Quadratic Equation Questions for IBPS PO/RRB, SBI, RBI, NICL, NIACL, LIC, UIIC, OICL, Bank of Baroda and other competitive exams.
Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
- I. 2x2 – 21x – 55 = 0
II. 3y2 – 14y – 5 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption C
Solution:
x = 5, 11/2
y = -1/3, 5
Put all values on number line and analyze the relationship
-1/3………5……..11/2 - I. 3x2 – 13x + 14 = 0
II. 3y2 – 19y + 28 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption D
Solution:
x = 2, 7/3
y = 7/3, 4
Put all values on number line and analyze the relationship
2………..7/3……4 - I. 3x2 + 2x – 21 = 0
II. 3y2 – 13y + 14 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E
Solution:
x = -3, 7/3
y = 2, 7/3
Put all values on number line and analyze the relationship
-3………..2……7/3 - I. 3x2 – 11x – 4 = 0
II. 3y2 + 14y + 16 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption A
Solution:
x = -1/3, 4
y = -8/3, -2
Put all values on number line and analyze the relationship
-8/3………..-2……6 - I. 3x2 – 8x + 4 = 0
II. 3y2 – 19y + 30 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption B
Solution:
x = 2/3, 2
y = 3, 10/3
Put all values on number line and analyze the relationship
2/3……2……..3……10/3 - I. 3x2 – 11x + 6 = 0
II. 3y2 – 16y + 20 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E
Solution:
x = 2/3, 3
y = 2, 10/3
Put all values on number line and analyze the relationship
2/3……2……..3……10/3 - I. 3x2 – 4x – 32 = 0
II. 3y2 + 14y + 16 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E
Solution:
x = -8/3, 4
y = -8/3, -2
Put all values on number line and analyze the relationship
-8/3………..-2……….4 - I. 2x2 + 13x + 20 = 0
II. 2y2 + 5y – 12 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E
Solution:
x = -4, -5/2
y = -4, 3/2
Put all values on number line and analyze the relationship
-4……….-5/2……..3/2 - I. 3x2 – 17x + 20 = 0
II. 3y2 + y – 10 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption C
Solution:
x = 5/3, 4
y = -2, 5/3
Put all values on number line and analyze the relationship
-2………5/3……..4 - I. 4x2 – 15x + 9 = 0
II. 2y2 – 13y + 21 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption D
Solution:
x = 3, 7/2
y = 3/4, 3
Put all values on number line and analyze the relationship
3/4………..3……..7/2
Madam , question no. 1 in wrong. please maintain the dignity as you provide good set of question.
QUES NO 1 AS PER SIGN RULE…AND OTHERWISE ALSO IS NOT CORRECT …..PLEASE MAKE CORRECTION…THANK YOU TEAM az
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