Quantitative Aptitude: Time and Work Set 6

Time and Work Questions tricks Examples IBPS/SBI PO, NIACL, NICl, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

1. A and B can do a piece of work in 25 days and 50 days respectively. If they start working together and a person C alone does the work for last 4 days then work is done in 14 days. Find in how many days C can do the work alone?
   A) 8 days
   B) 10 days
   C) 20 days
   D) 25 days
   E) 15 days
   
   View Answer

   Option B
   Solution:
   A=25 ———– 2 (Total work=50)
   B=50———— 1
   A+B = ———-3
   A and B did the work for 14-4=10 days
   (A+B)*10=3*10= 30 work
   remaining work=50-30=20
   C did 20 work in 4 days;
   1 day = 5 work
   so 50 work in 10 days
   
2. A and B can do a work in 60 days, B and C can do a work in 40 days and C and A can do the same work in 50 days. Find in how many days they together can complete the work?
   A) 32 (16/37) days
   B) 42 (16/37) days
   C) 32 (16/27) days
   D) 42 (16/27) days
   E) 32 (16/17) days
   
   View Answer

   Option A
   Solution:
   A+B =60 ———————– 10 (Total Work = 600)
   B+C =40 ———————– 40
   C+A = 50 ———————–12
   2 (A+B+C)= ——————–37
   A+B+C = 37/2
   600*2/37= 32 (16/37)
   
3. 1 man or 2 women or 3 children can do a work in 66 days. Find in how many days 1 man and 1 women and 1 child can do the same work?
   A) 24 days
   B) 28 days
   C) 30 days
   D) 36 days
   E) 38 days
   
   View Answer

   Option D
   Solution:
   1 M ——–66 ——1 (Total Work=66)
   2 W———66——-1
   3 C ———-66——-1
   1 day work of 1 M + 1W + 1 C=1 +1/2 +1/3 =11/6
   66/ (11/6)= 36 days
   
4. A and B can do a job in 25 days. They started working together and after 10 days B left the work. Then A did the remaining work in 60 days. Then find in how many days B alone can do the same work?
   A) 30 days
   B) 33 (1/3) days
   C) 40 days
   D) 45 days
   E) 47 days
   
   View Answer

   Option B
   Solution: Let total work =25
   1 day work of A and B =1
   Remaining work after 10 days= 25-10=15
   B do 15 work in 60 days
   means 25 work in 60*25/15=100 days
   A+B = 25 ———4 (Total Work= 10)
   B =100————1
   A=—————- 4-1=3
   B=100/3
   
5. A tap can fill a tank in 30 minutes. But due to leakage in tank it takes 36 minutes to fill the tank. If leakage point withdraws 20 litre water every minute then find the capacity of tank.
   A) 2400 litre
   B) 3000 litre
   C) 3600 litre
   D) 4000 litre
   E) 4500 litre
   
   View Answer

   Option C
   Solution: Let leakage = B
   A= 30 ———-6 (Total =180)
   A+B=36 ——5
   B= ——– (6-5=1)
   B will empty the tank in 180 minutes (1=180)
   capacity =180*20= 3600 litres
   
6. A and B can do a work in 40 days and 60 days respectively. They start work together and work for 15 days then C joins them and they finish the work in 20 days. If they get total wage of Rs 720 then find the share of C.
   A) Rs 100
   B) Rs 240
   C) Rs 360
   D) Rs 120
   E) Rs 150
   
   View Answer

   Option D
   Solution:
   A=40 ———– 3 (Total = 120)
   B=60 ————2
   A+B=————-5
   In 15 days =5*15=75 work
   45 remaining which is completed in 5 days, means
   1 day work of A, B and C is 9
   1 day work of C=9-5=4
   5 day work of C=20
   ratio of wages A:B:C = 60(3*20) : 40(2*20) : 20=3:2:1
   Share of C= 1/6*720=120
   
7. 5 men and 7 women can complete a work in 13 days while 4 men and 6 women can complete it in 16 days. Find in how many days will 2 men and 6 women complete the work?
   A) 24 days
   B) 22 days
   C) 20 days
   D) 28 days
   E) 26 days
   
   View Answer

   Option E
   Solution:
   5 M + 7W = 13 days
   65 M + 91 W = 1 day………….(1)
   4 M + 6 W = 16 days
   64 M + 96 W = 1 day………….(2)
   From (1) and (2)
   1 M = 5W
   Put in 1, 5M = 25W
   So 25W + 7W = 13 days
   32 W = 13
   1 W = 13*32 days
   So 16 W = 13*32/16 = 26 days
8. In a camp, there is a food for 400 students for 30 days but after 20 days, 200 students left. For how many more days the food will last now?
   A) 10 days
   B) 30 days
   C) 40 days
   D) 20 days
   E) 5 days
   
   View Answer

   Option A
   Solution:
   400*30 = 400*20 + (200*x)
   12000 = 8000 + 200x
   Solve, x = 20 days
   Total days = 20+20 = 40 days
   More days = 40-30 = 10 days
   
9. A group of men decided to do a work in 10 days but five of them did not come. If the rest of the group completed the work in 12 days, find the original number of men.
   A) 24
   B) 22
   C) 30
   D) 28
   E) 26
   
   View Answer

   Option C
   Solution:
   x*10 = (x-5)*12
   Solve, x = 30 men
10. A is thrice good a workman as B and B is half as good as workman as C. Find the ratio of days in which A, B and C can complete work alone respectively.
    A) 3 : 6 : 2
    B) 2 : 6 : 3
    C) 2 : 5 : 3
    D) 4 : 6 : 3
    E) 1 : 2 : 4
    
    View Answer

    Option B
    Solution:
    efficiency         A  :  B                B  :  C
    .                       3  :  1                1  :  2
    Efficiencies  A  :  B  :  C = 3 : 1 : 2
    So days== 1/3 : 1/1 : 1/2 = 2 : 6 : 3

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