**Directions (1-5):** A bar graph and a table are given.The bar graph shows the data regarding the number of boys and girls studying in 6^{th} class of 6 different schools. The table shows the respective ratio of passed boys/failed boys and passed girls /failed girls in 6 different schools.

- What is the approximate average number of failed boys in class 6
^{th} of all the 6 schools together ?

A) 50

B) 78

C) 56

D) 48

E) 45

View Answer

**Option C**

Solution:

Number of failed boys in A = 240*(1/4) = 60

Number of failed boys in B = 280*(3/14) = 60

Number of failed boys in C = 400*(4/25) = 64

Number of failed boys in D = 320*(1/16) = 20

Number of failed boys in E = 410*(4/41) = 40

Number of failed boys in F = 500*(9/50) = 90

Total number of failed boys = (60+60+64+20+40+90) = 334

Required avg. = 334/6 = 56(approx.)

- What is the difference between the total number of passed boys and passed girls in all 6 schools together ?

A) 285

B) 231

C) 200

D) 250

E) 220

View Answer

**Option B**

Solution:

Number of passed boys in A = 240*(3/4) = 180

Number of passed boys in B = 280*(11/14) = 220

Number of passed boys in C = 400*(21/25) = 336

Number of passed boys in D = 320*(15/16) = 300

Number of passed boys in E = 410*(37/41) = 370

Number of passed boys in F = 500*(41/50) = 410

Total number of passed boys = 1816

Number of passed girls in A = 160*(13/16) = 130

Number of passed girls in B = 250*(4/5) = 200

Number of passed girls in C = 450*(13/15) = 390

Number of passed girls in D = 260*(11/13) = 220

Number of passed girls in E = 230*(21/23) = 210

Number of passed girls in F = 450*(29/30) = 435

Total number of passed girls = 1585

Required difference = 231

- The number of passed boys in school F is approximately , what percent more than the number of passed girls in school C?

A) 13%

B) 11%

C) 7%

D) 5%

E) 8%

View Answer

**Option D**

Solution:

Number of passed boys in school F = 500*(41/50) = 410

Number of passed girls in school C = 450*(13/15) = 390

Required % = [(410 – 390)*100]/390 = 5.13 = 5% (approx.)

- The number of students in class 8
^{th} of school A is 25% more than the total number of students in class 6^{th} of the same school .What is the ratio between the number of students in class 8^{th} of school A and the number of passed girls in class 6^{th} of school E?

A) 50:21

B) 34:48

C) 51:42

D) 49:35

E) 51:40

View Answer

**Option A**

Solution:

Number of students in class 6^{th} of school A = 240 + 160 = 400

Number of students in class 8^{th} of school A = 400*(125/100) = 500

Number of passed girls in class 6^{th} of school E = 230*(21/23) = 210

Required ratio = 500 : 210 = 50 : 21

- The total number of failed boys in school A and F together is approximately what percent of the total number of passed girls in school B and E together?

A) 30%

B) 48%

C) 37%

D) 25%

E) 45%

View Answer

**Option C**

Solution:

Number of failed boys in school A = 240*(1/4) = 60

Number of failed boys in school F = 500*(9/50) = 90

Total number of failed boys = 60 + 90 = 150

Number of passed girls in school B = 200

Number of passed girls in school E = 210

Total number of passed girls = 200 + 210 = 410

Required % = (150/410)*100 = 36.58% = 37%(approx.)

**Directions(6-10): **Study the charts carefully and answer the related questions. The bar graph shows the profit % earned on six different articles . The pie-chart shows the cost price of six different articles sold by a store in 2015.

- The selling price of fan and cooler together is approximately what percent of the selling price of T.V. and radio together?

A) 88%

B) 96%

C)100%

D) 80%

E) 150%

View Answer

**Option B**

Solution:

CP of fan = (12/100)*72000 = 8640

Profit% = 25%

SP of fan = (8640*125)/100 = 10800

CP of cooler = (18/100)*72000 = 12960

Profit% = 48%

SP of cooler = (12960*148)/100 = 19180.80

Total SP of fan and cooler together = 10800 + 19180.80 = 29980.80

CP of TV = (21/100)*72000 = 15120

Profit% = 42%

SP of TV = (15120*142)/100 = 21470.40

CP of radio = (10/100)*72000 = 7200

Profit % = 36%

SP of radio = (7200*136)/100 = 9792

Total SP of TV and radio = 21470.40 + 9792 = 31262.40

Required % = (29980.80/31262.40)*100 = 95.9% = 96%(approx.)

- The marked price of TV is what percent of the cost price of cooler ?

A) 35%

B) 40%

C) 22%

D) Data inadequate

E) None of these

View Answer

**Option D**

Solution:

Since ,we don’t have discount of TV .So,we can’t find the marked price .

- What is the difference between the selling price of LED and that of TV?

A) 1520.67

B) 26450

C) 3457.45

D) 2491.60

E) 1457.8

View Answer

**Option D**

Solution:

CP of LED = (26/100)*72000 = 18720

Profit% = 28%

SP of LED = (18720*128)/100 = 23961.60

SP of TV = 21470.40

Required difference = 23961.60 – 21470.40 = 2491.20

- The selling price of fan is approx. what percent of the selling price of watch ?

A) 85%

B) 75%

C)90%

D) 70%

E) 115%

View Answer

**Option A**

Solution:

CP of fan = (12/100)*72000 = 8640

Profit% = 25%

SP of fan = (8640*125)/100 = 10800

CP of watch = (13/100)*72000 = 9360

Profit % = 35%

SP of watch = (9360*135)/100 = 12636

Required % = (10800/12636)*100 = 85.47% = 85%

- The marked price of radio is approx. what percent of the selling price of LED if 20% discount is available on radio?

A) 55%

B) 51%

C)45%

D) 36%

E) 44%

View Answer

**Option B**

Solution:

CP of radio = (10/100)*72000 = 7200

Profit% = 36%

SP of radio = (7200*136)/100 = 9792

Discount on radio = 20%

MP of radio = (9792/80)*100 = 12240

CP of LED = (26/100)*72000 = 18720

Profit% = 28%

SP of LED = (18720*128)/100 = 23961.60

Required % = (12240/23961.60)*100 = 51.08% = 51%

Thanks sir / mam

Nice quiz of di after long time

Thnks AZ

q no 7 is good….thank u team az…

Tks

ty

keep posting more 🙂

Thanks Banya Mam:))

tnk u team AZ 🙂

Ty:)

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