Quantitative Aptitude: Time and Work Set 3

 Time and Work Problems with tricks for SBI PO, IBPS PO, NIACL, NICl, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

  1. A and B can do a piece of work in 25 days. B and C can do the same piece of work in 30 days. C and A can do the same work in 37.5 days. In how many days will A alone do the same work?
    A) 100 days
    B) 60 days
    C) 50 days
    D) 75 days
    E) None of these
    View Answer
    Option B
    Solution
    :
    A+B =25 ————6 (1 days work) [total=150]
    B+C =30————-5 (1 days work)
    C+A =37.5———–4(1 days work)
    Total = LCM of 25,30,37.5
    1 day work=total work/days
    adding the three equation
    2(A+B+C) = 15
    A+B+C 1 day work = 7.5
    A+B+C – (B+C) =7.5 – 5 = 2.5
    A =150/2.5 = 60 days
  2. A and B started a work together and after 7 days A left the work and B did the remaining work in 56 days. Then find in how many days A alone can do the same work if A and B together can do the work in 21 days.
    A) 30 days
    B) 27 days
    C) 28 days
    D) 29 days
    E) None of these
    View Answer
    Option C
    Solution
    :
    A+B=21 days
    Let total work = 21
    A+B 1 day work = 1
    7 day work = 7
    remaining work = 21-7 = 14
    B did 14 work in 56 days
    1 work in 4 days
    21 work in 84 days
    A+B = 21
    B = 84 hence A will be 28
  3. 12 men can do a work in X days and 18 women can do the same work in (X+2) days. If the ratio of 18 men and 36 women work in same time is 9:10 then find the value of X
    A) 10 days
    B) 12 days
    C) 18 days
    D) 15 days
    E) None of these
    View Answer
    Option A
    Solution
    :
    18 men work/36 women work = 9/10
    To get 1 men work/1 women work divide 9 by 18 and 10 by 36
    1 men work/1 women work = (9/18)/(10/36)
    = 18 : 10
    Now multiply by 12*18 and 18*10 (no. of men and women as given in ques 12 men and 18 women)
    12*18 : 18*10 = 6 : 5 (This is the ratio of work)
    Hence ratio of days = 5 : 6
    difference => 1 = 2
    hence 5 = 10 days
  4. Ram and Shyam can complete an assignment of data entry in 6 days. If Ram is 60% of Shyam’s speed and the total key depression in the assignment are 96000, What is Ram’s speed in key depression per hour if they work for 10 hour daily?
    A) 300
    B) 600
    C) 400
    D) 1000
    E) None of these
    View Answer
    Option B
    Solution
    :
    Ram : Shyam = 3:5
    multiply the ratio with 60 (day*hour) i.e.6*10
    Ram : Shyam = 180 : 300
    Total = 480 = 96000
    1 = 200
    3 = 600
  5. If 32 men and 24 women can do a work in 2 days and 13 men and 18 women can do the same work in 4 days then find in how many days will 11 men do the work?
    A) 16 days
    B) 8 days
    C) 4 days
    D) 12 days
    E) None of these
    View Answer
    Option B
    Solution
    :
    32 M +24 W = 2
    => 64M+48 W = 1 day —— (i)
    13 M + 18 W = 4 day
    => 52 M + 72 W = 1 day—–(ii)
    using (i) and (ii)
    1 M = 2W
    put it in eq 1
    1 M = 88
    =>11 men = 8 days
  6. 2 men or 4 women or 6 boys can do a work in 22 days. Find in how many days will 1 men, 1 women and 1 boy together can do the work?
    A) 22 days
    B) 12 days
    C) 24 days
    D) Cannot be determined
    E) None of these
    View Answer
    Option C
    Solution
    :
    2M = 22=——- 1 (1 day work—total work =22)
    4W = 22———1
    6B = 22———-1
    2M = 1 work => 1 M = 1/2 work
    1 W = 1/4 work
    1B = 1/6 work
    1 M + 1W +1B = 1/2+1/4+1/6 = 11/12 work
    days required = 22/(11/12) = 24 days
  7. A is 50% more efficient than B. If A can do a work in 30 days, then find in how many will C do the work if C is 20% efficient of A and B together?
    A) 15 days
    B) 30 days
    C) 20 days
    D) 10 days
    E) None of these
    View Answer
    Option D
    Solution
    : B= 50% more efficient than A
    hence A:B=150:100=3:2=30:20 (in terms of day)
    A+B = 5
    C = 20% = 1/5
    C = 1
    1 = 10
    A : B : C = 3 : 2 : 1
    C = 1 = 10 days
  8. A contract is given to 40 person to do a work in 45 days. After 25 days it is found that only half work is done, then find how many more persons are required to complete the work on time?
    A) 10
    B) 15
    C) 20
    D) 8
    E) None of these
    View Answer
    Option A
    Solution
    :
    (40*25)/(1/2) = (x+40)*20 /(1/2)
    x=10
  9. A pipe can fill a cistern in 140 mins and B pipe can fill it in 105 mins. They are opened together but due to a leakage they take 10 min more to fill the tank. Find in how many minutes will leakage empty the tank?
    A) 240 mins
    B) 360 mins
    C) 420 mins
    D) 210 mins
    E) None of these
    View Answer
    Option C
    Solution
    :
    A=140————3 (total=420)
    B=105————4
    A+B=420/7=60 mins
    A+B+leakage=70 mins
    420/70=6 (1 mins work)
    7-6=1
    leakage=420/1=420 mins
  10. In a tank theer are 3 inlet pipes A,B and C. A can fill the tank 1.5 times faster than B. B can fill the tank in half time taken by C and tank C is 3 times less efficient as A.There is one outlet pipe D which can empty the tank in 10 mins and the time taken by D is half of the time taken by A. Find in how much time will A and B together fill the tank?
    A) 12 mins
    B) 15 mins
    C) 10 mins
    D) 20 mins
    E) None of these
    View Answer
    Option A
    Solution
    :
    —————A:B
    Work——–3:2
    Days———2:3
    B is half of C, hence C=6
    A:B:C=2:3:6 = 20:30:60
    time =D:A=1:2=10:20
    A=20
    B=30
    A+B=12 mins

 

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22 Thoughts to “Quantitative Aptitude: Time and Work Set 3”

  1. Deepak sahu

    mam 7th question ka answer 90 days aayega plz check kariye

    1. Jellyfish

      Frds…
      ……A…..B
      Eff.2….3
      W..3…2
      A work 30 means B work 20days
      Now
      …A+B…..C
      EF..5..6
      Wk.. 6..5
      Hence
      A+B=12
      C=10 days

      1. Oliver Queen

        bhai A 50% jyda efficient hai to B se kam din work karega to B ka 20 days kaise?
        A=30 days
        B 45 days
        apka ans galata hai

        1. Jellyfish

          Bro
          2:3 eff hair work inversely proportional hoga
          3:2

          1. Oliver Queen

            yep it will proportional
            then B should take 45 days to complete the whole work
            but you have taken 20 days for B

          2. jaga

            hn bhai u r right…

      2. PHENOMENAL

        c=6 kha se aya

  2. Jellyfish

    7/10 ty
    Question no 3 explain pls..

    1. Use this

      18 men’s 1 day work is 9
      Then
      1 man’s 1 day work = 9/18

      M1 × W2 = M2 × W1
      W2 = 9/18

  3. sachin shukla@ my turn 2017

    ty..

  4. purvi

    thanku mam 🙂

  5. Oliver Queen

    Ma’am ques-6 mein 24 4/31 hon chahie

    1. Oliver Queen

      ma’am qus 7 bhi galat hai
      B ka 45 days hoga na ki 20 days kyun ki A jyda efficient hai b se

        1. PHENOMENAL

          plzz xplain 7 ques how C= 1=10

          1. A+B = 5
            C = 20% of A+B = 1/5 of A+B
            So S = 1/5 * 5 = 1

            no need to take 1 = 10 step here, given by mistake

            A : B = 3 : 2
            now C = 1

            A : B : C = 3 : 2 : 1

          2. AB

            eff A = 3
            time taken by A = 30 days
            total work = 90
            eff of C = 1
            C takes 90 days …………. how 10 days maam ?
            A is 50% more efficient than B. If A can
            do a work in 30 days, then find in how many will C do the work if C is
            20% efficient of A and B together?

            A) 15 days

            B) 30 days

            C) 20 days

            D) 10 days

            E) None of these
            wordings bahut confusing ho rha maam

    2. 6th ka 24 hi hai
      2 men in 22 days. So 1 in 44 days
      1 w in 88 days
      1 b in 132 days
      Required ans = 1/22 + 1/88 + 1/132 = 11/264 = 1/24
      24 days

      1. Oliver Queen

        haan right
        mujhse typo* ho gayi thi to 24 somthing aa rha tha

  6. jaga

    mam q7 ka ans 15 hoga

  7. jaga

    thank u mam 🙂

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