Quant Questions Bank PO

Mixed Quantitative Aptitude Questions Set 38

46 Comments / Banking Quiz, Quantitative Aptitude / By

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, NIACL, NICL, RBI Grade B/Assistant, BOI, Bank of Baroda and other competitive exams

  1. A man gets simple interest of 1,000 on a certain principal at the rate of 5 percent p.a. in 4 years . What compound interest will the man get on twice the principal in two years at the same rate ?
    A) 1025
    B) 1550
    C) 2050
    D) 1475
    E) 1010
    View Answer
      Option  A
    Solution:
    Principal(P) = (SI *100)/(Time *Rate ) = (1000*100)/(4*5)
    = 5000
    Now, P= 10000
    Therefore ,
    CI = P[(105/100)^2 – 1 ] = Rs.1025
  2. Train A crosses a pole and platform in 18 seconds and 39 seconds respectively. The length of platform is 157.5 metre . What will be the length of train B if it is equal to the sum of half of the length train A and twice the length of the platform?
    A) 225.4m
    B) 400.5m
    C) 382.5m
    D) 425.7m
    E) 325.5m
    View Answer
      Option C
    Solution:
    Let the length of train A = x metre
    Therefore,
    (x/18) = (x+157.5)/39
    => x= 135 metre
    Length of train B = [(135/2) + 2*157.5] m = 382.5 m
  3. Minal have borrowed some money from her friend at the rate of  5% p.a. for the first three years, 15% p.a.  for the next five years and 15% p.a. for the beyond 10years . If the total interest paid  by him at the end of  18 years is Rs. 90,000, how much money did she borrow?
    A) Rs.45,000
    B) Rs.50,000
    C) Rs.40,500
    D) Rs.37,500
    E) Rs.22,500
    View Answer
      Option D
    Solution:
    Let the sum be Rs.x
    (x*5*3)/100 + (x*5*15)/100 + (x*15*10)/100 = 90,000
    =>x = 37500
  4. Tarun  got 30% of the maximum marks in the examination and failed by 10marks. However, Vimal who took the same examination got 40% of the total  marks and got 15 more than the passing marks in the examination. What were the passing marks in the examination?
    A) 75
    B) 65
    C)72
    D) 90
    E) 85
    View Answer
      Option E
    Solution:
    Let the maximum marks be x .
    Therefore,
    x*30% + 10 = x*40% – 15
    => x = 250
    Passing marks = 250*(30/100) + 10 = 85
  5. A person crosses a stationary bus in 18 seconds. The same bus crosses a pole in 4 seconds. What is the respective ratio between the speed of the bus and the speed of the man?
    A) 9:2
    B) 8:5
    C) 7:3
    D) 5:8
    E) 8:7
    View Answer
      Option A
    Solution:
    Let length be x.
    Then ,
    (x/4):(x/18) = 9:2
  6. 16 children are to be divided  into two groups A and B consisting of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children  is 76. What is the average percent marks of children of group B?
    A) 65(1/4)
    B) 77(2/3)
    C) 77(1/5)
    D) 67(1/2)
    E) 71(1/2)
    View Answer
      Option B
    Solution:
    A————B
    75———-y
    ——76
    (10/6)—-(6/6)
    Therefore,
    y = 76+(10/6) = 77(2/3)
  7. The difference between the simple interest received from two different sources on Rs. 1500 for 3 years in Rs. 13.50. What is the difference between their rates of interest?
    A) 0.5%
    B) 0.6%
    C) 0.3%
    D) 0.8%
    E) 0.7%
    View Answer
      Option C
    Solution:
    Here, the principal and time are same but rates are different.
    Hence, we get difference in simple interest due to difference in the rates.
    Diff. in 3 yrs. = 13.50
    Diff. in 1 yr. = (13.50/3) = Rs.4.50
    Diff. between rates = (4.50/1500)*100 = 0.3%
  8. The  area of a circular field is equal to the area of a rectangular field. The ratio of the length and the breadth of the rectangular field is 14:11 respectively and perimeter is 100metres . What is the diameter of the circular field?
    A) 18m
    B) 22m
    C) 30m
    D) 28m
    E) 33m
    View Answer
      Option D
    Solution:
    Let the length and breadth of the rectangular field be 14x and 11x metres resp.
    Therefore,
    2(14x + 11x) = 100
    => 50x 100
    => x = 2
    Area of rectangular field = 28*22 = 616m^2
    Area of circular field = 616 m^2
    pi*r*r = 616
    => r = sq. root(616/pi)
    => r = 14m
    Diameter = 28m
  9. From a well – shuffled pack of 52 playing cards , one card is drawn at random. What is the probability that the card drawn will be a black king?
    A) 1/26
    B) 2/13
    C)1/13
    D) 3/26
    E) 3/13
    View Answer
      Option A
    Solution:
    Required probability = (2C1)/52C1 = 2/52 = 1/26
  10. The number of ways in which 6 men and 5 women can dine at a round table, if no two women are to sit together . Find the number of arrangements.
    A) 8!*5!
    B) 4!*3!
    C) 6!*8!
    D) 6!*5!
    E) 5!*4!
    View Answer
      Option D
    Solution:
    No. of ways to fix the men in alternate positions = (6-1)! = 5!
    In out of six positions 5 women can be seated in 6P5 = 6!
    Required ways = 6!*5!

Click here for Quantitative Aptitude Questions

 

46 thoughts on “Mixed Quantitative Aptitude Questions Set 38”

  5. %%%

    mam in 10 ) ques….we subtract 1 i.e. (6-1)=5..in boys …why not from girls like this 6! for boys & (5-1)=4! for girls

  6. Diya

    in ques 3rd…….
    Let the sum be Rs.x

    (x*5*3)/100 + (x*5*15)/100 + (x*15*10)/100 = 90,000

    =>x = 37500
    2nd part (x*5*15)/100 …….=====>> x*5*10 hoga na?

          4. ครђ

            Start from man ,the sequence will be –

            M,W,M,W,M,W,M,W,M,W,M

            so no. of men can be arranged by 6!
            & no. of women can be arranged by 5!
            Required ways = 6!*5!

          6. $קгค๔єєק$

            see here..:)
            no of men arranged in circular table =(6-1)! =5!
            now no of women arranged in 6 places =6c5 =6
            now women aranged themselves =5!
            => t =6*5!*5! =6!*5!=86400 = option d

    2. $קгค๔єєק$

      this is also ryt but if u use combination instead of permutation then there is a std in combination for circular arrangement u can have easiness other wise for permutation u have to assume it as linear arrangemnt and solve in both case same ans u will get..:)

    1. $קгค๔єєק$

      by alligation
      75————x

      ——–76—–
      x-76———1
      now
      (x-76)/1 =5/3 => x =77(2/3) =77.667

  14. think tank

    Plz koi solve kro.2pipes can half the tank in 1.2hours.the tank was initially empty.Pipe B was kept open for half the time required by pipe A to fill the tank by itself. Then pipe A was kept open for as much time as was required by pipe B to fill 1/3 of the tank by itself.The least time in which any of the pipe can fill the bank.

    2. ADK

      1/a + 1/b == 5/12……1
      .
      a/2b + b/3a == 5/6
      3a^2 + 2b^2 – 5ab == 0
      a==b , a== 2b/3
      .
      For a==b we get b == 4.8 hrs
      for a==2b/3 we get b == 4hrs

  15. think tank

    A can fill the tank in 4 hours and B can fill 6 hours while C can outlet in 6 hours.A man open 2pipes to fill the tank and set a alarm to open third outlet tank when tank will half be filled.but he mistakely set alarm when tank will filled 3/4. What will be the difference between two times to fill the tank

    2. ADK

      let total work == 12 lit
      …………………….A………..B………..C
      work done/hr….3…………2………..-2
      Case 1
      6L filled by A & B in 6/5 == 1.2 hrs
      remaining 6L in 6/(3+2-2)==2hrs……total time == 3.2hrs
      .
      Case 2
      9 L filled by A&B in 9/5==1.8hrs
      remaining 3 lit in 3/3==1hrs…..total == 2.8
      Difference== 0.4hrs or 24mins

  17. merchant services representative

    I have viewed that clever real estate agents all over the place are Advertising. They are noticing that it’s in addition to placing a poster in the front yard. It’s really pertaining to building relationships with these suppliers who someday will become consumers. So, after you give your time and energy to assisting these vendors go it alone — the “Law connected with Reciprocity” kicks in. Good blog post.

Comments are closed.