A train running at the speed of 90 kmph passes a pole in 10 sec, in how much time the train can cross 350m long another train B, which running opposite direction with the speed of 180 kmph.
10 sec
8 sec
12 sec
15 sec
20 sec
Option B length of the train=90*5/18*10=250 m speed of train=90*5/18=25 m/sec speed of another train=180*5/18=50 m/sec required time=250+350/25+50=6000/75=8 sec
A bus can cover a certain distance in 5 hours and when same bus starts running with 20% less speed then it can cover 300 km in 5 hours. Find the distance of the journey.
375
400
425
500
575
Option A let the distance of the journey=D km original speed of the bus=5x decreased speed of the bus=4x 4x=300/5 x=15 distance=15*5*5=375 km
A train running at the speed of 72 kmph cross pole in 18 sec. If same train cross a ‘x’ meters long platform in 30 sec, then find value of ‘x’ ?
300
360
420
240
180
Option D speed of train=72*5/18=20 m/sec length of train=72*5/18*18=360 m ATQ, (360+x)/20=30 x=600-360=240 m length of platform=240 km
Train P having length of 200m crosses a platform twice of its length in 30 sec. Another train Q having speed of 180 kmph crosses a pole in 10 sec. Find time taken by both trains to cross each other when running in opposite direction.
12 sec
10 sec
18 sec
22 sec
25 sec
Option B speed of train P=200+400/30=600/30=20 m/sec length of train Q=180*5/18=50 m/sec required time=(500+200)/20+50=10 sec
Distance between A and B is 880 km and speed of car is 20% more than speed of a bike. If car starts from A towards B and at the same time bike starts from B towards A and they meet after 4 hours, then find total distance travelled by car.
400
480
540
600
360
Option B let speed of bike=5x speed of car=6x ATQ, 880/6x+5x=4 880/11x=20 sec 880/11x=4 x=20 km speed of car=6*20=120 kmph distance travelled by car=120*4=480 km
‘L’ meters of long train cross a 480 m long tunnel in 40 sec running at the speed of 108 kmph. If train cross a man running in opposite direction in 8 sec, find speed of man (in km/hour).
108
210
110
280
300
Option A speed of train=108*5/18=30 sec ATQ, L+480/40=30 sec L=1200-480=720 let, the speed of man=’x’ sec 720/30+x=12 x=30m/sec sped of main =30*18/5=108 km/hr
A train can cross a tunnel of length 360m in 15sec, while a pole in 3 sec. In what time the train can cross a platform of length of 210 m.
10 sec
8 sec
12 sec
16 sec
20 sec
Option A let length of train be x meters (x+360)/15=x/3 15x=3x+1080 x=90 meters speed of train=90+360/15=450/15=30 m/sec required time=90+210/30=10 sec
Ritu goes to office at a speed of 7 kmph and returns to the home at a speed of 4 kmph. If he takes 5 hours 30 minutes in all, what is the distance between the office and his home ?
24
15
18
20
14
Option E let distance between office and Ritu’s home=D km D/7+D/4=11/2 11D/28=11/2 D=14 km
A train running at 11/15 of his own speed reached a place in 60 hours. How much time could be saved if the train would run at its own speed ?
18
16
26
18
20
Option B let the original speed of train=15x current speed of train=11x original time required=60*11x/15x=44 time saved=60-44=16 hours
In covering a certain distance, the speed of A and B are in the ratio of 3:4. A takes 6 hours more than B to reach the destination. What is the time taken by A to reach the destination ?
20
32
30
24
36
Option D speed of A and B =3:4 time ratio of A and B =4:3 let time taken by A=4x time taken by=3x 4x-3x=6 x=6 time take by A to reach the destination=4*6=24 hours
