# Quantitative Aptitude: Simple/Compound Interest Set 19

1. The difference between simple interest and compound interest on a sum of rs.4400 for 2years is rs.44. What is the rate of interest per annum?
10%
15%
12%
18%
20%
Option A
Solution: Let the rate of interest be r% per annum.
ATQ,
4400×r^2/(100×100)=44
r= 10%

2. If the sum of money gets tripled at a certain rate of simple interest in three years, in how many years it will become 9 times of it self with same rate of interest?
15 years
9 years
27 years
10 years
12 years
Option E
Solution: Let the amount be P and rate of interest be R% per annum.
ATQ,
(3P-P)=P×R/100×3
R=200/3
Let us the assume that in t years amount will become 18 times itself .
ATQ,
(9P-P)=P×200/3×t/100
t=12 years

3. Difference between the simple interest received in 1.5 years at 24% per annum and that received in 3.5 years at 12% per annum on the same sum is Rs.1440, then find the sum ?
22000
30000
15000
24000
26000
Option D
solution: 100x*3.5*12/100 – 100X*1.5*24/100=1440
42x-36x=1440
x=240
Required sum = 100x
=100*240=24000

4. A lent of Rs.3000 to B for 2 years and Rs.1000 to C for 4 years on simple interest at the same rate of interest and received Rs.500 in all from both of them as interest. The rate of interest per annum is ,
10%
8%
6%
9%
5%
Option E
solution: 3000*r/100*2+1000*r/100*4=500
60r+40r=500
r=5%

5. The interest earned on a certain sum in 2years at 20% pa at CI is twice the interest earned on Rs.2200 for 2years at 10% SI. Find the value of sum.
3000
2000
2250
1280
1600
Option B
Solutions: p(1+r/100)^2-p=2*2200*10*2/100=880
p36/25-p=880
p=2000

6. Ram divided his total amount between his brother and sister in the ratio 5:3. His brother invested his share on CI for two years at the rate of 10% and received the interest rs.480 less than his sister ,who invested her share on SI for three years at the rate of 15%. find the share of individual Ram’s brother and sister respectively.
8000,4800
6400,5000
4800,3500
5000,3000
none of these
Option A
Solution: Let total savings of Ram is rs.8x
share of his brother =rs. 5x
and share of sister =rs.3x
CI received by his brother = 5p [(1+10/100)^2-1]=105p/100
ATQ, 3p*15/100*3-105p/100=480
135p/100-105p/100=480
30p=48000
p=rs.1600
Ram’s brother share=1600*5=rs.8000
Ram’s sister share=1600*3=rs.4800

7. Rajat invested rs.P on CI of the rate of 10% for 2 years and suman invested rs.Q on SI at the rate of 20% for 3 years and ratio of interest got by Rajat in 2nd year and total interest got by Suman is 1:3. If Rahul invested rs (P+Q) on SI for 2 years on 12% p.a. and gets rs. 372 as interest. Find amount of Rajat and Suman invested individually.
1000,550
1600,800
1200,900
1500,600
none of this
Option
Solution: 2nd year CI on 10% =10+10*10/100=11%
total 3 year SI at 20%=20*3=60%
According to questions , 11P/60Q=1/3
P=1/3*60/11=20Q/11
also given, (20Q/11+Q)*12/100*2=372
31Q/11*24/100 = 372
Q =372*1100/31*24
Q=rs. 550
P=20*550/11 =rs.1000

8. Srikatnta invested a sum of rs.20,000 in a scheme offering simple interest at 30% p.a. after 2 years, he again invested total money he got from scheme in share market of 80 per share, after 3 month he sold all his share at rs. 100 per share. Find his total profit.
8000
10,000
6000
9000
none of this
Option A
Solution: Amount = 20000+20,000*30*2/100=rs.32,000
Units of share parched =32000/80=400
selling price of share =400*100=40,000
Profit = 40,000-32000=8000

9. The simple interest accrued on a certain sum is rs. 5000 in 4 years at the rate of 10 p.a. What would be the compound interest accrued on the same sum at the same rate in years ?
3100
2625
1200
1400
none of this
Option B
solution: Let the sum be rs.x
x*10/100*4=5000
x=12500
CI for 2years @ 10%=10+10*10*10/100
=21%
21% of 12500 =2625

10. A invested total of rs.80,000 in two schemes M and N for 2 years. In scheme M he invested at 18% p.a. at SI and in scheme N he invested at 20% p.a at CI compounded annually. If SI received is rs.4800 more than CI, then find amount invested by him in scheme N.
50,000
30,000
40,000
20,000
none of these
Option B
solutions: Let amount invested in scheme N =x
and in scheme M =80000-x
rate of interest of scheme N=20+20+20*20/100=44%
[(80000-x)18*2/100]-44x/100=4800
2880000-36x/100-44x/100=4800
80x=2400000
x=30000

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