Quantitative Aptitude: Data Interpretation Questions Set 47

Directions (1-5): A bar graph and a table are given.The bar graph  shows the data regarding the number of boys and girls studying in 6^th class of 6 different schools. The table shows the respective ratio of passed boys/failed boys and passed girls /failed girls in 6 different schools.

1. What is the approximate average number of failed boys in class 6^th of all the 6 schools together ?
   A) 50
   B) 78
   C) 56
   D) 48
   E) 45
   
   View Answer

     Option C
   Solution:
   Number of failed boys in A = 240*(1/4)  = 60
   Number of failed boys in B = 280*(3/14) = 60
   Number of failed boys in C = 400*(4/25)  = 64
   Number of failed boys in D = 320*(1/16) = 20
   Number of failed boys in E = 410*(4/41) = 40
   Number of failed boys in F = 500*(9/50) = 90
   Total number of failed boys = (60+60+64+20+40+90) = 334
   Required avg. = 334/6 = 56(approx.)
   
2. What is the difference between the total number of passed boys and passed girls in all 6 schools together ?
   A) 285
   B) 231
   C) 200
   D) 250
   E) 220
   
   View Answer

     Option  B
   Solution:
   Number of passed boys in A  = 240*(3/4) = 180
   Number of passed boys in B  = 280*(11/14) = 220
   Number of passed boys in C  = 400*(21/25) = 336
   Number of passed boys in D  = 320*(15/16) = 300
   Number of passed boys in E  = 410*(37/41) = 370
   Number of passed boys in F  = 500*(41/50) = 410
   Total number of passed boys = 1816
   Number of passed girls in A  = 160*(13/16) = 130
   Number of passed girls in B  = 250*(4/5) = 200
   Number of passed girls in C  = 450*(13/15) = 390
   Number of passed girls in D  = 260*(11/13) = 220
   Number of passed girls in E  = 230*(21/23) = 210
   Number of passed girls in F  = 450*(29/30) = 435
   Total number of passed girls = 1585
   Required difference = 231
3. The number of passed boys in school F is approximately , what percent more than the number of passed girls in school C?
   A)  13%
   B) 11%
   C) 7%
   D) 5%
   E)  8%
   
   View Answer

     Option D
   Solution:
   Number of passed boys in school F = 500*(41/50) = 410
   Number of passed girls in school C = 450*(13/15) = 390
   Required % = [(410 – 390)*100]/390 = 5.13 = 5% (approx.)
   
4. The number of students in class 8^th of school A is 25% more than the total number of students in class 6^th of the same school .What is the ratio between the number of students in class 8^th of school A and the number of passed girls in class 6^th of school E?
   A) 50:21
   B) 34:48
   C) 51:42
   D)  49:35
   E) 51:40
   
   View Answer

     Option A
   Solution:
   Number of students in class 6^th of school A = 240 + 160 = 400
   Number of students in class 8^th of school A = 400*(125/100) = 500
   Number of passed girls in class 6^th  of school E = 230*(21/23) = 210
   Required ratio = 500 : 210 = 50 : 21
5. The total number of failed boys in school A and F together is approximately what percent of the total number of passed girls in school B and E together?
   A) 30%
   B) 48%
   C) 37%
   D) 25%
   E)  45%
   
   View Answer

     Option  C
   Solution:
   Number of failed boys in school A = 240*(1/4) = 60
   Number of failed boys in school F = 500*(9/50) = 90
   Total number of failed boys = 60 + 90 = 150
   Number of passed girls in school B = 200
   Number of passed girls in school E = 210
   Total number of passed girls = 200 + 210 = 410
   Required % = (150/410)*100 = 36.58% = 37%(approx.)
   

Directions(6-10): Study the charts carefully and answer the related questions. The bar graph shows the profit % earned on six different articles . The pie-chart shows the cost price of six different articles sold by a store in 2015.

1. The selling price of fan and cooler  together is approximately what percent of the selling price of T.V. and radio together?
   A) 88%
   B) 96%
   C)100%
   D) 80%
   E) 150%
   
   View Answer

     Option B
   Solution:
   CP of fan = (12/100)*72000 = 8640
   Profit% = 25%
   SP of fan = (8640*125)/100 = 10800
   CP of cooler = (18/100)*72000 = 12960
   Profit% = 48%
   SP of cooler = (12960*148)/100 = 19180.80
   Total SP of fan and cooler together = 10800 + 19180.80 = 29980.80
   CP of TV = (21/100)*72000 = 15120
   Profit% = 42%
   SP of TV = (15120*142)/100 = 21470.40
   CP of radio = (10/100)*72000 = 7200
   Profit % = 36%
   SP of radio = (7200*136)/100 = 9792
   Total SP of TV and radio = 21470.40 + 9792 = 31262.40
   Required % = (29980.80/31262.40)*100 = 95.9% = 96%(approx.)
   
2. The marked price of TV is what percent of the cost price of cooler ?
   A)  35%
   B) 40%
   C) 22%
   D) Data inadequate
   E) None of these
   
   View Answer

     Option D
   Solution:
   Since ,we don’t have discount of TV .So,we can’t find the marked price .
   
3. What is the difference between the selling price of LED and that of TV?
   A)  1520.67
   B) 26450
   C) 3457.45
   D) 2491.60
   E) 1457.8
   
   View Answer

     Option D
   Solution:
   CP of LED  = (26/100)*72000 = 18720
   Profit% = 28%
   SP of LED = (18720*128)/100 = 23961.60
   SP of TV = 21470.40
   Required difference = 23961.60 – 21470.40 = 2491.20
   
4. The selling price of fan is approx. what percent of the selling price of watch ?
   A)  85%
   B) 75%
   C)90%
   D) 70%
   E) 115%
   
   View Answer

     Option A
   Solution:
   CP of fan = (12/100)*72000 = 8640
   Profit% = 25%
   SP of fan = (8640*125)/100 = 10800
   CP of watch  = (13/100)*72000 = 9360
   Profit % = 35%
   SP of watch = (9360*135)/100 = 12636
   Required % = (10800/12636)*100 = 85.47% = 85%
   
5. The marked price of radio is approx. what percent of the selling price of LED if 20% discount is available on radio?
   A)  55%
   B) 51%
   C)45%
   D) 36%
   E) 44%
   
   View Answer

     Option  B
   Solution:
   CP of radio = (10/100)*72000 = 7200
   Profit% = 36%
   SP of radio = (7200*136)/100 = 9792
   Discount on radio = 20%
   MP of radio = (9792/80)*100 = 12240
   CP of LED = (26/100)*72000 = 18720
   Profit% = 28%
   SP of LED = (18720*128)/100 = 23961.60
   Required % = (12240/23961.60)*100 = 51.08% = 51%

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