# Mixed Quantitative Aptitude Questions Set 29

Quantitative Aptitude Questions IBPS RRB PO Clerk, SBI PO, IBPS PO, NIACL, NICL, RBI Grade B, BOI, Bank of Baroda and other competitive exams

1. Shravan and  Ronny  decided to go on a holiday  to B  on a particular day  from A. Shravan leaves for B  at 10 :00 am , at speed of 72km/hr. Ronny leaves for  B at 10:30 am same day  as Shravan left. At what speed should Ronny travel to catch up with Shravan in 4 hours?[in kmph] A) 86
B) 81
C) 78
D) 80
E) 82
Option B
Solution:
Distance  covered  by  Shravan  in  half  an  hour = 72*(1/2)= 36km
Relative  speed  of  Ronnny = (x-72) kmph
Therefore , 36 /(x-72) =4
X = 81 kmph

2. A started  a business.After 4 months from the start of the  business ,B and C joined. The  respective  ratio between the amounts invested by A, B and C  was  6:11:12 . If the C’s share in annual profit was Rs. 720 more  than A’s share  ,what was the total annual profit earned ?
A) Rs. 7580
B) Rs. 7680
C) Rs. 7860
D) Rs. 8680
E) Rs. 8210
Option B
Solution:
Ratio of the equivalent capitals of A,B and C for 1 month
= 6x * 12  : 11x * 8 : 12x *8
= 9 : 11 : 12
sum of the ratios =  9 + 11+ 12 = 32
If total amount profit be Rs. y
then,
12y/32    –     9y/32  = 720
=>   720 *32/3 = Rs. 7680
3. In a school  the number of boys and that  of  the girls are in the  respective ratio of 2:3 . If the number of boys is increased by 20% and that of girls is increased by 10% ,what will be the new ratio of number of boys to that of the girls ?
A) 14:5
B) 5:8
C) 21:6
D) 13:4
E) 8:11
Option E
Solution:
let the ratio of the no. of boys and girls be  2x and 3x respectively .
No. of boys after 20% increase  = 1.20 * 2x = 2.4x
No. of girls after 10% increase   =  1.10 * 3x = 3.3x
Required  ratio
= 2.4x/3.3x = 8 /11 = 8:11
4. The area of a square is 1024 sq.cm . What is the respective  ratio between the length  and the breadth  of a rectangle whose length  is twice the side of the square  and  breadth is 12 cm less than the side  of  the square  ?
A) 10:6
B) 12:8
C) 14:7
D) 16:5
E) 15:8
Option D
Solution:
side of the square = root(1024) = 32 cm
Length of the rectangle  = 2* 32 = 64
Breadth of the rectangle =  32 – 12 = 20 cm
Required ratio =  64 : 20  = 16 : 5
5. In a container  there  are  25 eggs  out  of  which  5 eggs  are  rotten . If  two eggs are chosen at  random, what  will  be  the  probability  that  at least  one  egg  is rotten ?     A) 10/30
B) 11/29
C) 12/20
D) 11/30
E) 10/29
Option D
Solution:
Total outcomes= 25c2= 300
Favourable outcomes = 20c1*5c1 +5c2 = 100 +10 = 110
Now, Probability of selecting at least one rotten egg = 110/300
= 11/30
6. Equal amounts of water were poured into three empty jars of different capacities, which made one jar 1/6 full, second jar 1/5 full and the third one 1/13 full. If the water in the jar with highest capacity is then poured into the jar with least capacity jar and then both are poured into the third (second least) capacity jar then the part of that jar filled with water is?
A) 3/2
B) 5/2
C) 1/4
D) 1/2
E) 3/4
Option D
Solution:
Let 1 liter water is poured in all the three jars.
1st filled 1/6th => Capacity = 6 liter.
Similarly 2nd capacity = 5 liters
third capacity = 13 litres
1 liter from largest jar (13 liter) is poured in smallest jar (5 liter)
=> water in smallest jar = 1+1 = 2 liter.
this is then poured into jar with capacity ( 6 litre )
total water in this jar now = 1+1+1 = 3litre
part filled 3/6 = ½
7. 8 litre are drawn from a cask of full wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16:65.how much wine di the cask hold originally?
A) 20
B) 24
C) 30
D) 16
E) 36
Option B
Solution:

1 – whole 4(16/65+16)
1 – 2/3=8
1/3=8
1=3*8=24 ltr.
8. A cricketer whose balling average is 24.85 run per wicket takes 5 wicket for 52 and thereby decrease his average by 0.85.the number of wickets taken by him before the last match was?
A) 60
B) 75
C) 90
D) 80
E) 85
Option D
Solution:

24.85 ………….52/5=10.4
…………….24
13.6………………0.85
2.72………………….17
17=5 => 1=5/17 => 2.72=5*2.72/17=80
9. 60 kg of a certain variety of rice at rs.32 per kg is mixed with 48 kg of another variety of rice and the mixture is sold at the average price of rs.28 per kg. If there is no profit or loss due to the new sale price,the price of secondary variety of rice per kg is?
A) 20
B) 24
C) 28
D) 23
E) 33
Option D
Solution:

32……….X
……..28
5…………..4
32*5+4*X / 9 = 28 => X=92/4=23
10. There are two alloys A and B. Alloy A contains zinc, copper and silver, as 60% 25% and 15% respectively, whereas alloy B also contains the same metals with percentages 60%, 15%, 25% respectively. If these two alloys are mixed such that the resultant will contain 18% silver, what is the ratio of these three metals in the resultant alloy?
A) 60:22:18
B) 15:27:19
C) 60:28:24
D) 18:41:36
E) 23 : 45 : 11
Option A
Solution:

the resultant alloy contains 9% silver so
A______B
15_______25
____ 18____
7________3
7:3
Then the resultant zinc percentage is
(7*60 + 3*60)/(7+3) = 60%.
So, copper percentage = 100 – (60 + 18) = 22
The ratio of these metals = 60 : 22 : 18

## 15 Thoughts to “Mixed Quantitative Aptitude Questions Set 29”

1. Jellyfish

7/10 ty az
Mam que no 7 option B not C
16/81=(1-8/k)^4
2/3=(1-8/k)
K=24

1. Shubhra

yes ans is 24 only

1. Jellyfish

Mam pls post high level puzzle &DI
Like SBI po main type

2. Ak\$hita \$inghal

Shubhi..pls give Di Like in sbi regularly… Pls ?

2. Jellyfish

Que no 8 explain pls
How we got 17=5…1=5/17
2.72*5*2.72/17????

1. Shubhra

5 wicket for 52

1. Jellyfish

Thx mam

3. Jellyfish

Alternate method que no 8
24.85x+52/x+5=24
24.85x+52=24x+120
0.85x=68
X=80

1. thinker

I am little confuse in this question plz help me.m esi methed se solve krti hun jisse aapne kiya bt ye question thoda alg h so confuse Ho gyi.

4. _/_

ty 🙂

5. ครђ

Thanks Ma’am :))

6. jaga

q 10 samjh mai nahi arha mujhe.

1. cActi?

kahan samjh nahi aa raha h ?

1. jaga

samjh gaya ab,.thank u

2. cActi?

A______B
15(Alloy A ka silver )_______25(Alloy B ka silver )
____ 18(resultant)____
7________3
7:3
The amount of zinc is same in both the alloy A and B :
Then the resultant zinc percentage is
(7*60 + 3*60)/(7+3) = 60%.
So, copper percentage = 100 – (60 + 18) = 22
The ratio of these metals = 60 : 22 : 18