- What is the sum if the difference between the simple interest and Compound interest on that sum for 2 years at 8 % is Rs. 1600.
270000210000250025000250000Option E

Diff = Sum*(r/100)2

1600 = Sum*(8/100)2

1600*100*100/64 = Sum

Sum = Rs. 250000 - 6 years ago, the ratio of ages of Me and my husband is 2: 3. After 6 years, the ratio of ages of Me and my husband is 3: 4. Find the sum of our present ages?
4089697290Option D

6 years ago, the ratio of ages of ours = 2: 3 (2x, 3x)

Present ages of ours = 2x + 6, 3x + 6

After 6 years, the ratio of ages ours = 3: 4

According to the question,

(2x + 12)/(3x + 12) = (3/4)

8x + 48 = 9x + 36

x = 12

Sum of the present ages ours = 2x + 3x + 12 = 72 years - Cistern A opened to fill the tank and after 4 hours is closed and then Cistern B opened and fills the remaining tank in 10 hours. If Cistern B alone fill 25% of the tank in 5 hours, in how many hours Cistern A and B together fill the tank completely?
5(1/7)5(5/9)5(6/7)4(5/7)5(5/7)Option E

B = 5 * 4/1 = 20 hours

4/x + 10/20 = 1

4/x = Â½

1/x = 1/8

A + B = 1/20 + 1/8

= 7/40

Time = 40/7 hours = 5(5/7) hours - A box contains x+4 pink chocolates, 6 white and 8 brown colour chocolates; if two chocolates are taken random and the probability of getting both are white colour chocolates is 5/92, then find the difference between the no. of pink colour chocolates and the no. of brown colour chocolates.
23456Option A

Given,

6c2/(x+18)c2=5/92

X2+35x-246=0

we get x=6

Required difference = 10-8=2 - Average ages of 5 men M1, M2, M3, M4 and M5 is 38 years. Ratio of the ages of M1 to M3 is 3:4 and after 5 years the ratio of the ages of M2 to M4 becomes 2: 3. If the difference between the ages of M1 and M2 is 2 years, then what is the present age of M5?
13456667We cannot find the answer.Option E

M1 + M2 + M3 + M4 + M5 = 190 years

M1/M3 = 3/4

M2 + 5/M4 + 5 = 2/3

2M4 + 10 = 3M2 + 15

2M4 â€“ 3M2 = 5

We cannot find the answer. - If the certain number of candidates in the police selection and the average weight is x kg. If after one month 5 candidates is reduced their weight by 4 kg, then the average weight is reduced by 2 kg. What is the total number of candidates in the selection?
5040302010Option E

Number of candidates = y

Total weight = xy

Total weight after reduced the weight = xy â€“ 5 * 4 = xy â€“ 20

(x â€“ 2) * y = xy â€“ 20

xy â€“ 2y = xy â€“ 20

2y = 20

y = 10 - Kailash is 8 years older than Akash and Akash is 12 years younger than Prakash. If the sum of the ages of Kailash, Akash and Prakash is 80 years, then what is Akashâ€™s age after 10 years?
5040302010Option C

Kâ€“ A = 8

Pâ€“A = 12

K + A + P = 80

A + 8 + A + 12 + B = 80

3A = 60

A = 20 years

After 10 years Akashâ€™s age = 20 + 10 = 30 years - Man A spends 60% of his salary on education fee. He spends 30% of remaining on food and 50% of the remaining on shopping. If he left with him Rs.2800, then what is the amount he spends on education fee?
1200015000125001234032000Option A

Education fee = 60/100 * x

Remaining = 40/100 * x

Food = 40/100 * x * 30/100 = 12x/100

Remaining = 40x/100 â€“ 12x/100 = 28x/100

Shopping = 28x/100 * 50/100 = 14x/100

Remaining = 14x/100

14x/100 = 2800

x = 20000

Education fee = (20000/100) * 60 = 12000 - Ratio of the length to breadth of the rectangular board is 2: 1. If Rs.1440 is required to paint the board at the rate of Rs.5 per square meter, then what is the difference between the length and breadth of the rectangular board?
1213141516Option A

Area of the board = l * b

2x * x = 1440/5

x = 12 m

Length = 2 * 12 = 24 m

Breadth = 12 cm

Difference = 24 â€“ 12 = 12 cm - The ratio of the income of P and Q is 3: 2 and the ratio of their spends is 6: 5. If the ratio of the income to savings of P is 3: 1, then what is the ratio of the savings of P to Q?
3: 53: 73: 23: 13: 4Option D

Income of P = 3x

Income of Q = 2x

Spends of A = 6y

Spends of B = 5y

Pâ€™s savings = 3x â€“ 6y

Pâ€™s savings = 1/3 * 3x = x

3x â€“ 6y = x

2x = 6y

x = 3yQâ€™s savings = 2x â€“ 5y = 2x â€“ 5 * (x/3)

= 6x â€“ 5x/3 = x/3

Required ratio = x: x/3 = 3: 1

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