The difference between simple interest and compound interest on a sum of rs.4400 for 2years is rs.44. What is the rate of interest per annum?
Option A Solution: Let the rate of interest be r% per annum. ATQ, 4400×r^2/(100×100)=44 r= 10%
If the sum of money gets tripled at a certain rate of simple interest in three years, in how many years it will become 9 times of it self with same rate of interest?
Option E Solution: Let the amount be P and rate of interest be R% per annum. ATQ, (3P-P)=P×R/100×3 R=200/3 Let us the assume that in t years amount will become 18 times itself . ATQ, (9P-P)=P×200/3×t/100 t=12 years
Difference between the simple interest received in 1.5 years at 24% per annum and that received in 3.5 years at 12% per annum on the same sum is Rs.1440, then find the sum ?
Option D solution: 100x*3.5*12/100 – 100X*1.5*24/100=1440 42x-36x=1440 x=240 Required sum = 100x =100*240=24000
A lent of Rs.3000 to B for 2 years and Rs.1000 to C for 4 years on simple interest at the same rate of interest and received Rs.500 in all from both of them as interest. The rate of interest per annum is ,
Option E solution: 3000*r/100*2+1000*r/100*4=500 60r+40r=500 r=5%
The interest earned on a certain sum in 2years at 20% pa at CI is twice the interest earned on Rs.2200 for 2years at 10% SI. Find the value of sum.
Option B Solutions: p(1+r/100)^2-p=2*2200*10*2/100=880 p36/25-p=880 p=2000
Ram divided his total amount between his brother and sister in the ratio 5:3. His brother invested his share on CI for two years at the rate of 10% and received the interest rs.480 less than his sister ,who invested her share on SI for three years at the rate of 15%. find the share of individual Ram’s brother and sister respectively.
none of these
Option A Solution: Let total savings of Ram is rs.8x share of his brother =rs. 5x and share of sister =rs.3x CI received by his brother = 5p [(1+10/100)^2-1]=105p/100 ATQ, 3p*15/100*3-105p/100=480 135p/100-105p/100=480 30p=48000 p=rs.1600 Ram’s brother share=1600*5=rs.8000 Ram’s sister share=1600*3=rs.4800
Rajat invested rs.P on CI of the rate of 10% for 2 years and suman invested rs.Q on SI at the rate of 20% for 3 years and ratio of interest got by Rajat in 2nd year and total interest got by Suman is 1:3. If Rahul invested rs (P+Q) on SI for 2 years on 12% p.a. and gets rs. 372 as interest. Find amount of Rajat and Suman invested individually.
none of this
Option Solution: 2nd year CI on 10% =10+10*10/100=11% total 3 year SI at 20%=20*3=60% According to questions , 11P/60Q=1/3 P=1/3*60/11=20Q/11 also given, (20Q/11+Q)*12/100*2=372 31Q/11*24/100 = 372 Q =372*1100/31*24 Q=rs. 550 P=20*550/11 =rs.1000
Srikatnta invested a sum of rs.20,000 in a scheme offering simple interest at 30% p.a. after 2 years, he again invested total money he got from scheme in share market of 80 per share, after 3 month he sold all his share at rs. 100 per share. Find his total profit.
none of this
Option A Solution: Amount = 20000+20,000*30*2/100=rs.32,000 Units of share parched =32000/80=400 selling price of share =400*100=40,000 Profit = 40,000-32000=8000
The simple interest accrued on a certain sum is rs. 5000 in 4 years at the rate of 10 p.a. What would be the compound interest accrued on the same sum at the same rate in years ?
none of this
Option B solution: Let the sum be rs.x x*10/100*4=5000 x=12500 CI for 2years @ 10%=10+10*10*10/100 =21% 21% of 12500 =2625
A invested total of rs.80,000 in two schemes M and N for 2 years. In scheme M he invested at 18% p.a. at SI and in scheme N he invested at 20% p.a at CI compounded annually. If SI received is rs.4800 more than CI, then find amount invested by him in scheme N.
none of these
Option B solutions: Let amount invested in scheme N =x and in scheme M =80000-x rate of interest of scheme N=20+20+20*20/100=44% [(80000-x)18*2/100]-44x/100=4800 2880000-36x/100-44x/100=4800 80x=2400000 x=30000