- In a fraction the numerator is increased by 80% and the denominator of the fraction is increased by 120%, then it becomes 5/11. Find the original fraction?
1/82/55/92/114/7Option C

The original fraction be (x/y)

[X*(180/100)]/[Y*(220/100)] = 5/11

9x/11y = 5/11

x/y = 5/9 - Akil, Brahma and kannan together have Rs. 33250. If 3/7th of Akilâ€™s amount is equal to 2/3rd of Brahmaâ€™s amount and 1/4th of Brahmaâ€™s amount is equal to 5/8th of kannanâ€™s amount, then how much amount does Akil have?
Rs. 17000Rs. 47500Rs. 17500Rs. 27500Rs. 15600Option C

A kil+ Brahma + kannan = Rs. 33250

(3/7)* A = (2/3)* B

(A/B) = (2/3) * (7/3) = 14/9

(1/4)* B = (5/8)* k

(B/k) = (5/8) * (4/1) = 5/2

The ratio of A, B and k = 70: 45: 18

133â€™s = 33250

1â€™s = 250

70â€™s = Rs. 17500 - Person 1, 2 and 3 started a business by investing an amount of Rs. 45000, Rs. 65000 and Rs. 70000 respectively. After 3 months, 1 invested Rs. 15000 more and 2 withdraw Rs. 5000. And after 4 months, 3 withdraw Rs. 15000. If the total profit at the end of the year is Rs. 114405, then find the share of 1?
Rs. 35500Rs. 37505Rs. 25505Rs. 30005Rs. 35505Option

The share of 1, 2 and 3,

= > [45000*3 + 60000*9]: [65000*3 + 60000*9]: [70000*7 + 55000*5]= > 675000: 735000: 765000

= > 45: 49: 51

Total profit = Rs. 114405

145â€™s = 114405

1â€™s = 789

The share of 1 = 789*45 = Rs. 35505 - A 90 litres of mixture of acid and water contains acid and water in the ratio of 3: 2. How much water should be added to the mixture to get 45 % acid on it?
3045672312Option A

Total mixture of acid and water = 90 litres

5â€™s = 90

1â€™s = 18

Total acid = 54 litres, water = 36 litres

According to the question,

54/(36 + x) = (45/55)

54/(36 + x) = 9/11

66 = 36 + x

X = 30

30 litres of water should be added to the mixture. - A yacht can sail 55 km downstream in 66 min. The ratio of the speed of the yacht in still water to the speed of the stream is 4: 1. How much time will the yacht take to cover 72 km upstream?
1 hr 24 m2hr 24 m5 hr 20 m6 hr 32 m1 hr 15mOption B

Speed of downstream = D/T = 55/(66/60) = 55*(60/66) = 50 km/hr

The ratio of the speed of the yacht in still water to the speed of the stream

= > 4: 1 (4x, x)

5x = 50

X = 10

Speed of upstream = 4x â€“ x = 3x = 30 km/hr

Distance = 752 km

Time = D/S = 72/30 = 2 2/5 hr = 2 hours 24 mins - 79.89% of 1400 + 17.05% of 399.99 â€“ 20% of 520 =? * 2
430220541123450Option C

80% of 1400 + 16.5% of 400 â€“ 20% of 520 =? * 2

80/100 * 1400 + 16.5/100 * 400 â€“ 20/100 * 520 =? * 2

1120 + 66 -104 =? * 2

? = 541 - 98.902 * âˆš1681 + 22.87 * âˆš5184 â€“ 48 * 69 =? * 89
2723222425Option A

99 * âˆš1681 + 23 * âˆš5184 â€“ 48 * 69 =? * 89

4059 + 1656 â€“ 3312 =? * 89

? = 27 - 34.56 % of 119.9 + 12.5 % of 231.5 + 9 * 29 =? + 132
200150250300350Option A

35 % of 120 + 12.5 % of 232 + 9 * 29 =? + 132

42 + 29 + 261 =? + 132

? = 200 - (âˆš1023.5 + âˆš3720.5) * âˆš15.89 +? = 482
12013011010090Option C

(âˆš1024 + âˆš3721) * âˆš16 +? = 482

(32+ 61) *4 +? =482

372 + ? = 482

? = 482 â€“ 372

? = 110 - 19.99 % of 64.67 + 111.5 * âˆš81 -13 * 8 =? + 27 * 15
340230123540512Option E

20 % of 65 + 112 * âˆš81 -13 * 8 =? + 27 * 15

13 + 1008 â€“ 104 =? + 405

? = 512

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