Mixed Reasoning Questions for Prelims Exams – Set 10

The expected Miscellaneous questions for SBI PO Prelims Exam

Directions (1-2): Point B is 6 m east of point A. Point C is 4 m east of point D. Point H is 6 m west of point G. Point D is 6 m north of point E. Point C is 5 south of point B. Point G is 3 m north of point F. Point E is 10 m west of point F.

1. Find distance AH.
   A) 17 m
   B) 10 m
   C) 12 m
   D) 15 m
   E) Cannot be determined
   
   View Answer

    Option B
   Solution:
   Vertical distance = BC + [DE – GF] = 5 + [6-3] = 8 m
   Horizontal distance = AB = 6
   So AH = √(8² + 6²) = 10 m
2. A person starts walking from Point C in east direction. After walking for 7 m, he takes left turn and reaches point P which is east of point B. Next he takes right turn and walks for 4 m and takes a right turn again. He goes straight, takes a right turn and reaches point G. Find the distance travelled by him.
   A) 24 m
   B) 25 m
   C) 27 m
   D) 26 m
   E) 28 m
   
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    Option C
   7 + 5 + 4 + (5+3) + 5 = 29m

Directions (3-4): Point A is 5 m north of point B. Point D is 8 m north of point C which is 6 m east of point B. Point F is 3 m west of point G. Point D is 4 m west of point E. Point I is 9 m west of point H which is 5 m south of point G. Point E is 6 m north of point F.

3. Find distance AI.
   A) 2√6 m
   B) 4√6 m
   C) 2√5 m
   D) 4√5 m
   E) Cannot be determined
   
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    Option D
   Vertical distance = AB + [GH – (DC – EF)] = 5 + [5 – (8-6)] = 8 m
   Horizontal distance = BC – [IH – (DE+FG)] = 6 – [9 – (4+3)] = 4 m
   So IA = √(8² + 4²) = 4√5 m
4. A person starts from point C in south direction, walks for 8m, takes a left turn, walks for some distance, takes a left turn again to reach point H. Find the distance travelled by him.
   A) 23 m
   B) 22 m
   C) 21 m
   D) 20 m
   E) Cannot be determined
   
   View Answer

    Option C
   Solution:
   8 + (DE+FG) + 6 = 8 + (4+3) + 6 = 21m
   

Directions (5-7): N is brother of D. A is married to C. A is father of P. M Is mother-in-law of L. K is father of T. S is sister of K. P is sister of Q. D is grandfather of Q. M is married to D.

5. How is S related to T?
   A) Sister
   B) Mother
   C) Uncle
   D) Aunt
   E) None of these
   
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    Option D
   Solution:
   S is sister of K and K is father of T. So S is aunt of T.
   
6. If L is married to K, then how is A related to T?
   A) Aunt
   B) Uncle
   C) Sister
   D) Mother-in-law
   E) Cannot be determined
   
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    Option B
   Solution:
   A is father of P. P is sister of Q. D is grandfather of Q. So D is father of A and then M is mother of A.
   M Is mother-in-law of L. and L is married to K and K is father of T.
   So A is brother of K and since K is father of T. So A is uncle of T
   
7. If L is married to K and J is married to S, then how is J related to D?
   A) daughter-in-law
   B) aunt
   C) daughter
   D) son-in-law
   E) A) or D)
   
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    Option D
   S is the sister so J is male so is son-in-law of D    

Directions (8-10): Seven friends in a class got different marks in a test. Nobody got same marks. E got more marks than A but not the greatest. C got less marks than D and more than F. G got more than D. Nobody got marks between A and D. Marks of A is lesser than that of D. B got more marks than only 1 friend. G got 98 marks and the one who is 3^rd from below got 76 marks.

8. If E got 95 marks, then find the total marks of E and C.
   A) 173
   B) 170
   C) 169
   D) 172
   E) 171
   
   View Answer

    Option E
   Solution:
   The order in increasing order of marks – F, B, C(76), A, D, E, G(98)
   So E+C = 95+76 = 171
9. If D got 86 marks, then what could be the marks of A?
   A) 88
   B) 85
   C) 73
   D) 74
   E) 90
   
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    Option B
   Solution:
   If will be between 76 and 86
   
10. If B got 75 marks, then what could be the total maximum score of B and E?
    A) 172
    B) 173
    C) 170
    D) 171
    E) 174
    
    View Answer

     Option A
    Solution:
    G has 98 marks, so E can have a maximum of 97 marks. So B+E = 75+97 = 172