090, 1093
1054
730
1081
1090
975
Option E

4. 9.2, 10.6, 7.6, 12.4, 6, 14, 4.4
11.2
12.5
13.9
10.6
14.6
Option D
+1.6,-3.2,+4.8,-6.4,+8,-9.6
10.8 in place of 10.6.

5. 200, 196, 192, 180, 160, 130, 88
196
200
180
130
160
Option A
Double difference
198 in place of 196.

6. A man invested Rs. 8000 in a scheme giving 20% p.a. compound interest for two year. The interest received from this scheme is 400% more than the interest on some other amount from another scheme giving 8% S.I. for 4 year. Find the total amount invested in both schemes.
11,000
10,200
12,500
15,200
12,120
Option B
CI earned in 2 years = 8000[(1+20/100)^3 – 1] – 8000
= 3520
Let amount invested in another scheme is Rs.P.
3520 = 500% of P*8*4/100
=>P – [3520*100]/[32*5]=>P = 2200
Total investment = 8000+2200 = 10,200

7. Radius of a cylinder is equal to the side of an equilateral triangle having area cm² and height of the cylinder is equal to the perimeter of the triangle. Then find the volume of cylinder.
1782*pi
1126*pi
1536*pi
1440*pi
1661*pi
Option C
Radius of cylinder = side of equilateral Δ
(3)^1/2/4 a^2 = 16(3)^1/2
a² = 64
=>a = 8 cm
And, height of cylinder = 3 × 8 = 24 cm
Volume of cylinder = πr²h
= π × 8² × 24
= 1536 π cm³

8. Sum of present ages of A and B is 41. Age of A 2 year hence is equal to age of C, 1 year ago. Age of A, 4 year hence is equal to age of B 1year ago and ratio of present age of A and D is 3 : 4. Find the difference of age of C and D.
2
5
7
4
3
Option E
A + B = 41 …(i)
C -1 = A + 2
C = A + 3
And
A + 4 = B – 1
⇒ B = A + 5 …(ii)
From (i) + (ii)
A = 18 years
B = 18 + 5 = 23 years
C = 18 + 3 = 21 years
D = = 24 years
Required difference = 24 – 21 = 3 years

9. The surface area of a spherical part of a hemispherical bowl with a flat circular detachable cover, excluding the cover, is 616 sq cm. The area of the cover is 38.5 sq cm. What is the volume of the bowl?
2636.12
2302.15
1928.61
2172.12
2032.69
Option E
2*pi*r*r = 616
=>r^2 = 616/2*7/22
=>r^2 = 98
Volume = 2/3 *pi*98*7(2)^1/2 = 2032.69 cm^3

10. In one litre of mixture of alcohol and water, 30% is water. The amount of alcohol that must be added to the mixture, so that the part of water in the mixture becomes 15%, is:
1452
1000
1100
1234
1340
Option B
300/(1000+x)*100 = 15
=>x = 1000 ml

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