Mixed Quantitative Aptitude Questions Set 188

1. In a fraction the numerator is increased by 80% and the denominator of the fraction is increased by 120%, then it becomes 5/11. Find the original fraction?
1/8
2/5
5/9
2/11
4/7
Option C
The original fraction be (x/y)
[X*(180/100)]/[Y*(220/100)] = 5/11
9x/11y = 5/11
x/y = 5/9

2. Akil, Brahma and kannan together have Rs. 33250. If 3/7th of Akilâ€™s amount is equal to 2/3rd of Brahmaâ€™s amount and 1/4th of Brahmaâ€™s amount is equal to 5/8th of kannanâ€™s amount, then how much amount does Akil have?
Rs. 17000
Rs. 47500
Rs. 17500
Rs. 27500
Rs. 15600
Option C
A kil+ Brahma + kannan = Rs. 33250
(3/7)* A = (2/3)* B
(A/B) = (2/3) * (7/3) = 14/9
(1/4)* B = (5/8)* k
(B/k) = (5/8) * (4/1) = 5/2
The ratio of A, B and k = 70: 45: 18
133â€™s = 33250
1â€™s = 250
70â€™s = Rs. 17500

3. Person 1, 2 and 3 started a business by investing an amount of Rs. 45000, Rs. 65000 and Rs. 70000 respectively. After 3 months, 1 invested Rs. 15000 more and 2 withdraw Rs. 5000. And after 4 months, 3 withdraw Rs. 15000. If the total profit at the end of the year is Rs. 114405, then find the share of 1?
Rs. 35500
Rs. 37505
Rs. 25505
Rs. 30005
Rs. 35505
Option
The share of 1, 2 and 3,
= > [45000*3 + 60000*9]: [65000*3 + 60000*9]: [70000*7 + 55000*5]= > 675000: 735000: 765000
= > 45: 49: 51
Total profit = Rs. 114405
145â€™s = 114405
1â€™s = 789
The share of 1 = 789*45 = Rs. 35505

4. A 90 litres of mixture of acid and water contains acid and water in the ratio of 3: 2. How much water should be added to the mixture to get 45 % acid on it?
30
45
67
23
12
Option A
Total mixture of acid and water = 90 litres
5â€™s = 90
1â€™s = 18
Total acid = 54 litres, water = 36 litres
According to the question,
54/(36 + x) = (45/55)
54/(36 + x) = 9/11
66 = 36 + x
X = 30
30 litres of water should be added to the mixture.

5. A yacht can sail 55 km downstream in 66 min. The ratio of the speed of the yacht in still water to the speed of the stream is 4: 1. How much time will the yacht take to cover 72 km upstream?
1 hr 24 m
2hr 24 m
5 hr 20 m
6 hr 32 m
1 hr 15m
Option B
Speed of downstream = D/T = 55/(66/60) = 55*(60/66) = 50 km/hr
The ratio of the speed of the yacht in still water to the speed of the stream
= > 4: 1 (4x, x)
5x = 50
X = 10
Speed of upstream = 4x â€“ x = 3x = 30 km/hr
Distance = 752 km
Time = D/S = 72/30 = 2 2/5 hr = 2 hours 24 mins

6. 79.89% of 1400 + 17.05% of 399.99 â€“ 20% of 520 =? * 2
430
220
541
123
450
Option C
80% of 1400 + 16.5% of 400 â€“ 20% of 520 =? * 2
80/100 * 1400 + 16.5/100 * 400 â€“ 20/100 * 520 =? * 2
1120 + 66 -104 =? * 2
? = 541

7. 98.902 * âˆš1681 + 22.87 * âˆš5184 â€“ 48 * 69 =? * 89
27
23
22
24
25
Option A
99 * âˆš1681 + 23 * âˆš5184 â€“ 48 * 69 =? * 89
4059 + 1656 â€“ 3312 =? * 89
? = 27

8. 34.56 % of 119.9 + 12.5 % of 231.5 + 9 * 29 =? + 132
200
150
250
300
350
Option A
35 % of 120 + 12.5 % of 232 + 9 * 29 =? + 132
42 + 29 + 261 =? + 132
? = 200

9. (âˆš1023.5 + âˆš3720.5) * âˆš15.89 +? = 482
120
130
110
100
90
Option C
(âˆš1024 + âˆš3721) * âˆš16 +? = 482
(32+ 61) *4 +? =482
372 + ? = 482
? = 482 â€“ 372
? = 110

10. 19.99 % of 64.67 + 111.5 * âˆš81 -13 * 8 =? + 27 * 15
340
230
123
540
512
Option E
20 % of 65 + 112 * âˆš81 -13 * 8 =? + 27 * 15
13 + 1008 â€“ 104 =? + 405
? = 512

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