Mixed Quantitative Aptitude Questions Set 195

  1. What is the sum if the difference between the simple interest and Compound interest on that sum for 2 years at 8 % is Rs. 1600.
    Option E
    Diff = Sum*(r/100)2
    1600 = Sum*(8/100)2
    1600*100*100/64 = Sum
    Sum = Rs. 250000


  2. 6 years ago, the ratio of ages of Me and my husband is 2: 3. After 6 years, the ratio of ages of Me and my husband is 3: 4. Find the sum of our present ages?
    Option D
    6 years ago, the ratio of ages of ours = 2: 3 (2x, 3x)
    Present ages of ours = 2x + 6, 3x + 6
    After 6 years, the ratio of ages ours = 3: 4
    According to the question,
    (2x + 12)/(3x + 12) = (3/4)
    8x + 48 = 9x + 36
    x = 12
    Sum of the present ages ours = 2x + 3x + 12 = 72 years


  3. Cistern A opened to fill the tank and after 4 hours is closed and then Cistern B opened and fills the remaining tank in 10 hours. If Cistern B alone fill 25% of the tank in 5 hours, in how many hours Cistern A and B together fill the tank completely?
    Option E
    B = 5 * 4/1 = 20 hours
    4/x + 10/20 = 1
    4/x = ½
    1/x = 1/8
    A + B = 1/20 + 1/8
    = 7/40
    Time = 40/7 hours = 5(5/7) hours


  4. A box contains x+4 pink chocolates, 6 white and 8 brown colour chocolates; if two chocolates are taken random and the probability of getting both are white colour chocolates is 5/92, then find the difference between the no. of pink colour chocolates and the no. of brown colour chocolates.
    Option A
    we get x=6
    Required difference = 10-8=2


  5. Average ages of 5 men M1, M2, M3, M4 and M5 is 38 years. Ratio of the ages of M1 to M3 is 3:4 and after 5 years the ratio of the ages of M2 to M4 becomes 2: 3. If the difference between the ages of M1 and M2 is 2 years, then what is the present age of M5?
    We cannot find the answer.
    Option E
    M1 + M2 + M3 + M4 + M5 = 190 years
    M1/M3 = 3/4
    M2 + 5/M4 + 5 = 2/3
    2M4 + 10 = 3M2 + 15
    2M4 – 3M2 = 5
    We cannot find the answer.


  6. If the certain number of candidates in the police selection and the average weight is x kg. If after one month 5 candidates is reduced their weight by 4 kg, then the average weight is reduced by 2 kg. What is the total number of candidates in the selection?
    Option E
    Number of candidates = y
    Total weight = xy
    Total weight after reduced the weight = xy – 5 * 4 = xy – 20
    (x – 2) * y = xy – 20
    xy – 2y = xy – 20
    2y = 20
    y = 10


  7. Kailash is 8 years older than Akash and Akash is 12 years younger than Prakash. If the sum of the ages of Kailash, Akash and Prakash is 80 years, then what is Akash’s age after 10 years?
    Option C
    K– A = 8
    P–A = 12
    K + A + P = 80
    A + 8 + A + 12 + B = 80
    3A = 60
    A = 20 years
    After 10 years Akash’s age = 20 + 10 = 30 years


  8. Man A spends 60% of his salary on education fee. He spends 30% of remaining on food and 50% of the remaining on shopping. If he left with him Rs.2800, then what is the amount he spends on education fee?
    Option A
    Education fee = 60/100 * x
    Remaining = 40/100 * x
    Food = 40/100 * x * 30/100 = 12x/100
    Remaining = 40x/100 – 12x/100 = 28x/100
    Shopping = 28x/100 * 50/100 = 14x/100
    Remaining = 14x/100
    14x/100 = 2800
    x = 20000
    Education fee = (20000/100) * 60 = 12000


  9. Ratio of the length to breadth of the rectangular board is 2: 1. If Rs.1440 is required to paint the board at the rate of Rs.5 per square meter, then what is the difference between the length and breadth of the rectangular board?
    Option A
    Area of the board = l * b
    2x * x = 1440/5
    x = 12 m
    Length = 2 * 12 = 24 m
    Breadth = 12 cm
    Difference = 24 – 12 = 12 cm


  10. The ratio of the income of P and Q is 3: 2 and the ratio of their spends is 6: 5. If the ratio of the income to savings of P is 3: 1, then what is the ratio of the savings of P to Q?
    3: 5
    3: 7
    3: 2
    3: 1
    3: 4
    Option D
    Income of P = 3x
    Income of Q = 2x
    Spends of A = 6y
    Spends of B = 5y
    P’s savings = 3x – 6y
    P’s savings = 1/3 * 3x = x
    3x – 6y = x
    2x = 6y
    x = 3y

    Q’s savings = 2x – 5y = 2x – 5 * (x/3)
    = 6x – 5x/3 = x/3
    Required ratio = x: x/3 = 3: 1


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