- Ratio of number of male of company X to company Y is 8 : 5. The ratio of female to male of company X and company Y is 3 : 4 and 7 : 5 respectively. The difference between number of female of company X and company Y is 150, then find total number of male and female in company Y ?
27002200180015001200Option C
Let the number of male of company X and Y = 8a and 5a
number of male and female of company X = 4a and 3a
number of male and female of company Y = 5a and 7a
The number of male and female of company X = 8a and 6a
difference = 7a – 6a = 150
a = 150
sum of number of male and female of company Y = 5a + 7a = 12a
= 12 * 15 = 1800 - A and B entered into a partnership business with initial investments of rs.4000 and rs.5000 respectively. After 6 months A and B withdrew rs.1000 and rs.2000 respectively, while C joined with them capital of 4x. If after 14 months, C received rs.4000 as profit share out of total profit of rs.12500, then find how much amount invested by C ?
40004500480060003200Option D
Profit sharing ratio of A, B and C = (4000 * 6 + 3000 * 8) : (5000 * 6 + 3000 * 8) : 4x * 8
= 48000 : 54000 : 32x
profit of A and B = 12500 – 4000 = 8500
32x/102000 = 4000/8500
x = 1500
C invested = 4 * 1500 = 6000 - Rohit invested rs.100x in a scheme offering compound interest at the rate of 20% p.a and after two years he again invested rs.80x in the same scheme. He received rs. 1243.2 as total interest after 3 years. If he rs.120x is invested at 10% p.a simple interest for 4 years the find how much interest he received ?
1128672845862920Option B
Compound interest after 2 years = 100x * 120/100 * 120/100 – 100x = 44x
now total principal = 100x + 44x + 80x = 224x
CI received after one year = 224x * 20/100 = 44.8x
total CI after 3 years = 88.8x
88.8x = 1243.2
x = 14
If he received 120x at 10% p.a in SI for 4 years
120 * 14 * 40/100 = 672 - The ratio of milk and water in Jar A is 5 : 3 and total mixture of container A is 480 liters. Jar B contains mixture of water to milk in the ratio of 7 : 9. Total mixture of jar A and B poured into another jar C such that quantity of milk in jar C is 60% of total mixture. Find the quantity of mixture in jar B ?
440 lt480 lt380 lt240 lt320 ltOption E
Quantity of milk in jar A = 480 * 5/8 = 300
quantity of water in jar B = 480 * 3/8 = 180
let the quantity of milk and water in jar B = 9x and 7x
300 + 9x = (480 + 16x) * 60/100
1500 + 45x = 48x + 1440
3x = 60
x = 20
total mixture in jar B = (9x + 7x) * 20 = 320 liters - A man deposited rs.8000 in a bank offering compound interest of 20% p.a compound annually for first 1.5 years and after 1.5 years he offering simple interest 50% p.a for rest of the time. If at the end of 1.5 years, he withdrew rs.3560, then how much amount received by him at the end of 3 years ?
1240010500180001225015240Option D
Rate of compound interest after 1.5 years = 20 + 10 + 20 * 10/100 = 32%
total amount after 1.5 years = 8000 * 132/100 = 10560
remaining amount after withdrawal by him = 10560 – 3560 = 7000
simple interest received for rest of time = 7000 * 1.5 * 50/100 = 5250
total amount received = 7000 + 5250 = 12250 - Directions : What will come in place of questions (?) marks in the following questions given below ?
30% of 168 + √1024 + 42 = ?84.294.8124.46584Option C
50.4 + 32 + 42 = ?
? = 124.4 - (25^2) + (38^2) – 1220 + ? = 1000
151162170175320Option A
625 + 1444 – 1220 + ? = 1000
? = 1000 – 849
? = 151 - (32 * 8 + 440 + 15 * 12) * 6 = ?
43403240201552568450Option D
(256 + 440 + 180) * 6 = ?
? = 5256 - 5^2 + 387 = 180/? + 376
68457Option D
25 + 387 = 180/? + 376
412 – 376 = 180/?
? = 5 - 75 * 8 + √1156 = ?^3 + 122
4321484Option D
600 + 34 = ?^3 + 122
?^3 = 512
? = 8
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