 # Mixed Quantitative Aptitude Questions Set 188

1. In a fraction the numerator is increased by 80% and the denominator of the fraction is increased by 120%, then it becomes 5/11. Find the original fraction?
1/8
2/5
5/9
2/11
4/7
Option C
The original fraction be (x/y)
[X*(180/100)]/[Y*(220/100)] = 5/11
9x/11y = 5/11
x/y = 5/9

2. Akil, Brahma and kannan together have Rs. 33250. If 3/7th of Akil’s amount is equal to 2/3rd of Brahma’s amount and 1/4th of Brahma’s amount is equal to 5/8th of kannan’s amount, then how much amount does Akil have?
Rs. 17000
Rs. 47500
Rs. 17500
Rs. 27500
Rs. 15600
Option C
A kil+ Brahma + kannan = Rs. 33250
(3/7)* A = (2/3)* B
(A/B) = (2/3) * (7/3) = 14/9
(1/4)* B = (5/8)* k
(B/k) = (5/8) * (4/1) = 5/2
The ratio of A, B and k = 70: 45: 18
133’s = 33250
1’s = 250
70’s = Rs. 17500

3. Person 1, 2 and 3 started a business by investing an amount of Rs. 45000, Rs. 65000 and Rs. 70000 respectively. After 3 months, 1 invested Rs. 15000 more and 2 withdraw Rs. 5000. And after 4 months, 3 withdraw Rs. 15000. If the total profit at the end of the year is Rs. 114405, then find the share of 1?
Rs. 35500
Rs. 37505
Rs. 25505
Rs. 30005
Rs. 35505
Option
The share of 1, 2 and 3,
= > [45000*3 + 60000*9]: [65000*3 + 60000*9]: [70000*7 + 55000*5]= > 675000: 735000: 765000
= > 45: 49: 51
Total profit = Rs. 114405
145’s = 114405
1’s = 789
The share of 1 = 789*45 = Rs. 35505

4. A 90 litres of mixture of acid and water contains acid and water in the ratio of 3: 2. How much water should be added to the mixture to get 45 % acid on it?
30
45
67
23
12
Option A
Total mixture of acid and water = 90 litres
5’s = 90
1’s = 18
Total acid = 54 litres, water = 36 litres
According to the question,
54/(36 + x) = (45/55)
54/(36 + x) = 9/11
66 = 36 + x
X = 30
30 litres of water should be added to the mixture.

5. A yacht can sail 55 km downstream in 66 min. The ratio of the speed of the yacht in still water to the speed of the stream is 4: 1. How much time will the yacht take to cover 72 km upstream?
1 hr 24 m
2hr 24 m
5 hr 20 m
6 hr 32 m
1 hr 15m
Option B
Speed of downstream = D/T = 55/(66/60) = 55*(60/66) = 50 km/hr
The ratio of the speed of the yacht in still water to the speed of the stream
= > 4: 1 (4x, x)
5x = 50
X = 10
Speed of upstream = 4x – x = 3x = 30 km/hr
Distance = 752 km
Time = D/S = 72/30 = 2 2/5 hr = 2 hours 24 mins

6. 79.89% of 1400 + 17.05% of 399.99 – 20% of 520 =? * 2
430
220
541
123
450
Option C
80% of 1400 + 16.5% of 400 – 20% of 520 =? * 2
80/100 * 1400 + 16.5/100 * 400 – 20/100 * 520 =? * 2
1120 + 66 -104 =? * 2
? = 541

7. 98.902 * √1681 + 22.87 * √5184 – 48 * 69 =? * 89
27
23
22
24
25
Option A
99 * √1681 + 23 * √5184 – 48 * 69 =? * 89
4059 + 1656 – 3312 =? * 89
? = 27

8. 34.56 % of 119.9 + 12.5 % of 231.5 + 9 * 29 =? + 132
200
150
250
300
350
Option A
35 % of 120 + 12.5 % of 232 + 9 * 29 =? + 132
42 + 29 + 261 =? + 132
? = 200

9. (√1023.5 + √3720.5) * √15.89 +? = 482
120
130
110
100
90
Option C
(√1024 + √3721) * √16 +? = 482
(32+ 61) *4 +? =482
372 + ? = 482
? = 482 – 372
? = 110

10. 19.99 % of 64.67 + 111.5 * √81 -13 * 8 =? + 27 * 15
340
230
123
540
512
Option E
20 % of 65 + 112 * √81 -13 * 8 =? + 27 * 15
13 + 1008 – 104 =? + 405
? = 512

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