Quantitative Aptitude: Data Interpretation Questions Set 47

Directions (1-5): A bar graph and a table are given.The bar graph  shows the data regarding the number of boys and girls studying in 6th class of 6 different schools. The table shows the respective ratio of passed boys/failed boys and passed girls /failed girls in 6 different schools.

  1. What is the approximate average number of failed boys in class 6th of all the 6 schools together ?
    A) 50
    B) 78
    C) 56
    D) 48
    E) 45
    View Answer
      Option C
    Solution:
    Number of failed boys in A = 240*(1/4)  = 60
    Number of failed boys in B = 280*(3/14) = 60
    Number of failed boys in C = 400*(4/25)  = 64
    Number of failed boys in D = 320*(1/16) = 20
    Number of failed boys in E = 410*(4/41) = 40
    Number of failed boys in F = 500*(9/50) = 90
    Total number of failed boys = (60+60+64+20+40+90) = 334
    Required avg. = 334/6 = 56(approx.)
  2. What is the difference between the total number of passed boys and passed girls in all 6 schools together ?
    A) 285
    B) 231
    C) 200
    D) 250
    E) 220
    View Answer
      Option  B
    Solution:
    Number of passed boys in A  = 240*(3/4) = 180
    Number of passed boys in B  = 280*(11/14) = 220
    Number of passed boys in C  = 400*(21/25) = 336
    Number of passed boys in D  = 320*(15/16) = 300
    Number of passed boys in E  = 410*(37/41) = 370
    Number of passed boys in F  = 500*(41/50) = 410
    Total number of passed boys = 1816
    Number of passed girls in A  = 160*(13/16) = 130
    Number of passed girls in B  = 250*(4/5) = 200
    Number of passed girls in C  = 450*(13/15) = 390
    Number of passed girls in D  = 260*(11/13) = 220
    Number of passed girls in E  = 230*(21/23) = 210
    Number of passed girls in F  = 450*(29/30) = 435
    Total number of passed girls = 1585
    Required difference = 231
  3. The number of passed boys in school F is approximately , what percent more than the number of passed girls in school C?
    A)  13%
    B) 11%
    C) 7%
    D) 5%
    E)  8%
    View Answer
      Option D
    Solution:
    Number of passed boys in school F = 500*(41/50) = 410
    Number of passed girls in school C = 450*(13/15) = 390
    Required % = [(410 – 390)*100]/390 = 5.13 = 5% (approx.)
  4. The number of students in class 8th of school A is 25% more than the total number of students in class 6th of the same school .What is the ratio between the number of students in class 8th of school A and the number of passed girls in class 6th of school E?
    A) 50:21
    B) 34:48
    C) 51:42
    D)  49:35
    E) 51:40
    View Answer
      Option A
    Solution:
    Number of students in class 6th of school A = 240 + 160 = 400
    Number of students in class 8th of school A = 400*(125/100) = 500
    Number of passed girls in class 6th  of school E = 230*(21/23) = 210
    Required ratio = 500 : 210 = 50 : 21
  5. The total number of failed boys in school A and F together is approximately what percent of the total number of passed girls in school B and E together?
    A) 30%
    B) 48%
    C) 37%
    D) 25%
    E)  45%
    View Answer
      Option  C
    Solution:
    Number of failed boys in school A = 240*(1/4) = 60
    Number of failed boys in school F = 500*(9/50) = 90
    Total number of failed boys = 60 + 90 = 150
    Number of passed girls in school B = 200
    Number of passed girls in school E = 210
    Total number of passed girls = 200 + 210 = 410
    Required % = (150/410)*100 = 36.58% = 37%(approx.)

Directions(6-10): Study the charts carefully and answer the related questions. The bar graph shows the profit % earned on six different articles . The pie-chart shows the cost price of six different articles sold by a store in 2015.

  1. The selling price of fan and cooler  together is approximately what percent of the selling price of T.V. and radio together?
    A) 88%
    B) 96%
    C)100%
    D) 80%
    E) 150%
    View Answer
      Option B
    Solution:
    CP of fan = (12/100)*72000 = 8640
    Profit% = 25%
    SP of fan = (8640*125)/100 = 10800
    CP of cooler = (18/100)*72000 = 12960
    Profit% = 48%
    SP of cooler = (12960*148)/100 = 19180.80
    Total SP of fan and cooler together = 10800 + 19180.80 = 29980.80
    CP of TV = (21/100)*72000 = 15120
    Profit% = 42%
    SP of TV = (15120*142)/100 = 21470.40
    CP of radio = (10/100)*72000 = 7200
    Profit % = 36%
    SP of radio = (7200*136)/100 = 9792
    Total SP of TV and radio = 21470.40 + 9792 = 31262.40
    Required % = (29980.80/31262.40)*100 = 95.9% = 96%(approx.)
  2. The marked price of TV is what percent of the cost price of cooler ?
    A)  35%
    B) 40%
    C) 22%
    D) Data inadequate
    E) None of these
    View Answer
      Option D
    Solution:
    Since ,we don’t have discount of TV .So,we can’t find the marked price .
  3. What is the difference between the selling price of LED and that of TV?
    A)  1520.67
    B) 26450
    C) 3457.45
    D) 2491.60
    E) 1457.8
    View Answer
      Option D
    Solution:
    CP of LED  = (26/100)*72000 = 18720
    Profit% = 28%
    SP of LED = (18720*128)/100 = 23961.60
    SP of TV = 21470.40
    Required difference = 23961.60 – 21470.40 = 2491.20
  4. The selling price of fan is approx. what percent of the selling price of watch ?
    A)  85%
    B) 75%
    C)90%
    D) 70%
    E) 115%
    View Answer
      Option A
    Solution:
    CP of fan = (12/100)*72000 = 8640
    Profit% = 25%
    SP of fan = (8640*125)/100 = 10800
    CP of watch  = (13/100)*72000 = 9360
    Profit % = 35%
    SP of watch = (9360*135)/100 = 12636
    Required % = (10800/12636)*100 = 85.47% = 85%
  5. The marked price of radio is approx. what percent of the selling price of LED if 20% discount is available on radio?
    A)  55%
    B) 51%
    C)45%
    D) 36%
    E) 44%
    View Answer
      Option  B
    Solution:
    CP of radio = (10/100)*72000 = 7200
    Profit% = 36%
    SP of radio = (7200*136)/100 = 9792
    Discount on radio = 20%
    MP of radio = (9792/80)*100 = 12240
    CP of LED = (26/100)*72000 = 18720
    Profit% = 28%
    SP of LED = (18720*128)/100 = 23961.60
    Required % = (12240/23961.60)*100 = 51.08% = 51%

 

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12 Thoughts to “Quantitative Aptitude: Data Interpretation Questions Set 47”

  1. anurag agarwal

    Thanks sir / mam
    Nice quiz of di after long time

  2. WANNA FLY

    q no 7 is good….thank u team az…

  3. MAYANK BHARADWAJ100%

    Tks

  4. Adamant

    ty
    keep posting more 🙂

  5. ครђ

    Thanks Banya Mam:))

  6. Rise And Shine

    tnk u team AZ 🙂

  7. ~~Sb acha hoga Ab ~~√

    Ty:)

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