Quantitative Aptitude: Percentage Questions Set 3

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, NIACL, NICL, RBI Grade B/Assistant, BOI, Bank of Baroda and other competitive exams

1. In a college there are 60% female students. 50 % of all the male students are in computer department. If there are total 62% students in computer department out of total 2400 students, then the no. of female students who are in computer department ?
   A) 528
   B) 1488
   C) 1008
   D) 730
   E) None
   
   View Answer

   Option C
   Solution:
   Let 60% students are female and 40% are male.
   Then,(50%male) 20% of male are in computer department and (62-20)42% are female in computer department.
   Female in computer department = (2400 *42) /100
   = 1008.
2. In an auditorium there are 3500 students. Last day except 1.5% of the boys all the students were present in the college. Today except 2% of the girls all the students are present in the college, but in both the days number of students present in the college, were same. The number of boys in the college is?
   A) 2000
   B) 1500
   C) 2500
   D) 1200
   E) None
   
   View Answer

   Option A
   Solution:
   From Options;
   let Number of boys = 2000
   let Number of girls = 1500
   98.5% of 2000 + 1500 = 98% of 1500 + 2000[It satisfies the condition]
   
3. 80% of a small number is 4 less than 40% of a larger number. The larger number is 50 greater than the smaller one. The value of smaller numbers is
   A) 15
   B) 40
   C) 10
   D) 35
   E) None
   
   View Answer

   Option B
   Solution:
   Let the smaller number be x and larger number be y.
   According to the question,
   80% of x + 4 = 40% of y
   4y – 8x = 40
   y – 2x = 10 ——— (1)
   y – x = 50 ———– (2)
   By using (1) and (2), we get
   x = 40
   y = 90
   
4. In an election only two candidates M and N contested 30% of the voters did not vote and 1600 votes were declared as invalid. The winner, M got 4800 votes more than his opponent thus he secured 51% votes of the total voters on the voter list. Percentage votes of the loser candidate, N out of the total voters on the voter list is:
   A) 5%
   B) 4%
   C) 2%
   D) 3%
   E) None
   
   View Answer

   Option D
   Solution:
   Total voters on the voter list = x
   51/100x + 51/100x – 4800 = 70/100x – 1600
   102x/100 – 4800 = 70/100x – 1600
   32x/100=3200
   x = 10000
   Votes of the loser candidate = 5100 – 4800 = 300
   Percentage votes of the loser candidate = 300/10000 * 100 = 3%
5. In a office there are 40% female employees, 30% of these earn greater than Rs6000/month and 70% of male employees earn less than Rs6000/month. What is the percentage of employees who earn more than Rs6000/month?
   A) 25%
   B) 32%
   C) Can’t be determined
   D) 45%
   E) None
   
   View Answer

   Option C
   Solution:
   Original values not given So we cant able to find the solution.
   
6. The ratio of the number of boys and girls in a school is 4:1. If 30% of the boys and 25% of the girls are scholarship holders, the percentage of the students who are not scholarship holders is
   A) 71
   B) 75
   C) 82
   D) 87
   E) None
   
   View Answer

   Option A
   Solution:
   Consider Total no of students = 100
   Ratio is 4:1 i.e Boys=80 and Girls=20
   Boys who got scholarship is 24(30% of 80)
   Girls who got scholarship is 5(25% of 20)
   Therefore % of students who do not get scholarship =100-(24+5) = 71%
7. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
   A) 45
   B) 54 6/11
   C) 45 5/11
   D) 54
   E) None
   
   View Answer

   Option C
   Solution:
   Number of runs made by running,
   =100-(3*4+8*6)
   =100-60==> 50
   Required %ge = (50/110)*100
   =45 5/11%
   
8. A number is mistakenly divided by 8 instead of being multiplied by 8.What is the percentage of error in the result ?
   A) 94.75
   B) 93.25
   C) 94.5
   D) 98.43
   E) None
   
   View Answer

   Option D
   Solution:
   % of error = ([8x – (x/8)] / 8x )×100
   = [64 – 1 / 64] ×100
   = 63×100/64 = 98.43
   
9. A reduction of 21% percent in the price of rice enables a person to buy 10.5 kg more for Rs100. The reduced price per kg of rice
   A) 2
   B) 2.5
   C) 3
   D) 3.5
   E) None
   
   View Answer

   Option A
   Solution:
   100*(21/100)/10.5=21/10.5
   =42/21=2.
   
10. James spend 30% of his monthly income on food article, 40% of the remaining spend for conveyance and clothing ans save 50% of the remaining. In his monthly salary is Rs 18,400 how much did he save?
    A) Rs4210
    B) Rs3864
    C) Rs4500
    D) Rs4820
    E) None
    
    View Answer

    Option B
    Solution:
    18400* 70/100*60/100*50/100=184*21
    =Rs3864.