Quantitative Aptitude: Quadratic Equations Set 24

Shubhra

Quadratic Equations Practice Sets for IBPS PO, NICL, NIACL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.

Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

  1. I. 5x2  – 18x + 9 =0
    II. 3y2 + 5y – 2 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option A
    Solution:
    5x2   – 18x + 9  = 0
    => 5x2  – 15x – 3x  + 9 =0
    => (5x – 3 )(x-3 )= 0
    => x=  3/ 5 or  x= 3
     3y2 + 5y – 2 = 0
    => 3y2  + 6y – y -2 = 0
    => (3y-1)(y + 2) = 0
    => y = 1/3  or  -2
  2. I. √x  – √6 / √x = 0
    II. y3 – 63/2  = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option E
    Solution: 
    √x  –   √6 / √x = 0
    x – √6 = 0
    x = √6
    y3   – 6 (3/2 )  = 0
    =>y3  = (√6)3
    => y = √6
  3. I. (625)1/4x + √1225  = 155
    II. √196y + 13  = 279
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option A
    Solution: 
    5x + 35 = 155
    => 5x = 155 – 35
    => x = 120/ 5 = 24√196 y  + 13 = 279
    => 14y = 279 -13
    => y = 266/14 =19
  4. I. 3x2 – 17x + 24 =0
    II. 4y2  – 15y + 14 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option A
    Solution: 
    3x2  -17x  + 24 =0
    => 3x2 – 9x  – 8x +24 = 0
    => (3x- 8)(x-3) = 0
    =>  x=  8/3 or 3
    4y2  – 15y + 14 = 0
    => 4y2  – 8y -7y +14 = 0
    => (4y -7 )(y-2)=0
    => y = 7 /4 or  2
  5. I. x2 – 2x – √5 x + 2√5 = 0
    II. y2 – √3 y – √2 y + √6 =0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option A
    Solution: 
    x2  – 2x- √5 x + 2√5 = 0
    => x(x-2 ) – √5 (x-2 )= 0
    => (x-2)(x-√5)=0
    => x= 2 0r √5
    y2  – √3 y  – √2 y + √6 =0
    => y(y-√3) – √2(y – √3) = 0
    => (y – √2)(y- √3) =0
    => y = √2 or √3
  6. I. 5x2 – 23x + 12 = 0,
    II. 5y2 – 28y + 15 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
     Option E
    Solution: 
    x = 3/5, 4
    y = 3/5, 5
  7. I. 6x2 + 5x – 6 = 0,
    II. 3y2 – 11y + 6 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option D
    Solution:
    x = 2/3, 3
    y = -3/2, 2/3
  8. I. 3x2 – 5x – 12 = 0,
    II. 2y2 – 17y + 36 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option B
    Solution:
    x = -4/3, 3
    y = 4, 9/2
  9. I. 8x2 – (4 + 4√3)x + 2√3 = 0,
    II. 3y2 – (4 + 3√3)y + 4√3 = 0
    A) x > y
    B) x < y
    C) x ≥ y
    D) x ≤ y
    E) x = y or relationship cannot be determined
    View Answer
    Option B
    Solution:
    8x2 – (4 + 4√3)x + 2√3 = 0
    (8x2 – 4x) – (4√3x – 2√3) = 0
    4x (2x- 1) – 2√3 (2x – 1) = 0,
    So x = 1/2 (0.5), 2√3/4 (0.87)
    3y2 – (4 + 3√3)y + 4√3 = 0
    (3y2 – 4y) – (3√3y – 4√3) = 0
    y (3y – 4) – √3 (3y – 4) = 0
    So, y = √3 (1.732), 4/3
    put on number line
    0.5………..0.87……..4/3………1.732
  10. I. x2 + (4 + 2√2)x + 8√2 = 0
    II. 3y2 – (3 + √3)y + √3 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option B
    Solution:
    x2 + (4 + 2√2)x + 8√2 = 0
    (x2 + 4x) + (2√2x + 8√2) = 0
    x (x + 4) + 2√2 (x + 4) = 0
    So x = -4, -2√2 (-2.8) 
    3y2 – (3 + √3)y + √3 = 0
    (3y2 – 3y) – (√3y – √3) = 0
    3y (y – 1) – √3 (y – 1) = 0
    So y = 1, √3/3 (0.57)

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29 Thoughts to “Quantitative Aptitude: Quadratic Equations Set 24”

  1. Pawan
    July 17, 2017 at 5:46 pm

    please check ques 1 its coming option E

    1. Shubhra
      July 17, 2017 at 6:41 pm

      values of x and y ?

      1. thinker
        July 17, 2017 at 8:16 pm

        Mam question 6me ,x=3/5,4 and y=3/5,5 to eska answer no relation kese Hua .Y bda ya equal hona chahiye.ye question mujhse hmesha wrong ho hate h.why no relation?

        1. ครђ
          July 18, 2017 at 1:19 am

          Value of X= 3/5 , 4
          Value of Y= 3/5 , 5
          Compare 4 & 3/5 we get x>y …4 and 5 x<y

          1. thinker
            July 18, 2017 at 11:57 am

            Thanks

      2. Pawan
        July 17, 2017 at 8:39 pm

        value of x is same but value of y coming 2/3,-1 please check my eq can i make it as 3y^2+3y+2y-2=0

        1. ครђ
          July 18, 2017 at 1:28 am

          Value of Y = -6/3 & 1/3
          = -2 ,0.3
          Value of X = 3, 0.6
          So X>Y option A 🙂

  2. Pawan
    July 17, 2017 at 5:52 pm

    also check ques 5
    ans should b option (a)

  3. Barish!!
    July 17, 2017 at 6:31 pm

    thanku mam /

  4. Jellyfish
    July 17, 2017 at 6:55 pm

    8/10 Thx az
    Queno 5 option should be A
    Que 6 2nd statement 5y^2-28y+15=0 he chahiye

  5. thinker
    July 17, 2017 at 8:12 pm

    9/10

  6. Sachin Shukla
    July 17, 2017 at 8:50 pm

    10/10 ty:)))

  7. Sindabad
    July 18, 2017 at 4:14 am

    @s@Shubhra_AspirantsZone:disqus sir, are u same subhra sir from Affairscloud??

    1. Shubhra
      July 18, 2017 at 7:52 am

      Yes the same

      And i am female 🙂

      1. Sindabad
        July 18, 2017 at 8:53 am

        Sorry, good morning ma’am

  8. swati
    July 18, 2017 at 11:04 am

    thank you team 10/10 easy….provide more…….sets like this……

  9. jaga
    July 18, 2017 at 12:09 pm

    thank u mam

  10. anurag agarwal
    July 18, 2017 at 2:50 pm

    Unable to solve question 5.9.10
    How to solve it

    1. Shubhra
      July 18, 2017 at 9:31 pm

      What doubt ?
      See 9th solution.
      U have to take without root values together
      And with root s values together
      And then take common like in 2nd step in 9th.

      See again. Ask if doubt

  11. Ayushi
    July 31, 2017 at 11:43 am

    thankuu mam 🙂

  12. Chotu D(mind) !! {NONSENSE}
    August 29, 2017 at 9:58 pm

    done

  13. वैम्पायर हंटर
    August 30, 2017 at 5:31 pm

    6th ka sign chk kro

    1. Shubhra
      August 31, 2017 at 1:39 am

      6th is E
      doubt ?

      1. वैम्पायर हंटर
        August 31, 2017 at 8:54 am

        Wo 6th ke 2nd equtn me sign minus minus hh
        To fr value dono plus me likh rkhe ho ye bol rha hun…

        1. Shubhra
          August 31, 2017 at 12:23 pm

          ok ok

          yes +

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