Quantitative Aptitude: Time, Speed and Distance Set 7

Time Speed Distance Questions for NICL, SBI PO, IBPS PO, NIACL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

  1. A man covers a distance in 10hrs and in three equal parts. The speed is 10kmph, 20kmph and 60kmph respectively. Find the distance?
    A) 240km
    B) 300km
    C) 150km
    D) 180km
    View Answer
    Option D
    Solution:

    Distance = speed * time
    Here we need average speed. So average speed will come 18kmph
    Distance = 18*10 = 180km
  2. Two persons covers same distance at 42kmph and 48kmph respectively. They find that the slower one takes 30minutes more to cover the distance. Find the distance cover by them?
    A) 150km
    B) 168km
    C) 200km
    D) 224km
    View Answer
    Option B
    Solution:

    Speed:
    42 : 48
    7 : 8
    Time 8 : 7
    .        (+1)
    1=30
    8=240minutes = 4hrs
    Distance = speed * time
    = 42*4
    = 168km
  3. Two persons goes from A to B at 12kmph and 8kmph. The faster one reach B first and come back. He meets slower one at a point R. find the distance between A & R if the distance between A to B is 20km?
    A) 12km
    B) 24km
    C) 16km
    D) 18km
    View Answer
    Option C
    Solution:

    it is clear that both person covers double distance .
    So 2*20/(12+8) =2hrs
    Slower one covers 8*2 = 16km
    In that time in which father one covers 12*2 =24km
    So 16km is ans
  4. Two trains are running on a parallel track in same direction. Train A comes from behind and overtake train B in 60seconds. One person in train A observes that he covers train B in 40seconds. If the speed of trains in the ratio of 3:1, then find the ratio of length of train A & B?
    A) 1:3
    B) 3:2
    C) 2:3
    D) 1:2
    View Answer
    Option D
    Solution:

    In this question speed doesn’t matter because we know …..length = speed*time. Speed remains same in both cases so it will cancel out.
    Now length of A+B =60unints
    Length of B = 40 units
    Length of A = 60-40 =20units
    A : B
    20 : 40
    1 : 2
  5. If a person cover a distance in 5/7th of his normal speed, then he will reach his destination 20minutes late. Find the usual time taken by him on his normal speed?
    A) 100min
    B) 50min
    C) 140min
    D) 70min
    View Answer
    Option B
    Solution:

    Shortcut : multiply numerator by time/difference
    Difference = 7-5 =2
    Time = 20
    5*20/2 = 50min
  6. A man cover a distance in t hrs, if he met with an accident after 20km and he then run at his 3/5th of his normal speed, so he reach his destination 40minutes late. If he met with an accident at 30km then he reach only 30min late. Find his original speed?
    A) 60kmph
    B) 50kmph
    C) 40kmph
    D) 24kmph
    View Answer
    Option C
    Solution:

    After moving 10km more, man saves 10minutes. For saving of 40minutes he has to cover 40km.
    Now speed:   after accident            before accident
    .                             3                                5
    Time                      5                                3
    .                                            (+2)
    2=40minutes
    1=20min
    (Normal time) 3= 60min
    So he covers 40km in 60min with normal speed = 40kmph
  7. A thief steal a car at 1pm and run at a speed of 80kmph. The theft discovered at 2pm and police run behind him at a speed of 100kmph. Find at what time police will catch the theif?
    A) 6pm
    B) 7pm
    C) 8pm
    D) 5pm
    View Answer
    Option A
    Solution:

    The thief cover 80km in 1hr.
    Time – 80/(100-80) = 4hrs.
    So – 2pm+4 = 6pm
  8. A boat travels upstream from Q to P and downstream from P to Q in 3hrs. if the distance between P to Q is 4km and the speed of the stream is 1kmph, then what is the speed of the boat in still water?
    A) 4.5kmph
    B) 5.2kmph
    C) 2.5kmph
    D) 3kmph
    View Answer
    Option D
    Solution:

    Go with options
    4/(3+1) + 4/(3-1) = 3hr
    Only option D satisfy
  9. A boat covers 12km upstream and 18km downstream in 3hrs. while it covers 36km up stream and 24km downstream in 6(1/2) hrs. find velocity of the stream?
    A) 1.5kmph
    B) 1kmph
    C) 2kmph
    D) 2.5kmph
    View Answer
    Option C
    Solution:

    12/y + 18/x =3…………..(1)
    36/y + 24/x = 13/2……………(2)
    By solving above equation we will get
    X=12kmph, y = 8kmph
    Speed of stream = (12-8)/2 = 2kmph
  10. Two person A & B with speed of 30kmph and 40kmph comes towards each other. When they meet it is find that faster one cover 30km more than slower one, find the distance cover by train?
    A) 210km
    B) 240km
    C) 280km
    D) 300km
    View Answer
    Option A
    Solution:

    Faster train cover 10km more in every hour. So for 30km the train has to run for 3hrs.
    Distance = (30+40) *3
    = 210km

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25 Thoughts to “Quantitative Aptitude: Time, Speed and Distance Set 7”

  1. $~$PrAdeEP$K$~$~$

    …:)))

  2. $~$PrAdeEP$K$~$~$

    mam /sir explain the short trick used in que 6 frm were 40 is comming mam…;)))

    1. Which step u dint get?

      1. $~$PrAdeEP$K$~$~$

        40 is coming from were i got 40 ans by basic method but from the short trick given i cant figure it out…:)) mam….:)

        1. See. 20 km and 30 km. And 40 mins late and 30 minutes late
          Means is 10 km (30-20)me 10 minutes (40-30) save hue

          Ab 40 mins late ya 30 mins late kuch b lelo.
          Yahn 40 mims late liya hai.
          To 40 mins me 40 km save honge.

          Ab speed = 3/5
          3……5
          Time reciprocate ho jata hai distance same hai to.
          So time.
          5…….3……(1)
          Yahn +2
          This +2 time = 40 mins
          1 = 20.
          And actual time 3 tha na before accident (1) se
          So 3 == 60
          so 40 km in 60 min is 40km/hr

          1. $~$PrAdeEP$K$~$~$

            okk mam…:))

  3. Misha

    6th ques and ans samaj nh aaya hh……. plz elaborate it

    1. See. 20 km and 30 km. And 40 mins late and 30 minutes late
      Means is 10 km (30-20)me 10 minutes (40-30) save hue

      Ab 40 mins late ya 30 mins late kuch b lelo.
      Yahn 40 mims late liya hai.
      To 40 mins me 40 km save honge.

      Ab speed = 3/5
      3……5
      Time reciprocate ho jata hai distance same hai to.
      So time.
      5…….3……(1)
      Yahn +2
      This +2 time = 40 mins
      1 = 20.
      And actual time 3 tha na before accident (1) se
      So 3 == 60
      so 40 km in 60 min is 40km/hr.

      Got now ?

      1. Arun v Kumar

        Mam if we consider the second equation how this works ie if +2=30 and then the equation will lead to an another answer pls help and to save 40 minutes he has
        to travel 40km then total km will be 60km these r my doubts

        1. See:::

          If we take +2 = 30::

          2=30minutes
          1=15min
          (Normal time) 3= 45min
          So he covers 30km in 45min with normal speed = 30 * 60/45 = 40kmph

          Same answer

          Got now ??

          1. Arun v Kumar

            thanks a lot, now i understood this trick……

      2. Misha

        Thank u mamm…

  4. Marry..

    18 kaise aya 1st que..?

    1. aayat

      avg speed=3xyz/xy+yz+zx
      s=36000/2000=18

    2. AMAZON

      @@Shubhra_AspirantsZone:disqus mam 18 kse aaya 1st me?

  5. Sachin Shukla

    ty:))

  6. Ak$hita $inghal

    pls explain q4?

    1. aayat

      A+B/60=B/40
      40A+40B=60B
      40A=20B
      A/B=20/40=1/2

  7. Ravi Upadhyay

    thnx.. gud question

  8. Ruchiie

    Mam 6 n 10 ni aya

  9. Sudipta Basak

    Mam
    In question no 4
    Why B is 40 unit??
    Plz explain..

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