Time Speed Distance Questions for NICL, SBI PO, IBPS PO, NIACL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.

- Two trains are running with speed 40kmph and 60kmph in the same direction. A man in the slower train passes by the faster train in 36seconds. Find the length of faster train?

A) 100mtr

B) 150mtr

C) 200mtr

D) 250mtr

E) 300mtr

- After travelling two hours a train met with an accident due to this it stops for an hour. After this the train moves at 66(2/3)% speed of its original speed and reaches to destination 3hour late. If the accident would occur at 200km ahead in the same line then the train reaches only 2.5hours late. Then find the distance of journey and the original speed of the train?

A) 2400km,600kmph

B) 1800km,300kmph

C) 2400km,400kmph

D) 1800km,200kmph

E) 2000km,100kmph

- A man travels a distance in three equal parts. He covers first part at 20kmph,second part at 40kmph and third part at 120kmph. Find the distance if he covers total distance in 20hrs.

A) 1400km

B) 1200km

C) 1440km

D) 1600km

E) 1500km

- A person who can walk down a hill at the rate of 6kmph and climb up the hill at rate of 4kmph. He ascends and comes down to his starting point in 5hrs. how far did he ascends ?

A) 12km

B) 14km

C) 20km

D) 24km

E) 16km

- A student walks from his house at a speed of 2(1/2)km per hour and reaches his school 6minutes late. The next day he increases his speed by 1kmph and reaches 6minutes before school time. How far is the school from his home?

A) 5/4km

B) 9/4km

C) 7/4km

D) 11/4km

E) 10/4km

- In covering a distance of 60km Abhi takes 2hrs more than Sam. If Abhi triples his speed then he would take 2hrs less than Sam. Abhi speed in kmph is ?

A) 10kmph

B) 12kmph

C) 15kmph

D) 20kmph

E) 14kmph

- Two men start together to walk a certain distance, one at 5kmph and another at 4kmph. The former arrives an hour before the latter. Find the distance?

A) 10km

B)Â 15km

C) 20km

D) 25km

E) 30km

- A man covers a distance in downstream at 18kmph. If the speed of stream is 2kmph then find his speed in upstream?

A) 12kmph

B) 14kmph

C) 16kmph

D) 18kmph

E) 20kmph

- The distance between a thief and apolicemen is 300m. the speed of thief is 12m/s and the speed of police is 15m/s. find the distance covered by police to catch the thief?

A) 1000m

B) 1200m

C) 1500m

D) 2000m

E) 1300m

- Two trains of same length passes each other in 36sec. if the speed of trains are 40kmph and 20kmph respectively, then find the length of train?

A) 200 m

B) 400 m

C) 600 m

D) 300 m

E) 500 m

### Click here for more Questions on Time Speed Distance

Can u plz explain how average speed is 72 km in question no 3

explain the third qus

In Q 2 option C also follow all conditions but only .1 difference comes so can we accept it as a ans or its wrong ??

q5 ?

u can easily solve with the help of options so go for it

its also easy

u can understand Q 3?

by option how?

use these given value and solve

qs 8 ?

its very simple

downstream speed =18

stream speed 2 but when we swim against stream speed it will be double so now stream speed 4

so 18-4=14ans

ty

downstream =x+y

upstream =x-y

now (x-y)^2 = (x+y)^2 -4xy

=(18)^2 -4*14*4 =14 km/hr

Q4. There are 3 containers A, B and C which contain water, milk and acid respectively in equal quantities. 10% of the content of A is taken out and poured into B. Then, the same 10% from B is transferred to C, from which again the same 10% is transferred to A. What is the proportion of milk in container A at the end of the process ?

(a) 9/10

(b) 1/11

(c) 1/121

(d) 10/1011

(e) None of these

process kitni baar ki h ye to bathoo 1,2,3,4???

etna hi hai qs me

na phir to nhi hoga ese kese hoga process to btani pdegi ki kitni baar kiya h

2 baar kiya hoga to alag aayga 3 baar kiya hoga to alag % aayega

quantity A 100x (water) Ataken 10% water poured into B

means A remaining 90X

now,B=100Xmilk710X water

10%poured into c means remaining 10x,x

C contained 100x acid 10x milk x water

10% poured into A

(90x+x/10) water x milk 10x acid

X=1011/10=101.1=10/1011

done

plz explain Q 3 in details

>>>TY,,,TY<<<

qs 3 ?

mere kuch or aa rha

Que-3 ?

ye kaun sa method h?

given spd

s(1) =20km/hr

s(2) =40km/hr

s(3) =120km/hr

take lcm =120

let distance =120

d(1) =d(2) =d(3) =40

now t1 +t2+t3 =20

(40/20) +(40/40)+(40/120) =20

=>10/3 =20 =>1 =6

so 120 =720 => d =720 km

Que no 9 easier way

X/12=X+300/15

X=1200

1200+300=1500 thief covered dist &police covered dist 1200km

Mam qye 3 explain

Average of 3quantity is

3*a*b*c/(ab)+(BC)+(ca) when dist is same

According to this formula

3*30*40*120/8000=36*20=720 ans ???

same

i think mam ka galat ho gaya hoga

aayat math ke liye konsa book follow karti ho ??

After travelling two hours a train met with an accident due to this it stops for an hour. After this the train moves at 66(2/3)% speed of its original speed and reaches to destination 3hour late. If the accident would occur at 200km ahead in the same line then the train reaches only 2.5hours late. Then find the distance of journey and the original speed of the train?

A) 2400km,600kmph

B) 1800km,300kmph

C) 2400km,400kmph

D) 1800km,200kmph

E) 2000km,100kmph

appka soln chahiye mam

Ye mujhe bhi nai aya try karti hu

https://uploads.disquscdn.com/images/f620f604c95c3744d6413801871e8a425600050fe0758295554522afcf64b19f.jpg

ty maam :))

2nd question smjh aya ??

2nd muze problem ho rahi hai

Qn2 —

diff of time= 3 – 2.5 = 1/2 hr

original spd = V

66 2/3% of its original spd = 2/3*V

1/2 = 200/(2V/3) – 200/V

1/2 = 200*/2V

V = 200 km/hr

let normal time = T

extra time = 3T/2 – T = T/2

T/2 = 3

T = 6 hrs

total distance = 200 + 200*6 = 1400 km

Sir ratio wale metd se kaise karenge??

ratio wale se mujhe nhi ata sorry

Ok ty

ðŸ™‚

spd ratio =2:3

=> time ratio =3:2

now 3/2 -1 =30 mins

=>1 =60mins

since in time 1 it travelled 200km

=>200 =60min=>200km/hr =spd

now again 3/2 -1 =3

=>1= 6 hrs

=>distance in 6 hrs =6*200 =1200

=> totl dist =1200+200 =1400

vgud

..:)))

dear

x/y-x/2/3*y=2…1

x/y-x+200/4y=1/2..2

solve 1&2 ye method galat hai kya?

isse to X & Y ki value hi nhi ayega

But dist &speed unknown hai to Lena hoga ??

thx got it..

ok ðŸ™‚

Qn3 —

let distance of each equal part = D

then total distance = 3D

T1 +T2 +T3 = 20

D/20 +D/40 +D/120 = 20

10D/120 = 20

D = 240

total distance = 3D = 720

ys same here

_/_

ques no 3 ka ans to optin se differ aa ra ðŸ˜›

yes ans is 200/1400

ok sir ðŸ˜› apna solution do

spd ratio =2:3

=> time ratio =3:2

now 3/2 -1 =30 mins

=>1 =60mins

since in time 1 it travelled 200km

=>200 =60min=>200km/hr =spd

now again 3/2 -1 =3

=>1= 6 hrs

=>distance in 6 hrs =6*200 =1200

=> totl dist =1200+200 =1400

thanKU :))

@@disqus_0OrBOABGUE:disqus Please dear tell me in this question , i didn’t get after 2=4 and 3=6 fir time 6 kese aaya hain

kindly explain?

6 : In covering a distance of 60km Abhi takes 2hrs more than Sam. If Abhi triples his speed

then he would take 2hrs less than Sam. Abhi speed in kmph is ?

. Abhi triples his speed

. tripleâ€¦â€¦â€¦â€¦â€¦.normal

speed 3â€¦â€¦â€¦â€¦â€¦â€¦â€¦â€¦1

time 1â€¦â€¦â€¦â€¦â€¦â€¦â€¦..3

. 3 -1 =2

2=4hrs

3=6hrs

so Abhi cover60km in 6hrs

60/6 =10kmph

see here…:)

let initial spd s(i) of abhi =1 now trippling his speed mns 1*3 =3

now ini.to increased spd ratio

s(i)————-s(c)

1—————-3

=> initial to increased time ratio

T(i)———–T(c)

3—————-1

now 2 ratio =(+2-(-2))=4 => 3 ratio = inital time = 6hrs

now ini.spd =totl dist/ini.time =60/6 =10km/h

6hrs is the initial time of abhi with which he covers 60 kms

I think the admin of this web page is really working hard

in favor of his web page, because here every material is quality based

data.

Touche. Outstanding arguments. Keep up the good effort.

Having read this I thought it was very informative. I appreciate you taking the time and energy to put this article together. I once again find myself personally spending a significant amount of time both reading and leaving comments. But so what, it was still worthwhile!

Why users still make use of to read news

papers when in this technological world the whole thing

is available on net?

It’s actually a nice and useful piece of info.

I am happy that you simply shared this helpful information with us.

Please keep us informed like this. Thanks for sharing.

Hey there, I think your blog might be having

browser compatibility issues. When I look at your blog in Opera, it looks fine but when opening in Internet Explorer,

it has some overlapping. I just wanted to give you a quick heads

up! Other then that, great blog!

Nice post. I learn something new and challenging on sites I stumbleupon every day. It will always be useful to read through content from other writers and practice a little something from other sites.

Simply wish to say your article is as astounding. The clarity in your post is simply great and i could assume you are an expert on this subject.

Fine with your permission let me to grab your RSS feed to keep

up to date with forthcoming post. Thanks a million and please carry on the rewarding work.

Pretty section of content. I just stumbled upon your web site

and in accession capital to assert that I acquire in fact enjoyed account your blog posts.

Any way I’ll be subscribing to your augment and even I achievement you access consistently fast.

Hello, I think your site might be having browser compatibility issues.

When I look at your website in Ie, it looks fine but when opening in Internet Explorer, it has some overlapping.

I just wanted to give you a quick heads up!

Other then that, terrific blog!

Somebody necessarily assist to make critically articles I would state.

This is the first time I frequented your web page and up to now?

I amazed with the analysis you made to make this particular

publish extraordinary. Fantastic task!

Simply want to say your article is as astonishing. The clearness in your post is simply excellent and i could assume

you’re an expert on this subject. Well with your permission allow me to grab your RSS feed to keep updated with forthcoming post.

Thanks a million and please continue the rewarding work.

Oh my goodness! Amazing article dude! Many thanks, However I

am encountering problems with your RSS. I don’t know why

I cannot subscribe to it. Is there anybody having the same RSS issues?

Anyone who knows the solution will you kindly respond? Thanx!!

I visited several web sites except the audio quality for

audio songs existing at this web site is in fact fabulous.

I blog quite often and I really thank you for your content.

The article has truly peaked my interest.

I’m going to bookmark your site and keep checking for

new details about once per week. I opted in for your Feed too.

Howdy! Quick question that’s entirely off topic. Do you know how to make your site

mobile friendly? My weblog looks weird when viewing from my iphone4.

I’m trying to find a template or plugin that might be able to correct this problem.

If you have any recommendations, please share. Cheers!

Pretty nice post. I just stumbled upon your weblog and wished to say that I’ve really enjoyed surfing around your blog posts.

In any case I will be subscribing to your rss feed and I hope you write again very soon!

I am genuinely pleased to glance at this weblog posts which carries plenty

of helpful data, thanks for providing these kinds

of data.

Great post. I’m experiencing a few of these issues as well..

Thank you for the auspicious writeup. It in truth was once a entertainment account it.

Glance advanced to far added agreeable from you! However, how can we keep up a correspondence?

Hi, its fastidious piece of writing on the topic of media print, we all

know media is a fantastic source of data.

Valuable info. Fortunate me I found your site accidentally,

and I am stunned why this twist of fate didn’t came about

earlier! I bookmarked it.

I visited various web pages but the audio quality for audio songs current at this

web site is in fact fabulous.

Amazing issues here. I’m very glad to see your article.

Thank you so much and I am taking a look forward to contact you.

Will you kindly drop me a e-mail?

I loved as much as you will receive carried out right here.

The sketch is attractive, your authored subject matter stylish.

nonetheless, you command get bought an impatience over that you wish be delivering the following.

unwell unquestionably come further formerly again since exactly the same nearly very often inside

case you shield this increase.

hello!,I like your writing very much! share we communicate

extra approximately your article on AOL? I require an expert in this space to

resolve my problem. May be that’s you! Having a look ahead to look you.

Iâ€™m not that much of a internet reader to be honest but your sites really nice, keep it up!

I’ll go ahead and bookmark your site to come back down the road.

Many thanks

Hey! I know this is kinda off topic but I

was wondering which blog platform are you using for this site?

I’m getting sick and tired of WordPress because I’ve had problems with hackers

and I’m looking at options for another platform.

I would be great if you could point me in the direction of a good platform.

I am in fact thankful to the owner of this site who has shared this fantastic paragraph at at this place.

Heya superb website! Does running a blog similar to

this take a large amount of work? I have very little knowledge of coding but I had

been hoping to start my own blog soon. Anyways, if you have

any ideas or techniques for new blog owners please share. I

understand this is off subject however I simply needed to

ask. Thanks a lot!

wonderful submit, very informative. I wonder why the other experts of this sector do not notice this.

You should continue your writing. I’m confident, you’ve a great readers’ base already!

My brother recommended I might like this web site.

He was entirely right. This post actually made my day. You cann’t imagine just how much time I

had spent for this information! Thanks!

Incredible points. Solid arguments. Keep up the good work.

This site was… how do you say it? Relevant!! Finally I have found something which helped me. Thank you!

I will immediately grab your rss feed as I can’t to find your e-mail

subscription link or e-newsletter service. Do you’ve any? Please permit me

recognise in order that I could subscribe. Thanks.

Oh my goodness! Impressive article dude! Thanks, However I am encountering troubles with your RSS. I donâ€™t understand the reason why I can’t join it. Is there anybody else having similar RSS issues? Anyone that knows the answer can you kindly respond? Thanx!!

Good way of describing, and nice piece of writing to obtain data regarding my presentation subject

matter, which i am going to present in institution of higher education.

Hey there, You’ve done an excellent job. I will definitely digg

it and personally recommend to my friends. I am sure they will be benefited from this site.

This is a great tip especially to those new to the blogosphere. Brief but very accurate informationâ€¦ Many thanks for sharing this one. A must read article!