- In a fraction the numerator is increased by 80% and the denominator of the fraction is increased by 120%, then it becomes 5/11. Find the original fraction?
1/82/55/92/114/7Option C

The original fraction be (x/y)

[X*(180/100)]/[Y*(220/100)] = 5/11

9x/11y = 5/11

x/y = 5/9 - Akil, Brahma and kannan together have Rs. 33250. If 3/7th of Akil’s amount is equal to 2/3rd of Brahma’s amount and 1/4th of Brahma’s amount is equal to 5/8th of kannan’s amount, then how much amount does Akil have?
Rs. 17000Rs. 47500Rs. 17500Rs. 27500Rs. 15600Option C

A kil+ Brahma + kannan = Rs. 33250

(3/7)* A = (2/3)* B

(A/B) = (2/3) * (7/3) = 14/9

(1/4)* B = (5/8)* k

(B/k) = (5/8) * (4/1) = 5/2

The ratio of A, B and k = 70: 45: 18

133’s = 33250

1’s = 250

70’s = Rs. 17500 - Person 1, 2 and 3 started a business by investing an amount of Rs. 45000, Rs. 65000 and Rs. 70000 respectively. After 3 months, 1 invested Rs. 15000 more and 2 withdraw Rs. 5000. And after 4 months, 3 withdraw Rs. 15000. If the total profit at the end of the year is Rs. 114405, then find the share of 1?
Rs. 35500Rs. 37505Rs. 25505Rs. 30005Rs. 35505Option

The share of 1, 2 and 3,

= > [45000*3 + 60000*9]: [65000*3 + 60000*9]: [70000*7 + 55000*5]= > 675000: 735000: 765000

= > 45: 49: 51

Total profit = Rs. 114405

145’s = 114405

1’s = 789

The share of 1 = 789*45 = Rs. 35505 - A 90 litres of mixture of acid and water contains acid and water in the ratio of 3: 2. How much water should be added to the mixture to get 45 % acid on it?
3045672312Option A

Total mixture of acid and water = 90 litres

5’s = 90

1’s = 18

Total acid = 54 litres, water = 36 litres

According to the question,

54/(36 + x) = (45/55)

54/(36 + x) = 9/11

66 = 36 + x

X = 30

30 litres of water should be added to the mixture. - A yacht can sail 55 km downstream in 66 min. The ratio of the speed of the yacht in still water to the speed of the stream is 4: 1. How much time will the yacht take to cover 72 km upstream?
1 hr 24 m2hr 24 m5 hr 20 m6 hr 32 m1 hr 15mOption B

Speed of downstream = D/T = 55/(66/60) = 55*(60/66) = 50 km/hr

The ratio of the speed of the yacht in still water to the speed of the stream

= > 4: 1 (4x, x)

5x = 50

X = 10

Speed of upstream = 4x – x = 3x = 30 km/hr

Distance = 752 km

Time = D/S = 72/30 = 2 2/5 hr = 2 hours 24 mins - 79.89% of 1400 + 17.05% of 399.99 – 20% of 520 =? * 2
430220541123450Option C

80% of 1400 + 16.5% of 400 – 20% of 520 =? * 2

80/100 * 1400 + 16.5/100 * 400 – 20/100 * 520 =? * 2

1120 + 66 -104 =? * 2

? = 541 - 98.902 * √1681 + 22.87 * √5184 – 48 * 69 =? * 89
2723222425Option A

99 * √1681 + 23 * √5184 – 48 * 69 =? * 89

4059 + 1656 – 3312 =? * 89

? = 27 - 34.56 % of 119.9 + 12.5 % of 231.5 + 9 * 29 =? + 132
200150250300350Option A

35 % of 120 + 12.5 % of 232 + 9 * 29 =? + 132

42 + 29 + 261 =? + 132

? = 200 - (√1023.5 + √3720.5) * √15.89 +? = 482
12013011010090Option C

(√1024 + √3721) * √16 +? = 482

(32+ 61) *4 +? =482

372 + ? = 482

? = 482 – 372

? = 110 - 19.99 % of 64.67 + 111.5 * √81 -13 * 8 =? + 27 * 15
340230123540512Option E

20 % of 65 + 112 * √81 -13 * 8 =? + 27 * 15

13 + 1008 – 104 =? + 405

? = 512