- A man deposited a total amount of rs. 36000 partially in scheme A and scheme B. Scheme A offers simple interest at the rate of 14% p.a while scheme B offers compound interest at the rate of 20% p.a compounded annually. If the interest earned from scheme A after 2 years is rs.2160 less than the interest earned from scheme B after 2 years, then what is the amount deposited in scheme B ?
1500017000230001400017500Option B

Let amount deposited in scheme B = rs. x

amount deposited in scheme A = rs.(36000 – x)

Rate of compound interest after 2 years = 20 + 20 + 20 * 20/100 = 44%

x * 44/100 – (36000 – x) * 14/100 * 2 = 2160

(44x – 108000 + 28x)/100 = 2160

72x = 1224000

x = 17000

amount deposited in scheme B is rs.17000 - The income of A and B are in the ratio 4 : 5 respectively. If the expenditure of A and B are rs.14000 and rs.18000 and ratio of saving of A and B is 6 : 7, then what is the saving of B ?
80009200700068008200Option C

Let income of A and B = 4x and 5x respectively

4x – 14000/5x – 18000 = 6/7

28x – 98000 = 30x – 108000

x = 5000

income of B = 5 * 5000 = 25000

saving of B = 25000 – 18000 = 7000 - A takes 5 days less than B to complete a work alone. A and B together can complete the work in 13 7/11 days. Find the time taken by B to complete the whole work ?
25 days30 days45 days43 days40daysOption B

Let B alone can complete the whole work = x days

A alone can complete the whole work = (x – 5) days

1/x – 5 + 1/x = 11/150

2x – 5/x^2 – 5x = 11/150

11x^2 – 55x = 300x – 750

11x^2 – 355x + 750 = 0

11x^2 – 330x – 25x + 750 = 0

x = 30

B alone can complete the whole work in 30 days - Three containers having capacity in the ratio of 4 : 5 : 3 contain mixture of milk and water in the ratio of 2 : 3, 4 : 1 and 3 : 1 respectively. If all three containers poured in a big container, then find the ratio of water to milk in final mixture ?
28 : 13785 : 15283 : 157134 : 495 : 2Option C

Let total mixture in three container are 400, 500 and 300 respectively

total quantity of milk in big container = 400 * 2/5 + 500 * 4/5 + 300 * 3/4 = 785

total quantity of water in big container = 400 * 3/5 + 500 * 1/5 + 300 * 1/4 = 415

required ratio = 415 : 785 = 83 : 157 - B and C started a partnership business with the capital of rs.(x + 4000) and rs.(x + 2000) respectively. After one year A joined the business with capital of rs.(x + 12000) while B left the business. If at the end of three years the profit sharing ratio of A , B and C is 20 : 6 : 15, then find the difference between amount invested by A and B in the business ?
150001300014000800012000Option D

A : B : C = (x + 12000) * 2 : (x + 4000) * 1 : (x + 2000) * 3

= 2x + 24000 : x + 4000 : 3x + 6000

2x + 24000/x + 4000 = 20/6

20x + 80000 = 12x + 144000

8x = 64000

x = 8000

difference = (8000 + 12000) – (8000 + 4000) = 8000 - Directions : In these questions two equations is given, solve the equations and answer the questions given below.

I. x^2 – 42x + 392 = 0

II. y^2 – 27y + 180 = 0X < YX > YX ≤ YX ≥ YX = Y or no relationOption E

I. x^2 – 28x – 14x + 392 = 0

x = 28 , 14

II. y^2 – 15y – 12y + 180 = 0

y = 15, 12 - I. x^2 – 8x – 65 = 0

II. 2y^2 – 27y + 91 = 0

X < YX > YX ≤ YX ≥ YX = Y or no relationOption E

I. x^2 – 13x + 5x – 65 = 0

x = 13, -5

II. 2y^2 – 14y – 13y + 91 = 0

2y = 14, 13

y = 7, 6.5 - I. x^3 = 216

II. 5y^2 + 2y – 185 = 0X < YX > YX ≤ YX ≥ YX = Y or no relationOption B

I. x^3 = 216

x = 6, 6

II. 5y^2 + 15y – 13y – 37 = 0

5y = – 15, 13

y = -3 , 2.6 - I. x^2 + 17x + 60 = 0

II. y^2 – 2y – 15 = 0X < YX > YX ≤ YX ≥ YX = Y or no relationOption A

I. x^2 + 12x + 5x + 60 = 0

x = -12, -5

II. y^2 – 5y + 3y – 15 = 0

y = 5, -3 - I. x^2 – 15x + 36 = 0

II. y^2 – 19y + 60 = 0X < YX > YX ≤ YX ≥ YX = Y or no relationOption E

I. x^2 – 12x – 3x + 36 = 0

x = 12 , 3

II. y^2 – 15y – 4y + 60 = 0

y = 15, 4