Quantitative Aptitude: Simplification Questions Set 79

Directions(1-10): What approximate value will come in place of question mark ‘?’ in the following questions.

  1. [(๐Ÿ–๐Ÿ’) ^๐Ÿ รท ๐Ÿ๐Ÿ– ร— ๐Ÿ๐Ÿ] รท ๐Ÿ๐Ÿ’ = ๐Ÿ• ร—?
    20
    22
    18
    24
    10
    Option C
    [(๐Ÿ–๐Ÿ’) ^๐Ÿ รท ๐Ÿ๐Ÿ– ร— ๐Ÿ๐Ÿ] รท ๐Ÿ๐Ÿ’ = ๐Ÿ• ร—?
    =>7 ร—? = 84ร—84/28 ร— 12 ร— 1/24
    => ? = 18

     

  2. (7.9% of 134) โ€“ (3.4% of 79) =?
    12
    8
    10
    6
    13
    Option B
    (7.9% of 134) โ€“ (3.4% of 79) =?
    ? = 7.9/100 ร— 134 โˆ’ 3.4/100 ร— 79
    = 7.9 == 8

     

  3. [(๐Ÿ๐Ÿ—๐Ÿ)^ ๐Ÿ รท ๐Ÿ”๐Ÿ’ ร— ๐Ÿ๐Ÿ’] รท ๐Ÿ’๐Ÿ– = โˆš?
    84490
    87389
    81020
    89300
    82944
    Option E
    [(๐Ÿ๐Ÿ—๐Ÿ)^ ๐Ÿ รท ๐Ÿ”๐Ÿ’ ร— ๐Ÿ๐Ÿ’] รท ๐Ÿ’๐Ÿ– = โˆš?
    =>โˆš? = 36864/64 ร— 24 ร— 1/48 = 288
    => ? = 82944

     

  4. 30% of ๐Ÿ/๐Ÿ• of ๐Ÿ/๐Ÿ— of ๐Ÿ/๐Ÿ“ of ๐Ÿ/๐Ÿ‘ of 9450 =?
    46
    42
    44
    40
    48
    Option E
    30% of ๐Ÿ/๐Ÿ• of ๐Ÿ/๐Ÿ— of ๐Ÿ/๐Ÿ“ of ๐Ÿ/๐Ÿ‘ of 9450 =?
    =>? = 30/100 ร— 2/7 ร— 2/9 ร— 2/5 ร— 2/3 ร— 9450
    = 48

     

  5. (๐Ÿ/๐Ÿ๐ŸŽ๐Ÿ๐Ÿ’)^( โˆ’๐Ÿ/๐Ÿ“) + ( ๐Ÿ/๐Ÿ‘๐Ÿ’๐Ÿ‘)^( โˆ’๐Ÿ/๐Ÿ‘) = ? ร— 5
    18
    13
    10
    15
    17
    Option B
    (๐Ÿ/๐Ÿ๐ŸŽ๐Ÿ๐Ÿ’)^( โˆ’๐Ÿ/๐Ÿ“) + ( ๐Ÿ/๐Ÿ‘๐Ÿ’๐Ÿ‘)^( โˆ’๐Ÿ/๐Ÿ‘) = ? ร— 5
    =>?ร— 5 = (4)^{( โˆ’5)ร—( โˆ’2/5)} + (7) ^{(โˆ’3)ร—( โˆ’2/ 3)}
    => ? = (16+49)/5 = 13

     

  6. 3.5% of 40 + 3.5% of 80 =? % of 10
    40
    45
    48
    42
    46
    Option D
    3.5% of 40 + 3.5% of 80 =? % of 10
    =>? = (1.4 + 2.8)/10 ร— 100 = 42

     

  7. ๐Ÿ( ๐Ÿ•/๐Ÿ—) + ๐Ÿ(๐Ÿ“/๐Ÿ‘) + ๐Ÿ‘(๐Ÿ/๐Ÿ—) โ€“ ๐Ÿ’(๐Ÿ/๐Ÿ“) = ?
    1(15/41)
    3(11/46)
    4(16/45)
    3(10/45)
    4(16/41)
    Option C
    ๐Ÿ( ๐Ÿ•/๐Ÿ—) + ๐Ÿ(๐Ÿ“/๐Ÿ‘) + ๐Ÿ‘(๐Ÿ/๐Ÿ—) โ€“ ๐Ÿ’(๐Ÿ/๐Ÿ“) = ?
    ? = (1 + 2 + 3 โˆ’ 4) + ( 7/9 + 5/3 + 1/9 โ€“ 1/5 )
    = 2 + 106/45 = 4(16/45)

     

  8. (๐Ÿ ร— ๐Ÿ‘)^๐Ÿ‘ รท (๐Ÿ’ ร— ๐Ÿ—)^๐Ÿ ร— (๐Ÿ๐Ÿ• ร— ๐Ÿ–)^๐Ÿ = (๐Ÿ”)^?
    3
    5
    2
    6
    7
    Option B
    (๐Ÿ ร— ๐Ÿ‘)^๐Ÿ‘ รท (๐Ÿ’ ร— ๐Ÿ—)^๐Ÿ ร— (๐Ÿ๐Ÿ• ร— ๐Ÿ–)^๐Ÿ = (๐Ÿ”)^?
    =>(6)^? = (6) ^3 รท 6^4 ร— 6^6
    โ‡’ (6)^? = 6^(3โˆ’4+6)
    โ‡’ ? = 5

     

  9. ๐Ÿ’๐Ÿ“๐Ÿ’. ๐Ÿ“๐Ÿ– โˆ’ ๐Ÿ‘๐Ÿ•๐Ÿ”. ๐Ÿ–๐Ÿ— + ๐Ÿ๐Ÿ๐Ÿ. ๐Ÿ’๐Ÿ“ โˆ’ ๐Ÿ—๐Ÿ“. ๐Ÿ’๐Ÿ = ?
    104
    110
    100
    107
    117
    Option A
    ๐Ÿ’๐Ÿ“๐Ÿ’. ๐Ÿ“๐Ÿ– โˆ’ ๐Ÿ‘๐Ÿ•๐Ÿ”. ๐Ÿ–๐Ÿ— + ๐Ÿ๐Ÿ๐Ÿ. ๐Ÿ’๐Ÿ“ โˆ’ ๐Ÿ—๐Ÿ“. ๐Ÿ’๐Ÿ = ?
    ? = 576.03 โ€“ 472.31 = 103.72
    == 104

     

  10. โˆš๐Ÿ“๐Ÿ•๐Ÿ” รท (๐Ÿ’)^๐Ÿ ร— ๐Ÿ•. ๐Ÿ’ + (๐Ÿ•)^๐Ÿ‘ โˆ’ ๐Ÿ๐Ÿ‘๐Ÿ = ?
    110
    111
    120
    127
    123
    Option E
    โˆš๐Ÿ“๐Ÿ•๐Ÿ” รท (๐Ÿ’)^๐Ÿ ร— ๐Ÿ•. ๐Ÿ’ + (๐Ÿ•)^๐Ÿ‘ โˆ’ ๐Ÿ๐Ÿ‘๐Ÿ = ?
    = ? = 24 รท 16 ร— 7.4 + 343 โˆ’ 231
    = 11.1 + 112 = 123.1 == 123

     


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