# Mixed Reasoning Questions for Upcoming Exams – Set 82

1. If it is possible to make a meaningful word, using the 3rd, 4th, 7th and 9th letters of the word ‘MELLIFLUOUS’, then what is the second letter of the word formed? If no such word be formed, mark the answer as ‘Y’. If more than one word can be formed mark the answer as ‘X’.
L
O
J
X
Y
Option B
The 3rd, 4th, 7th and 9th letters of the word ‘MELLIFLUOUS’ are L, L, L and O. The word can be formed using these letters are LOLL.

2. If it is possible to make a meaningful word, using the 2nd, 3rd, 7th and 8th letters of the word ‘SEGREGATE’, then what is the last letter of the word formed? If no such word be formed, mark the answer as ‘Y’. If more than one word can be formed mark the answer as ‘X’.
E
C
H
X
Y
Option A
The 2nd, 3rd, 7th and 8th letters of the word ‘SEGREGATE’ are E, G, A and T. The word can be formed using these letters are GATE.

3. If it is possible to make a meaningful word, using the 3rd, 4th, 6th and 8th letters of the word ‘ACQUIESCENT’, then what is the last letter of the word formed? If no such word be formed, mark the answer as ‘Y’. If more than one word can be formed mark the answer as ‘X’.
B
E
G
X
Y
Option E
The 3rd, 4th, 6th and 8th letters of the word ‘ACQUIESCENT’ are Q, U, E and C. No word can be formed from these letters.

4. How many such digit pairs are there in the number ‘691683654’ which have as many digits between them in the number as they have between them in the natural number system?
Eight
Nine
Four
Six
Seven
Option E
There are seven such pairs: 3-5, 4-5, 4-6, 4-8, 5-6, 5-8, 6-8

5. How many such pair of letters are there in the word ‘SACRIFICE’ which have as many letters between them in the word as they have between them in the English alphabet?
Four
Three
Two
One
Zero
Option C
There are two such pairs: C-F, E-I

6. How many such pair of letters are there in the word ‘ABOMINATION’ which have as many letters between them in the word as they have between them in the English alphabet?
Seven
Four
Six
Five
Eight
Option C
There are six pairs of letters: A-B, A-I, B-I, O-I, O-T, O-N

7. How many such pair of letters are there in the word ‘ABATEMENT’ which have as many letters between them in the word as they have between them in the English alphabet?
Four
Three
Six
Five
Two
Option D
Five pairs of letters are there: A-B, A-E, B-E, A-E, A-B

8. There are 56 students in a class and the ratio of Boys and Girls are 5:2. Ram’s rank is 18th from the top and there are only 10 boys sitting in between Ram and Shalu, who is a girl and sitting behind Ram. Then how many girls are sitting ahead of Shalu?
14
8
7
Cannot be determined
None of these
Option D
There are 56 students in the class. Boys = 56 × 2/7 = 16 Girls = 56 × 5/7 = 40 As we don’t know the exact the number of girls sitting ahead or behind Shalu, so cannot be determined.

9. If it is possible to make only one meaningful English word with the third, the fifth, the seventh and the ninth letters of the word ADVENTUROUS, which of the following will be the third letter of that word? If no such word can be made give ‘X’ as the answer and if more than one such word can be made give ‘Y’ as the answer.
N
O
V
X
Y
Option D
Given Word: A D V E N T U R O U S 1st letter = V; 5th letter = N; 7th letter = U; 8th letter = O Letters given: V N U O No meaningful word can be formed by using the letters V N U O.

10. If it is possible to make a meaningful word, using the 3rd, 4th, 6th and 8th letters of the word ‘ATMOSPHERE’, then what is the last letter of the word formed? If no such word be formed, mark the answer as ‘Y’. If more than one word can be formed mark the answer as ‘X’.
M
E
P
X
Y
Option D
The 3rd, 4th, 6th and 8th letters of the word ‘ATMOSPHERE’ are M, O, P and E. Three words are formed by these letters – MOPE, POEM and POME.