- A train , 240 m long crosses a man, walking along the line in opposite direction at the rate of 3 km/hr in 10 seconds. What is the speed of train ?
80 km/hr75 km/hr83.4 km/hr92.8 km/hr68 km/hrOption C

Let speed of train = x m/hr

240/(3 + x) 5/18 = 10

x = 83.4 km/hr - A boat takes a total of 24 hours to over 90 km in downstream and 90 km in upstream. If the ratio of speed of boat in sill water and speed of stream is 4 : 1, then find how much time is required to cover 120 km distance in down stream speed ?
8 hours14 hours20 hours15 hours12 hoursOption E

Let speed of boat in still water = 4x

speed of stream = x

downstream speed = 4x + x = 5x

upstream speed = 4x – x = 3x

90/5x + 90/3x = 24

x = 2

downstream speed = 5 * 2 = 10 km/hr

time = 120/10 = 12 hours - A equilateral tringle and a square have the same area. If the perimeter of the square is 88cm, then find what is area of the equilateral tringle ?
196 cm^2256 cm^2144 cm^2484 m^2125 cm^2Option D

Perimeter of square = 88cm

side of square = 88/4 = 22cm

area of square = 22 * 22 = 484 cm^2

area of tringle = 484 cm^2 - Pipe A can fill a tank in 15 hours and pipe B can fill the same tank in 60 hours, pipe C can empty in 10 hours. Pipe A and B are kept opened for 10 hours in the beginning and then pipe C is also opened, what is the time taken to empty the tank ?
60 hours40 hours30 hours25 hours50 hoursOption E

Capacity of the tank = 15, 60, 10 = 60 units

efficiency of pipe A = 60/15 = 4 units

efficiency of pipe B = 60/60 = 1

efficiency of pipe C = 60/10 = 6 units

tank filled in 1st 10 hours = (4 + 1) * 10 = 50 units

now, when all the pipe work together, 1 unit of water will out in every minute from tank.

50 units of water will be in 50 hours. - The ratio of age of A and B, 6 years ago was 3 : 4. Sum of the present age of B and C is 80 years. C is 12 years elder to A. Find the difference of age of B and C after 4 years ?
5 years6 years8 years4 years12 yearsOption D

6 years ago age of A = 3x

age of B = 4x

present age of A = 3x + 6

present age of B = 4x + 6

present age of C = 3x + 6 + 12 = 3x + 18

4x + 6 + 3x + 18 = 80

7x = 56

x = 8

age of B after 4 years = 4x + 6 + 4 = 42 years

age of C after 4 years = 3x + 18 + 4 = 46 years

difference = 46 – 42 = 4 years - Directions : What will be wrong number in the following wrong number series ?

120, 83, 113, 93, 105, 99, 1011138310512099Option D

The series is, (- 6 * 7), (+ 5 * 6), ( – 4 * 5), ( + 3 * 4), ( – 2 * 3), ( + 1 * 2) - 1898, 1870, 1657, 1608, 1096, 1015, 15
109610151898151870Option E

The series is ( – 5^2 ), (- 6^3), (- 7^2), (- 8^3 ), (- 9^2), (- 10^3) - 48, 84, 156, 300, 590, 1164
481563005901164Option D

The series is, ( * 2 – 12), ( * 2 – 12)… - 2, 6, 12, 24, 30, 42, 56
241230422Option A

The series is , (1^2 + 1), (2^2 + 2), (3^2 + 3)… - 1, 6, 24, 60, 120, 210
616024210Option B

The series is, (1^3 – 1), (2^3 – 2), (3^3 – 3), (4^3 – 4)…

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