Mixed Quantitative Aptitude Questions Set 43

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, NIACL, NICL, RBI Grade B/Assistant, BOI, Bank of Baroda and other competitive exams

  1. Three pipes A, B and C can fill a cistern in 6 hours . After working together for 2 hours, C is closed and A and B fills it in 7 hours more .Find the time taken by C alone to fill the cistern.
    A) 10 hours
    B) 17 hours
    C) 14 hours
    D) 8 hours
    E) 11 hours
    View Answer
      Option C
    Solution:
    A + B + C = 6 hours =  (1/6)* 2 (for 2 days ) = (1/3) work
    Remaining = 1 – (1/3) = (2/3) work
    A + B  = (2/3) work —– 7 hours
    A + B = 7*(3/2) = (21/2) hour
    Remaining time taken by C alone = (1/6) – (2/21) = 42/3 = 14 hours
  2. Rs.12600 is invested in 3 parts in such a way that the S.I. on first part at 2% p.a. for 3 years is equal to S.I. on second part at 3% p.a. for 4 years is equal to S.I. on third part at the rate of 4% p.a. for 5 years are equal . Find the S.I. on second part.
    A) 3200
    B) 4890
    C)4000
    D) 3550
    E) 3500,
    View Answer
      Option  E
    Solution:
    A/ B = 6/3  and  B/C = 6/10
    A:B:C = 10:5:3
    For A = (12600/18)*10 = 7000
    For B = (12600/18)*5 = 3500
    For C = (12600/18)*3 = 2100
  3. The population of  a town is 5000. Suppose the number of males increase by 5% and the females by 10%,then the population becomes 6000. Find the number of males in the town.
    A) 2000
    B) 1200
    C) 9000
    D) 7000
    E) 3000
    View Answer
      Option A
    Solution:
    Average % increase = (1000/5000)*100 = 20%
    Male  —————- Female
    5%———————-10%
    ————–20%
    10%——————–15%
    Therefore , Male : Female = 2:3
    Population of males = (5000/5)*2 = 2000
  4. A reduction of 10% in the price of sugar enables a person to obtain 15 kg more for Rs. 300. What is the reduction price per kg? Find also the original price per kg.
    A) Rs.(7/5)
    B) Rs.(6/4)
    C) Rs. (15/7)
    D) Rs. (20/9)
    E) Rs.(17/5)
    View Answer
      Option D
    Solution:
    The fall in price , there is a saving of 10% on Rs. 300 i.e. Rs.30
    For Rs.30 ——– 15 kg of sugar
    Reduced price per kg = Rs.30 / 15 = Rs.2
    Original Price = 2 *(100/100-10) = Rs. (20/9)
  5. The profit % of A and B are same on selling an articles at Rs. 2400 each but A calculates his profit on the S.P. while B on its C.P. this profit is equal to 23% each. What is the difference between their profits ?
    A) 80
    B) 103
    C) 112
    D) 133
    E) 145
    View Answer
      Option B
    Solution:
    SP1 = (123/100)*CP1
    => 2400 = (123/100)*CP1
    => CP1 = 1951
    CP2 = (123/100)*SP2 = 2952
    CP1 + CP2 = 4903
    Total SP =4800, Profit = 103
  6. After covering a distance  of 30km with a uniform speed there is some defect in a train engine and therefore , its speed is reduced to (4/5) of its original speed . Consequently, the train reaches its destination late by 45 mins. Had it happened after covering 18 km more, the train would have reached 9 minutes earlier. Find the speed of the train.
    A) 45km/hr.
    B) 35km/hr.
    C) 30km/hr.
    D) 50km/hr.
    E) 58km/hr.
    View Answer
      Option C
    Solution:
    Diff. of speed = 18 km
    18/(4/5)S -18/S = 9/60
    => S = 30km/hr.
  7. A train running at a speed of 25km/hr takes 18 sec  to pass a railway platform and it takes 13.5 sec to pass a man who is running at a speed of 5 km/hr in the same direction. Find the length of the train and length of the platform.
    A) 30km
    B)50km
    C) 33km
    D)45km
    E) 40km
    View Answer
      Option B
    Solution:
    Dist. =  length + platform’s length `
    => 75 + length = 18*(25/18)*5
    => length = 50 km
  8. A is thrice as efficient as B. A started the work and work for 6 days tehn it is replaced by B . B then worked for 9 days and they together complete 50% of the work then B alone can do the whole work in how many days.
    A) 48 days
    B) 52 days
    C) 60 days
    D) 65 days
    E) 54 days
    View Answer
      Option E
    Solution:
    A : B = 3 : 1
    A : B = 6 : 9 = 6*3 : 9*1 = 27 unit
    50% = 27
    100% = 54
    Therefore, B alone take = 54/1 = 54 days

  9. A , B and C can complete a piece of work in 10, 12 and and 15 days resp. A left the work 5 days before the completion of the work B left two days after A had left . Find the number of days required to complete the work.
    A) 10 days
    B) 7 days
    C) 12 days
    D) 18 days
    E) 15 days
    View Answer
      Option B
    Solution:
    10,12,15==== 60 ==== 6x , 5x ,4x
    (x-5)/10 + (x-3)/12 + x/15 = 1
    => x = 7 days
  10. The average age of a family of 6 members is 22 years. If the age of the youngest member be 7 years. What was the average age of family at the birth of the youngest members?
    A) 14 years
    B) 20 years
    C) 15 years
    D) 18 years
    E) 11 years
    View Answer
      Option D
    Solution:
    6 * 22 = 132 , 6 * 7 = 42
    132 – 42 = 90/5 = 18 years

 

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14 Thoughts to “Mixed Quantitative Aptitude Questions Set 43”

  1. _/_

    ty nice qs
    awesome !!

  2. Happy Singh

    check question 3

    1. Banya

      now checked ..

  3. Pablo Escobar

    Didn’t get the third one

    1. Banya

      now its updated..

      1. Pablo Escobar

        10%——————–15%
        I didn’t understand this line

  4. Pablo Escobar

    In 10 why did you multiply 7 by 6 . it’s average age???

    1. Banya

      sum of age of 6 member = 22*6 = 132
      sum of age of 5 member excluding younger one = 132-7 = 125
      average age of 5 member = 125/5 = 25 , average age at the time of birth = 25-7 = 18
      now its ok ?

      1. Pablo Escobar

        Yeah thanks

  5. doli

    in qs 3 it will 2000 in the place of 1000

    1. deepali

      2nd m ration kaha ase ae?

    2. Banya

      now its is ok .. ty 🙂

  6. Mera bhi din ayega :)))

    ty

  7. Jahnavi

    explain 5th ques plz

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