- In each of these questions, two equations (a) and (b) are given. You have to solve both the equations and give answer.

2m2+11m+14=0

4n2+12n+9=0if m < nif m > nif m ≤ nIf m ≥ nif m = n or no relation can be establishedOption A

From eq (a),2m^2+4m+7m+14=0

2m(m+2)+7(m+2)=0

m= -2,-3.5

From eq (b),(2n+3)^2=0

n= -1.5 , -1.5 - m^2 – 4 = 0

n^2 + 6n + 9=0if m < nif m > nif m ≤ nIf m ≥ nif m = n or no relation can be establishedOption B

From eq(a),m = +-2

From eq(b), n^2 + 3n + 3n + 9=0

n = -3 ,- 3 - m^2 – 7m + 12 = 0

n^2 + n -12=0if m < nif m > nif m ≤ nIf m ≥ nif m = n or no relation can be establishedOption D

From eq (a), m^2 – 3m – 4m +12=0

m(m-3)-4(m-3)=0

m=3,4

From eq(b) , n(n+4) -3(n+4) = 0

n =3, -4 - m^2 = 729

n = √529if m < nif m > nif m ≤ nIf m ≥ nif m = n or no relation can be establishedOption E

m = +-27

n = 23 - m^4 – 227 = 398

n^2 + 321 = 346if m < nif m > nif m ≤ nIf m ≥ nif m = n or no relation can be establishedOption E

m^4 = 625 = +-5

n^2 = 346-321 =+-5 - x^2 – 12p +35=0

q^2 – 25=0if x > yif x ≥ yif x < yif x ≤ yif x = y or there is no relation between ‘x’ and ‘y’Option B

From eq(a) , x^2 -7x – 5x +35 =0

x(x-7) – 5(x-7)=0

x= 5,7

From eq (b) ,y = 5 , -5 - 2x^2+5x -12=0

2y^2 -y – 1=0if x > yif x ≥ yif x < yif x ≤ yif x = y or there is no relation between ‘x’ and ‘y’Option E

From eq(a) , 2x^2+8x-3x-12=0

2x(x+4)-3(x+4)=0

x=1.5 , -4

From eq(b) , 2y^2 – 2y +y – 1=0

y = -0.5 , 1 - x^2=49

y^2+15y+56 =0if x > yif x ≥ yif x < yif x ≤ yif x = y or there is no relation between ‘x’ and ‘y’Option B

x=7 , -7

y^2 + 7q + 8q + 56=0

y = – 7, -8 - 4x^2 – 4x+15=0

2y^2 +5y – 7=0if x > yif x ≥ yif x < yif x ≤ yif x = y or there is no relation between ‘x’ and ‘y’Option A - (x+y)^2 = 3136

y +2513 = 2569if x > yif x ≥ yif x < yif x ≤ yif x = q or there is no relation between ‘x’ and ‘y’Option C

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