Mixed Quantitative Aptitude Questions Set 225

1. What is the monthly income of Jitu ?
I. Jitu spends 85% of his income on various expenses and remaining amount he saved.
II. Monthly saving of Jitu are rs.7500.
III. Out of total money spent by Jitu in a month, one-fifth is spent on rent and remaining amount of rs.34000 on other items.
Only I and II sufficient
Only II and III sufficient
Only I and II sufficient
Neither I nor II and III is sufficient
Any of the two statements is sufficient
Option E
Let income of Jitu = rs.x
from I and II,
15% of x = 7500
x = 7500 * 100/15 = 50000
From I and III,
x * 85/100 * 4/5 = 34000
x = 50000
from I and III
4/5 th of expenditure = 34000
expenditure = 42500
income = 42500 + 7500 = 50000
thus, answer can be find out by any of two given statement

2. How much time will require the train to reach from point X to point Y ?
I. The train will pass the other train of equal length of 400m running opposite in direction in 16 secs
II. Distance between point X and Y is 252 km.
III. The 400m long train crosses a signal pole in 20sec.
Only I and II is sufficient
Only II and III is sufficient
Neither of any statement is sufficient
All statements are sufficient
Only I and III is sufficient
Option B
Statement I is not required to get answer
from statement III,
Speed of train = 400/20 = 20 m/sec
speed( in km) = 20 * 18/5 = 72 km/hr
from statement II,
time = 252/72 = 3.5 hr
statement II and III required to get answer.

3. What is the length of a running train A crossing another running train B ?
I. A and B two train take 18secs to cross each other, while running opposite direction.
II. The length of train B is 180m
Only I and II is sufficient
Only II is sufficient
Either I or II statement
Neither I nor II is sufficient
Only I sufficient
Option D
Length of train A = l meters
from I, time taken by train to cross each other = 18secs
let speed of train A and B = x and y respectively
relative speed of A and B = (x + y) m/s
from II, length of train B = 180 meters
180 + l/x + y = 18
thus, we can not calculate answer by using these two statements.

4. What will be respective ratio of saving of A and B.
I. Income of A is 4% less than that of C and also expenditure of A is 12.5% less than that of C. B spend 3/5 th of his income.
II. C save rs. 7000 and A save rs.7400. Income of B is rs.1000 more than that of C.
Only I is sufficient
Only II is sufficient
Either I or II statement
Neither I nor II is sufficient
Only I and II is sufficient
Option E
Let income of C = 25x
income of A = 25x * 96/100 = 24x
let expenditure of A = 7y
expenditure of C = 8y
B spend 3/5 th of his his income
from II
saving of C = 7000
saving of A = 7400
Income of B is 1000 that of C
from I and II,
expenditure of A = 24x – 7y = 7400
expenditure of C = 25x – 8y = 7000
by solving two equations,
x = 600 and y = 1000
income of B = 25 * 600 + 1000 = 16000
saving B = 16000 * 2/5 = 6400
Ratio = 7400 : 6400 = 37 : 32
statement I and II is required

5. What is the CI on a sum at the end of 3 years ?
I. CI at the end of two years is rs.110
II. Difference between CI and SI at the end of two year is rs.100 and rate of percent is 10%.
Only I is sufficient
Only II is sufficient
Either I or II statement
Neither I nor II is sufficient
Only I and II is sufficient
Option B
From I,
Sum can not be find out as rate is not given
From II,
Difference PR^2/100^2
100 = P *100/10000
P = 10000
only statement II is sufficient.

6. I. x^2v- 41x + 348 = 0
II. y^2 – 20y + 99 = 0
X < Y
X > Y
X ≥ Y
X ≤ Y
X = Y or no relation.
Option B
I. x^2 – 29x – 12x + 99 = 0
x = 29, 12
II. y^2 – 11y – 9y + 99 = 0
y = 11, 9

7. I. 2x^2 – 2x _ 24 = 0
II. 3y^2 – 8y + 4 = 0
X < Y
X > Y
X ≥ Y
X ≤ Y
X = Y or no relation.
Option E
I. 2x^2 – 8x + 6x – 24 = 0
x = 8, – 6
x = 4, -3
II. 3y^2 – 6y – 2y + 4 = 0
3y = 6, 2
y = 2, .67

8. I. 5x^2 – 28x + 15 = 0
II. 3y^2 – 29 y + 68 = 0
X < Y
X > Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option E
I. 5x^2 – 25x – 3x + 15 = 0
5x = 25, 3
x = 5, .6
II. 3y^2 – 17y – 12y + 68 = 0
y3y = 17, 12
y = 5.66, 4

9. I. x^3 = 4913
II. y^2 = 225
X < Y
X > Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option B
I. x^3 = 4913
x = 17
II. y^2 = 225
y = 15, -15

10. I. 2x^2 – 20x + 48 = 0
II. y^2 – 15y + 56 = 0
X < Y
X > Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option A
I. 2x^2 – 12x – 8x + 48 = 0
2x = 12, 8
x = 6, 4
II. y^2 – 8y – 7y + 56 = 0
y = 8, 7