Quant Sectional Test 1 for SBI PO 2017 Prelim Exam

Hello Aspirants

We are providing you with Quant Section Mock for the upcoming SBI PO 2017 Prelim Exam. It contains 35 questions and time limit is 25 minutes.

To start the mock, click on start quiz button below. To end the quiz, click on Quiz-Summary after the last question and then click on finish quiz.

Share your marks in the comment section below.
You can take this quiz as many times you want.
If you find any mistake, please tell us in the comment section.

Time limit: 0

0 of 35 questions completed

Questions:

Information

You have already completed the quiz before. Hence you can not start it again.

quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

Congratulations!!!" SBI Pre - Quant 1 "

0 of 35 questions answered correctly

Your time:

Time has elapsed

Your Final Score is : 0
You have attempted : 0
Number of Correct Questions : 0 and scored 0
Number of Incorrect Questions : 0 and Negative marks 0

Average score
Your score

Not categorized
You have attempted: 0
Number of Correct Questions: 0 and scored 0
Number of Incorrect Questions: 0 and Negative marks 0

Your result has been entered into toplist

Name: E-Mail:

Captcha:

maximum of 35 points
Pos.	Name	Entered on	Points	Result
Table is loading
No data available

Answered
Review

Question 1 of 35

1. Question
1 points
Directions (1-5): What will come in place of question mark (?) in the following number series?

3, 6, 20, 56, 125, ?
- 167
- 282
- 238
- 133
- 276
Correct

Incorrect

Unattempted
Question 2 of 35

2. Question
1 points
Directions (1-5): What will come in place of question mark (?) in the following number series?

4, 6, 16, 56. 240, ?
- 1232
- 1067
- 1218
- 1108
- 1099
Correct

*1 + 2, *2 + 4, *3 + 8, *4 + 16, *5 + 32

Incorrect

*1 + 2, *2 + 4, *3 + 8, *4 + 16, *5 + 32

Unattempted

*1 + 2, *2 + 4, *3 + 8, *4 + 16, *5 + 32
Question 3 of 35

3. Question
1 points
Directions (1-5): What will come in place of question mark (?) in the following number series?

100, 122, 148, 178, ?, 250
- 269
- 319
- 298
- 212
- 243
Correct

Consecutive number are:
10² + 0², 11² + 1², 12² + 2², 13² + 3², 14² + 4², 15² + 5²

Incorrect

Consecutive number are:
10² + 0², 11² + 1², 12² + 2², 13² + 3², 14² + 4², 15² + 5²

Unattempted

Consecutive number are:
10² + 0², 11² + 1², 12² + 2², 13² + 3², 14² + 4², 15² + 5²
Question 4 of 35

4. Question
1 points
Directions (1-5): What will come in place of question mark (?) in the following number series?

12, 6, 10, 28, 104, ?
- 542
- 360
- 478
- 456
- 345
Correct

12*0.5 + 0 = 6
6*1.5 + (0+1) = 10
10*2.5 + (1+2) = 28
28*3.5 + (3+3) = 104
104*4.5 + (6+4) = 478

Incorrect

12*0.5 + 0 = 6
6*1.5 + (0+1) = 10
10*2.5 + (1+2) = 28
28*3.5 + (3+3) = 104
104*4.5 + (6+4) = 478

Unattempted

12*0.5 + 0 = 6
6*1.5 + (0+1) = 10
10*2.5 + (1+2) = 28
28*3.5 + (3+3) = 104
104*4.5 + (6+4) = 478
Question 5 of 35

5. Question
1 points
Directions (1-5): What will come in place of question mark (?) in the following number series?

4, 10, 22, 46, 94, ?
- 215
- 202
- 165
- 178
- 190
Correct

*2 + 2, *2 + 2, *2 + 2, *2 + 2, *2 + 2.

Incorrect

*2 + 2, *2 + 2, *2 + 2, *2 + 2, *2 + 2.

Unattempted

*2 + 2, *2 + 2, *2 + 2, *2 + 2, *2 + 2.
Question 6 of 35

6. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)

2/9 × 1136 + 19.99 × 17.09 – √290 = ?
- 525
- 556
- 512
- 575
- 598
Correct

2/9 × 1134 + 20 × 17 – √289

252 + 340 – 17 = 575

Incorrect

2/9 × 1134 + 20 × 17 – √289

252 + 340 – 17 = 575

Unattempted

2/9 × 1134 + 20 × 17 – √289

252 + 340 – 17 = 575
Question 7 of 35

7. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)

19.96% of 239.9 – 15.01% of 179.89 = ?% of 299.9
- 9
- 7
- 11
- 6
- 13
Correct

Incorrect

Unattempted
Question 8 of 35

8. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)

√1935 + 13.03 × 24.98 = ? + 10.9% of 2239.9
- 176
- 144
- 102
- 123
- 188
Correct

Incorrect

Unattempted
Question 9 of 35

9. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)

2434.07 – 846.89 + 27.04 × 15.92 = ? + 1567.9
- 460
- 450
- 470
- 440
- 430
Correct

Incorrect

Unattempted
Question 10 of 35

10. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)

23.99% of 149.78 + 45.79% of 250.07 = (?)² – 1700 ÷ 23
- 27
- 11
- 21
- 18
- 15
Correct

Incorrect

Unattempted
Question 11 of 35

11. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:

What is the number of males in department C?
- 187
- 174
- 171
- 168
- 162
Correct

6/13 * 26/100 * 1450 = 174

Incorrect

6/13 * 26/100 * 1450 = 174

Unattempted

6/13 * 26/100 * 1450 = 174
Question 12 of 35

12. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:

Females in department D is what percent less than the males in department B?
- 22.65%
- 25.23%
- 30.87%
- 27.48%
- 28.57%
Correct

Females in D = 5/8 * 16/100 * 1450 = 145
Males in B = 7/12 * 24/100 * 1450 = 203
So required % = (203-145)/203 * 100 = 28.57%

Incorrect

Females in D = 5/8 * 16/100 * 1450 = 145
Males in B = 7/12 * 24/100 * 1450 = 203
So required % = (203-145)/203 * 100 = 28.57%

Unattempted

Females in D = 5/8 * 16/100 * 1450 = 145
Males in B = 7/12 * 24/100 * 1450 = 203
So required % = (203-145)/203 * 100 = 28.57%
Question 13 of 35

13. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:

In department E, if 50% of males and 60% of females are married, then what is the number of unmarried employees in department E?
- 189
- 112
- 190
- 145
- 209
Correct

Unmarried Males in E = 50% of 6/11 * 22/100 * 1450 = 87
Unmarried Females in E = 40% of 5/11 * 22/100 * 1450 = 58
So unmarried employees = 87 + 58 = 145

Incorrect

Unmarried Males in E = 50% of 6/11 * 22/100 * 1450 = 87
Unmarried Females in E = 40% of 5/11 * 22/100 * 1450 = 58
So unmarried employees = 87 + 58 = 145

Unattempted

Unmarried Males in E = 50% of 6/11 * 22/100 * 1450 = 87
Unmarried Females in E = 40% of 5/11 * 22/100 * 1450 = 58
So unmarried employees = 87 + 58 = 145
Question 14 of 35

14. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:

Total number of female employees is what percent of total number of male employees in the company?
- 86.9%
- 92.3%
- 81.7%
- 98.5%
- 102.2%
Correct

Employees in
A = 174, Male employees = 2/3 * 174 = 116, Female employees = 58
B = 348, Male employees = 7/12 * 348 = 203, Female employees = 145
C = 377, Male employees = 6/13 * 377 = 174, Female employees = 203
D = 232, Male employees = 3/8 * 232 = 87, Female employees = 145
E = 319¸ Male employees = 6/11 * 319 = 174, Female employees = 145
Total male employees = 754
Total female employees = 696
So required % = 696/754 * 100 = 92.3%

Incorrect

Employees in
A = 174, Male employees = 2/3 * 174 = 116, Female employees = 58
B = 348, Male employees = 7/12 * 348 = 203, Female employees = 145
C = 377, Male employees = 6/13 * 377 = 174, Female employees = 203
D = 232, Male employees = 3/8 * 232 = 87, Female employees = 145
E = 319¸ Male employees = 6/11 * 319 = 174, Female employees = 145
Total male employees = 754
Total female employees = 696
So required % = 696/754 * 100 = 92.3%

Unattempted

Employees in
A = 174, Male employees = 2/3 * 174 = 116, Female employees = 58
B = 348, Male employees = 7/12 * 348 = 203, Female employees = 145
C = 377, Male employees = 6/13 * 377 = 174, Female employees = 203
D = 232, Male employees = 3/8 * 232 = 87, Female employees = 145
E = 319¸ Male employees = 6/11 * 319 = 174, Female employees = 145
Total male employees = 754
Total female employees = 696
So required % = 696/754 * 100 = 92.3%
Question 15 of 35

15. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:

If after a year the percentage of employees in each department remain same, and the total employees increase by 1000, then which of the following is true?
- New number of employees in department B = Old number of employees in department C
- New number of employees in department A = 5% more than old number of employees in department A
- Old number of employees in department B = 100 + New number of employees in department D
- Old number of employees in department E = New number of employees in department C – 85
- All are true
Correct

New number of employees = 1000 + 1450 = 1550
Old number of employees in department B = 348
and New number of employees in department D = 16/100 * 1550 = 248
So C option is true

Incorrect

New number of employees = 1000 + 1450 = 1550
Old number of employees in department B = 348
and New number of employees in department D = 16/100 * 1550 = 248
So C option is true

Unattempted

New number of employees = 1000 + 1450 = 1550
Old number of employees in department B = 348
and New number of employees in department D = 16/100 * 1550 = 248
So C option is true
Question 16 of 35

16. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

I. 3x² + 19x + 28 = 0,
II. 2y² + 7y + 6 = 0
- x > y
- x < y
- x ≥ y
- x ≤ y
- x = y or relation cannot be established
Correct

Explanation:
3x² + 19x + 28 = 0
3x² + 12x + 7x + 28 = 0
Gives x = -4, -7/3
2y² + 7y + 6 = 0
2y² + 4y + 3y + 6 = 0
Gives y = -2, -3/2
Put on number line
-4…. -7/3…. -2…. -3/2

Incorrect

Explanation:
3x² + 19x + 28 = 0
3x² + 12x + 7x + 28 = 0
Gives x = -4, -7/3
2y² + 7y + 6 = 0
2y² + 4y + 3y + 6 = 0
Gives y = -2, -3/2
Put on number line
-4…. -7/3…. -2…. -3/2

Unattempted

Explanation:
3x² + 19x + 28 = 0
3x² + 12x + 7x + 28 = 0
Gives x = -4, -7/3
2y² + 7y + 6 = 0
2y² + 4y + 3y + 6 = 0
Gives y = -2, -3/2
Put on number line
-4…. -7/3…. -2…. -3/2
Question 17 of 35

17. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

I. 4x² – 9x – 9 = 0,
II. 2y² + 3y – 35 = 0
- x > y
- x < y
- x ≥ y
- x ≤ y
- x = y or relation cannot be established
Correct

Explanation:
4x² – 9x – 9 = 0
4x² – 12x + 3x – 9 = 0
Gives x = -3/4, 3
2y² + 3y – 35 = 0
2y² + 10y – 7y – 35 = 0
Gives y = -5, 7/2
Put on number line
-5….. -3/4….. 3…. 7/2

Incorrect

Explanation:
4x² – 9x – 9 = 0
4x² – 12x + 3x – 9 = 0
Gives x = -3/4, 3
2y² + 3y – 35 = 0
2y² + 10y – 7y – 35 = 0
Gives y = -5, 7/2
Put on number line
-5….. -3/4….. 3…. 7/2

Unattempted

Explanation:
4x² – 9x – 9 = 0
4x² – 12x + 3x – 9 = 0
Gives x = -3/4, 3
2y² + 3y – 35 = 0
2y² + 10y – 7y – 35 = 0
Gives y = -5, 7/2
Put on number line
-5….. -3/4….. 3…. 7/2
Question 18 of 35

18. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

I. 6x² + 22x + 15 = 0,
II. 6y² – 7y – 10 = 0
- x > y
- x < y
- x ≥ y
- x ≤ y
- x = y or relation cannot be established
Correct

Explanation:
6x² + 22x + 15 = 0
6x² + 18x + 5x + 15 = 0
Gives x = -3, -5/6
6y² – 7y – 10 = 0
6y² – 12y + 5y – 10 = 0
Gives y = -5/6, 2
Put on number line
-3…. -5/6….. 2

Incorrect

Explanation:
6x² + 22x + 15 = 0
6x² + 18x + 5x + 15 = 0
Gives x = -3, -5/6
6y² – 7y – 10 = 0
6y² – 12y + 5y – 10 = 0
Gives y = -5/6, 2
Put on number line
-3…. -5/6….. 2

Unattempted

Explanation:
6x² + 22x + 15 = 0
6x² + 18x + 5x + 15 = 0
Gives x = -3, -5/6
6y² – 7y – 10 = 0
6y² – 12y + 5y – 10 = 0
Gives y = -5/6, 2
Put on number line
-3…. -5/6….. 2
Question 19 of 35

19. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

I. 4x² – 5x – 6 = 0,
II. 4y² – 9y – 9 = 0
- x > y
- x < y
- x ≥ y
- x ≤ y
- x = y or relation cannot be established
Correct

Explanation:
4x² – 5x – 6 = 0
4x² – 8x + 3x – 6 = 0
Gives x = -3/4, 2
4y² – 9y – 9 = 0
4y² – 12y + 3y – 9 = 0
Gives y = -3/4, 3
Put on number line
-3/4….. 2…. 3

Incorrect

Explanation:
4x² – 5x – 6 = 0
4x² – 8x + 3x – 6 = 0
Gives x = -3/4, 2
4y² – 9y – 9 = 0
4y² – 12y + 3y – 9 = 0
Gives y = -3/4, 3
Put on number line
-3/4….. 2…. 3

Unattempted

Explanation:
4x² – 5x – 6 = 0
4x² – 8x + 3x – 6 = 0
Gives x = -3/4, 2
4y² – 9y – 9 = 0
4y² – 12y + 3y – 9 = 0
Gives y = -3/4, 3
Put on number line
-3/4….. 2…. 3
Question 20 of 35

20. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

I. 2x² – 19x + 45 = 0,
II. y² – 6y + 8 = 0
- x > y
- x < y
- x ≥ y
- x ≤ y
- x = y or relation cannot be established
Correct

Explanation:
2x² – 19x + 45 = 0
2x² – 10x – 9x + 45 = 0
Gives x = 9/2, 5
y² – 6y + 8 = 0
y² – 2y – 4y + 8 = 0
Gives y = 2, 4
Put on number line
2…. 4…. 9/2…. 5

Incorrect

Explanation:
2x² – 19x + 45 = 0
2x² – 10x – 9x + 45 = 0
Gives x = 9/2, 5
y² – 6y + 8 = 0
y² – 2y – 4y + 8 = 0
Gives y = 2, 4
Put on number line
2…. 4…. 9/2…. 5

Unattempted

Explanation:
2x² – 19x + 45 = 0
2x² – 10x – 9x + 45 = 0
Gives x = 9/2, 5
y² – 6y + 8 = 0
y² – 2y – 4y + 8 = 0
Gives y = 2, 4
Put on number line
2…. 4…. 9/2…. 5
Question 21 of 35

21. Question
1 points
Perimeter of a rectangle is 120 m more than the circumference of a circle . If the length and breadth of the rectangle are in the ratio 5 : 4 and the length of rectangle and radius of circle are in ratio 10 : 3, find the area of the rectangle.
- 3420 m^2
- 2760 m^2
- 3920 m^2
- 3440 m^2
- 3560 m^2
Correct

Explanation:

b/l = 4/5 and l/r = 10/3
So
b : l : r is
4*10 : 5*10 : 5*3
8 : 10 : 3
So perimeter of rectangle is 2(8x+10x) = 36x
and circumference of circle = 2 * 22/7 * 3x = 132x/7
So
36x = 120 + 132x/7
Solve, x = 7
So area of rectangle = 8x*10x = 3920 m²

Incorrect

Explanation:

b/l = 4/5 and l/r = 10/3
So
b : l : r is
4*10 : 5*10 : 5*3
8 : 10 : 3
So perimeter of rectangle is 2(8x+10x) = 36x
and circumference of circle = 2 * 22/7 * 3x = 132x/7
So
36x = 120 + 132x/7
Solve, x = 7
So area of rectangle = 8x*10x = 3920 m²

Unattempted

Explanation:

b/l = 4/5 and l/r = 10/3
So
b : l : r is
4*10 : 5*10 : 5*3
8 : 10 : 3
So perimeter of rectangle is 2(8x+10x) = 36x
and circumference of circle = 2 * 22/7 * 3x = 132x/7
So
36x = 120 + 132x/7
Solve, x = 7
So area of rectangle = 8x*10x = 3920 m²
Question 22 of 35

22. Question
1 points
Ratio of age of A seven years hence to C five years ago is 6 : 5. Present ratio of ages of B and C is 9 : 10. If the present age of B is 4 more than the present age of A, find the age if B.
- 23
- 26
- 30
- 27
- 24
Correct

(A+7)/(C-5) = 6/5
B/C = 9/10
B = 4 + A
Solve
A = 23, B = 27, C = 30

Incorrect

(A+7)/(C-5) = 6/5
B/C = 9/10
B = 4 + A
Solve
A = 23, B = 27, C = 30

Unattempted

(A+7)/(C-5) = 6/5
B/C = 9/10
B = 4 + A
Solve
A = 23, B = 27, C = 30
Question 23 of 35

23. Question
1 points
The average age of 19 men in a group is 56 years. When 3 men from the group are excluded the average becomes 54 years. Find the total age of the 3 men excluded.
- 187 years
- 207 years
- 220 years
- 176 years
- 200 years
Correct

19…. 56
16…. 54

So total age of men excluded = 19*(56-54) + 54*(19-16) = 38 + 162 = 200 years

Incorrect

19…. 56
16…. 54

So total age of men excluded = 19*(56-54) + 54*(19-16) = 38 + 162 = 200 years

Unattempted

19…. 56
16…. 54

So total age of men excluded = 19*(56-54) + 54*(19-16) = 38 + 162 = 200 years
Question 24 of 35

24. Question
1 points
Thirty-two men can complete a work in 18 days and thirty-four women can complete the same work in 21 days. Twelve men and fourteen women started the work and continued for 16 days. If men now leave the work, how many days will be required by women to complete the remaining work?
- 21 days
- 17 days
- 15 days
- 18 days
- 22 days
Correct

32m in 18 days, so 12 in 32*18/12 = 48 days
34m in 21 days, so 14 in 34*21/14 = 51 days
They worked for 16 days, so in 16 they completed (1/48 + 1/51)*16 = 11/17 of work
So remaining work = 1 – 11/17 = 6/17
which is to be completed by 14 women
Now
34 w complete 1 work in 21 days, so 14 w complete 6/17 work in x days
So
34 * 21 * 6/17 = 14 * x * 1
Solve, x = 18 days

Incorrect

32m in 18 days, so 12 in 32*18/12 = 48 days
34m in 21 days, so 14 in 34*21/14 = 51 days
They worked for 16 days, so in 16 they completed (1/48 + 1/51)*16 = 11/17 of work
So remaining work = 1 – 11/17 = 6/17
which is to be completed by 14 women
Now
34 w complete 1 work in 21 days, so 14 w complete 6/17 work in x days
So
34 * 21 * 6/17 = 14 * x * 1
Solve, x = 18 days

Unattempted

32m in 18 days, so 12 in 32*18/12 = 48 days
34m in 21 days, so 14 in 34*21/14 = 51 days
They worked for 16 days, so in 16 they completed (1/48 + 1/51)*16 = 11/17 of work
So remaining work = 1 – 11/17 = 6/17
which is to be completed by 14 women
Now
34 w complete 1 work in 21 days, so 14 w complete 6/17 work in x days
So
34 * 21 * 6/17 = 14 * x * 1
Solve, x = 18 days
Question 25 of 35

25. Question
1 points
A box contains 320 tickets (numbered 1 to 320). Find the probability of drawing a ticket containing a multiple of 3 or 8.
- 51/160
- 133/320
- 121/320
- 53/160
- None of these
Correct

Multiple of 3 up to 320 = 320/3 = 106
Multiple of 8 up to 320 = 320/8 = 40
Multiples of 3*8 = 24 up to 320 = 320/24 = 13
SO favorable events = 106 + 40 – 13 = 133
So required probability = 133/320

Incorrect

Multiple of 3 up to 320 = 320/3 = 106
Multiple of 8 up to 320 = 320/8 = 40
Multiples of 3*8 = 24 up to 320 = 320/24 = 13
SO favorable events = 106 + 40 – 13 = 133
So required probability = 133/320

Unattempted

Multiple of 3 up to 320 = 320/3 = 106
Multiple of 8 up to 320 = 320/8 = 40
Multiples of 3*8 = 24 up to 320 = 320/24 = 13
SO favorable events = 106 + 40 – 13 = 133
So required probability = 133/320
Question 26 of 35

26. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.

Find the approximate average number of valid votes polled in village B over the given years.
- 3020
- 3145
- 3276
- 3076
- 2965
Correct

Explanation:
(3200 +2600+3300)/3

Incorrect

Explanation:
(3200 +2600+3300)/3

Unattempted

Explanation:
(3200 +2600+3300)/3
Question 27 of 35

27. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.

If in city A, the percentage increase in total votes polled in 2015 over 2010 is same as the percentage increase in total votes polled in 2010 over 2005, then find the number of total votes polled in 2015?
- 4563
- 4630
- 4519
- 4608
- 4672
Correct

Explanation:
% increase in 2010 = (3840-3200)/3200 * 100 = 20%
So in 2015 = 120/100 * 3840

Incorrect

Explanation:
% increase in 2010 = (3840-3200)/3200 * 100 = 20%
So in 2015 = 120/100 * 3840

Unattempted

Explanation:
% increase in 2010 = (3840-3200)/3200 * 100 = 20%
So in 2015 = 120/100 * 3840
Question 28 of 35

28. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.

If 25% of total votes polled in village A in 2005 are from females and total valid voted by females is 865, then find the number of valid votes from males in village A in same year.
- 1865
- 1965
- 2035
- 1935
- 1825
Correct

Explanation:
Total valid votes are 2800 and by females is 865 so remaining by males.
2800 – 865 = 1935

Incorrect

Explanation:
Total valid votes are 2800 and by females is 865 so remaining by males.
2800 – 865 = 1935

Unattempted

Explanation:
Total valid votes are 2800 and by females is 865 so remaining by males.
2800 – 865 = 1935
Question 29 of 35

29. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.

What is the approximate average number of invalid votes polled in 2000?
- 287
- 324
- 275
- 269
- 316
Correct

Explanation:
2700-2350 = 350, 3200-2860 = 340, 4060-3890 = 170
(350+340+170)/3

Incorrect

Explanation:
2700-2350 = 350, 3200-2860 = 340, 4060-3890 = 170
(350+340+170)/3

Unattempted

Explanation:
2700-2350 = 350, 3200-2860 = 340, 4060-3890 = 170
(350+340+170)/3
Question 30 of 35

30. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.

Total invalid votes polled in village B in 2005 is what percent greater than total invalid votes in village C in 2005?
- 110%
- 90%
- 100%
- 105%
- 95%
Correct

Explanation:
Invalid in B in 2005 = 3600-3300 = 300
Invalid in C in 2005 = 3600-3450 = 150
So required % = (300-150)/150 * 100 = 100%

Incorrect

Explanation:
Invalid in B in 2005 = 3600-3300 = 300
Invalid in C in 2005 = 3600-3450 = 150
So required % = (300-150)/150 * 100 = 100%

Unattempted

Explanation:
Invalid in B in 2005 = 3600-3300 = 300
Invalid in C in 2005 = 3600-3450 = 150
So required % = (300-150)/150 * 100 = 100%
Question 31 of 35

31. Question
1 points
A sum of Rs 6000 is invested in parts in two schemes for 3 years and 2 years respectively. Scheme A offers 11% rate of interest per annum and scheme B offers 10% rate of interest compounded annually. If amount obtained from first part is Rs 2520 less than twice the amount obtained from second part, find the amount invested in Scheme A.
- Rs 2800
- Rs 3100
- Rs 3500
- Rs 2700
- Rs 3200
Correct

x + x*11*3/100 = 2[(6000-x)*(1 + 10/100)²] – 2520
133x/100 = 120*121 – 242x/100 – 2520
375x/100 = 12000
So x = Rs 3200

Incorrect

x + x*11*3/100 = 2[(6000-x)*(1 + 10/100)²] – 2520
133x/100 = 120*121 – 242x/100 – 2520
375x/100 = 12000
So x = Rs 3200

Unattempted

x + x*11*3/100 = 2[(6000-x)*(1 + 10/100)²] – 2520
133x/100 = 120*121 – 242x/100 – 2520
375x/100 = 12000
So x = Rs 3200
Question 32 of 35

32. Question
1 points
An article is marked 30% above the cost price. While selling the shopkeeper gives a discount of 10%. What is the profit percent o the shopkeeper if he also uses false weights of 1000 gm instead of 1200 gm?
- 46.25%
- 54.25%
- 65.25%
- 34.25%
- None of these
Correct

Profit % when false weights are used = (1200-1000)/1000 * 100 = 20%
Now let CP = 100
So MP = 130 (30% above the cost price)
So SP after discount = 90/100 * 130 = 117
Now seller selling 20% less in weight so CP = Rs 80
Now CP = 80, SP = 117
So profit % = 37/80 * 100

Incorrect

Profit % when false weights are used = (1200-1000)/1000 * 100 = 20%
Now let CP = 100
So MP = 130 (30% above the cost price)
So SP after discount = 90/100 * 130 = 117
Now seller selling 20% less in weight so CP = Rs 80
Now CP = 80, SP = 117
So profit % = 37/80 * 100

Unattempted

Profit % when false weights are used = (1200-1000)/1000 * 100 = 20%
Now let CP = 100
So MP = 130 (30% above the cost price)
So SP after discount = 90/100 * 130 = 117
Now seller selling 20% less in weight so CP = Rs 80
Now CP = 80, SP = 117
So profit % = 37/80 * 100
Question 33 of 35

33. Question
1 points
A solution contains alcohol and water in the ratio 3 : 1. 16 litres of the solution is drawn and 12 litres of water is added. Now 11 litres of the mixture is replaced by 11 litres of the water. If the final ratio of alcohol to water in the solution is 9 : 13, find the initial quantity of the solution.
- 48 litres
- 50 litres
- 56 litres
- 64 litres
- None of these
Correct

Solving with options will help.
initial ratio is 3 : 1
So total is 4. So total quantity must be a multiple of 4, so discard option C) 50
Next check with other options:
16 litres withdrawn, so alcohol withdrawn is 3/4 * 16 = 12 l, and water withdrawn is 1/4 * 16 = 4 l
A) 48 in the ratio 3 : 1 is 36 and 12. Now
So alcohol now is 36-12 = 24 and water = 12 – 4 = 8
Now 12 l water added so water becomes = 8 + 12 = 20
See now alcohol + water is 24+20 = 44 which is a multiple of 11 (since 11 litres withdrawn next)
So this can be the answer
Proceed further to find out that if this is the answer

In other options we do not get a multiple of 11 in that step.

Incorrect

Solving with options will help.
initial ratio is 3 : 1
So total is 4. So total quantity must be a multiple of 4, so discard option C) 50
Next check with other options:
16 litres withdrawn, so alcohol withdrawn is 3/4 * 16 = 12 l, and water withdrawn is 1/4 * 16 = 4 l
A) 48 in the ratio 3 : 1 is 36 and 12. Now
So alcohol now is 36-12 = 24 and water = 12 – 4 = 8
Now 12 l water added so water becomes = 8 + 12 = 20
See now alcohol + water is 24+20 = 44 which is a multiple of 11 (since 11 litres withdrawn next)
So this can be the answer
Proceed further to find out that if this is the answer

In other options we do not get a multiple of 11 in that step.

Unattempted

Solving with options will help.
initial ratio is 3 : 1
So total is 4. So total quantity must be a multiple of 4, so discard option C) 50
Next check with other options:
16 litres withdrawn, so alcohol withdrawn is 3/4 * 16 = 12 l, and water withdrawn is 1/4 * 16 = 4 l
A) 48 in the ratio 3 : 1 is 36 and 12. Now
So alcohol now is 36-12 = 24 and water = 12 – 4 = 8
Now 12 l water added so water becomes = 8 + 12 = 20
See now alcohol + water is 24+20 = 44 which is a multiple of 11 (since 11 litres withdrawn next)
So this can be the answer
Proceed further to find out that if this is the answer

In other options we do not get a multiple of 11 in that step.
Question 34 of 35

34. Question
1 points
A and B started a business by investing Rs10,000 and Rs 11,000 respectively. After 4 months they both withdrew Rs 1000. After a further of half year, A invested Rs 1000 more and B invested Rs 2000 more. If a total profit received after a year is Rs 54,450, what is the difference in the shares of A and B?
- Rs 3340
- Rs 3970
- Rs 3090
- Rs 3150
- None of these
Correct

10000*4 + 9000*6 + 10000*2 : 11000*4 + 10000*6 + 12000*2
10000*6 + 9000*6 : 11000*4 + 10000*6 + 12000*2
10*6 + 9*6 : 11*4 + 10*6 + 12*2
10*3 + 9*3 : 11*2 + 10*3 + 12
57 : 64
Difference = (64-57)/(57+64) * 54450 = 3150

Incorrect

10000*4 + 9000*6 + 10000*2 : 11000*4 + 10000*6 + 12000*2
10000*6 + 9000*6 : 11000*4 + 10000*6 + 12000*2
10*6 + 9*6 : 11*4 + 10*6 + 12*2
10*3 + 9*3 : 11*2 + 10*3 + 12
57 : 64
Difference = (64-57)/(57+64) * 54450 = 3150

Unattempted

10000*4 + 9000*6 + 10000*2 : 11000*4 + 10000*6 + 12000*2
10000*6 + 9000*6 : 11000*4 + 10000*6 + 12000*2
10*6 + 9*6 : 11*4 + 10*6 + 12*2
10*3 + 9*3 : 11*2 + 10*3 + 12
57 : 64
Difference = (64-57)/(57+64) * 54450 = 3150
Question 35 of 35

35. Question
1 points
10 man can do a work in 50 days. While 20 women can do the same work in 40 days. Three teams A,B and C formed having different number of men and women. Team A contains 20 men and 10 women. Team B contains 25 men and 8 women. Team C contains 5 men and 40 women. If the team that completes the work in minimum time wins the game, which team will emerge as the winner?
- A
- B
- C
- Both A and B
- Both B and C
Correct

10 men => 50 days ; 20 women => 40 days
Team A (20 men->25 days ; 10 women->80 days)=(25*80)/(25+80)= 19.04 days
Team B(25 men->20 days ; 8 women->100 days)=(20*100)/(120)=16.66 days
Team C(5 men->100 days ; 40 women->20 days)=16.66 days

Incorrect

10 men => 50 days ; 20 women => 40 days
Team A (20 men->25 days ; 10 women->80 days)=(25*80)/(25+80)= 19.04 days
Team B(25 men->20 days ; 8 women->100 days)=(20*100)/(120)=16.66 days
Team C(5 men->100 days ; 40 women->20 days)=16.66 days

Unattempted

10 men => 50 days ; 20 women => 40 days
Team A (20 men->25 days ; 10 women->80 days)=(25*80)/(25+80)= 19.04 days
Team B(25 men->20 days ; 8 women->100 days)=(20*100)/(120)=16.66 days
Team C(5 men->100 days ; 40 women->20 days)=16.66 days

window.wpProQuizInitList = window.wpProQuizInitList || []; window.wpProQuizInitList.push({ id: '#wpProQuiz_41', init: { quizId: 41, mode: 1, globalPoints: 35, //customized code :add "negativePoints". negativePoints: [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], timelimit: 1500, qtime: 0, resultsGrade: [0], bo: 640, qpp: 0, catPoints: [35], formPos: 0, lbn: "Quiz-summary", json: {"1691":{"type":"single","id":1691,"catId":0,"negative_points":0,"points":1,"correct":[0,0,1,0,0]},"1692":{"type":"single","id":1692,"catId":0,"negative_points":0,"points":1,"correct":[1,0,0,0,0]},"1693":{"type":"single","id":1693,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1694":{"type":"single","id":1694,"catId":0,"negative_points":0,"points":1,"correct":[0,0,1,0,0]},"1695":{"type":"single","id":1695,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1697":{"type":"single","id":1697,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1698":{"type":"single","id":1698,"catId":0,"negative_points":0,"points":1,"correct":[0,1,0,0,0]},"1699":{"type":"single","id":1699,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1700":{"type":"single","id":1700,"catId":0,"negative_points":0,"points":1,"correct":[0,1,0,0,0]},"1701":{"type":"single","id":1701,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1702":{"type":"single","id":1702,"catId":0,"negative_points":0,"points":1,"correct":[0,1,0,0,0]},"1704":{"type":"single","id":1704,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1705":{"type":"single","id":1705,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1706":{"type":"single","id":1706,"catId":0,"negative_points":0,"points":1,"correct":[0,1,0,0,0]},"1707":{"type":"single","id":1707,"catId":0,"negative_points":0,"points":1,"correct":[0,0,1,0,0]},"1709":{"type":"single","id":1709,"catId":0,"negative_points":0,"points":1,"correct":[0,1,0,0,0]},"1710":{"type":"single","id":1710,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1711":{"type":"single","id":1711,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1712":{"type":"single","id":1712,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1713":{"type":"single","id":1713,"catId":0,"negative_points":0,"points":1,"correct":[1,0,0,0,0]},"1741":{"type":"single","id":1741,"catId":0,"negative_points":0,"points":1,"correct":[0,0,1,0,0]},"1742":{"type":"single","id":1742,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1743":{"type":"single","id":1743,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1744":{"type":"single","id":1744,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1745":{"type":"single","id":1745,"catId":0,"negative_points":0,"points":1,"correct":[0,1,0,0,0]},"1716":{"type":"single","id":1716,"catId":0,"negative_points":0,"points":1,"correct":[1,0,0,0,0]},"1717":{"type":"single","id":1717,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1718":{"type":"single","id":1718,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1719":{"type":"single","id":1719,"catId":0,"negative_points":0,"points":1,"correct":[1,0,0,0,0]},"1720":{"type":"single","id":1720,"catId":0,"negative_points":0,"points":1,"correct":[0,0,1,0,0]},"1746":{"type":"single","id":1746,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]},"1747":{"type":"single","id":1747,"catId":0,"negative_points":0,"points":1,"correct":[1,0,0,0,0]},"1748":{"type":"single","id":1748,"catId":0,"negative_points":0,"points":1,"correct":[1,0,0,0,0]},"1784":{"type":"single","id":1784,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,1,0]},"1785":{"type":"single","id":1785,"catId":0,"negative_points":0,"points":1,"correct":[0,0,0,0,1]}} } });

6 Thoughts to “Quant Sectional Test 1 for SBI PO 2017 Prelim Exam”

K!nG Iz B!nG

March 4, 2017 at 5:42 pm

Results
24 of 35 questions answered correctly

Your time: 00:25:00
Divaker

March 7, 2017 at 12:50 am

good initiative please upload it on daily basis if possible
dream girl ;;;;/@ :)

March 9, 2017 at 6:06 pm

18 of 35 questions answered correctly

Your time: 00:23:18

You have reached 18 of 35 points, (51.43%)
DBZ

March 10, 2017 at 12:25 pm

Wah 🙂
Shubhra

April 4, 2017 at 2:09 am

Practice more sets 🙂
1. M@UT!!
  
  April 4, 2017 at 2:13 am
  
  Ok mam

Comments are closed.

Information

Congratulations!!!" SBI Pre - Quant 1 "

1. Question

2. Question

3. Question

4. Question

5. Question

6. Question

7. Question

8. Question

9. Question

10. Question

11. Question

12. Question

13. Question

14. Question

15. Question

16. Question

17. Question

18. Question

19. Question

20. Question

21. Question

22. Question

23. Question

24. Question

25. Question

26. Question

27. Question

28. Question

29. Question

30. Question

31. Question

32. Question

33. Question

34. Question

35. Question

6 Thoughts to “Quant Sectional Test 1 for SBI PO 2017 Prelim Exam”