Directions (1-5): Answer the questions based on the information given below:
In a certain language,
“mobiles are very good” is coded as “U6F K8E Z8Z V14T”
“department has vrs schemes” is coded as “N20U J14T D6T U6T”
“europe tax american scholar” is coded as “J14S I16O D6Y K12F”
“per capitals rupees orders” is coded as “K16T X12T H6S U12T”
- How is the word “AGGRANDIZE” coded in the given language?
K22EE20DK20FG20RNone of theseOption C
Explanation:
STEP1:
a) If the number of letters of the word is even, then first element of the code is determined by, Number of letters of word + Alphabetical number of the first letter of word =letter corresponding to resultant number.
b) If the number of letters of the word is odd, then first element of the code is determined by, Number of letters of word + Alphabetical number of the second letter of word =letter corresponding to resultant number.
STEP2: The second element of the code is twice the number of letters of that word.
STEP3: The third element of the code is the letter succeeding last letter of the word. - How is the word “BLANDISHMENT” coded in the given language?
B20UM22UN21VN24UNone of theseOption D
- How is the word “CIRCUMLOCUTION” coded in the given language?
C20UN28OO28QQ27UQ28OOption E
- How is the word “EMBEZZLEMENT OBSTREPEROUS” coded in the given language?
Q28I N21YN54T Q25UQ22U M34TNone of theseQ24U N24TOption E
- In the given paragraph, the code “P22Z ” represents which of the given words?
SOBRIETYSCURRILOUSSERENDIPITYPROSCRIBERELEGATEOption C
Directions (6-10): Answer the questions based on the information given below:
P ‘ Q implies P + Q
P : Q implies P – Q
P ! Q implies P ÷ Q
P * Q implies P * Q
- A boy travels with a speed of “s” from X to Y and returns from Y to X with speed “q” .What is the average speed of the boy over the entire journey?
2s!q/s’q2s*q/s!q2s:q/s’q2s*q/s’qnone of theseOption D
- Sheerin has a cuboid box which has length ,breadth and height which can be shown by “x”, “y” and “z” respectively.What is the formula for its total surface area?
2[(x’y) ‘ (y*z) ‘ (x*z)]2[(x*y) ‘ (y!z) ‘ (x*z)]2[(x:y) ‘ (y*z) ‘ (x:z)]2[(x*y) ‘ (y*z) ‘ (x*z)]None of theseOption D
- Answer the questions based on the information given below:
If ” @ ” indicates either ” +” or ” * ” , solve the following questions. What is the maximum value of 1@2@3@4@5@6@7 ?45145041940158748255Option B
Use multiplication between 2 to 7 and then use addition between 1 and 2. we will get 5041 - What is lowest value of 1@2@3@4 ?
8101211None of theseOption E
Use multiply between 1 and 2 and addition between 2,3 and 4. It will give 9. - If
P implies “+” ,
Q implies ” – ” ,
R implies ” * ” ,
S implies ” / ” ,
then calculate value of expression 3P4Q5R6S1 ?– 27– 2122.5– 23None of theseOption D
3 + 4 – 5 * 6 / 1 =3 + 4 – 5 * 6 = 3 + 4 -30 = – 23
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