Data Interpretation Questions (DI) for IBPS PO 2017, IBPS Clerk, NIACL, NICL, SBI PO, RBI Grade B, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.
Directions (1-5): The below bar graph shows the production (in thousands) of different items by a manufacturing firm in 6 different months.
- If only 80% of the pencils manufactured in may are suitable for sale and a discount of 10% is given on the MP, then what is the profit% ?
A) 30
B) 10
C) 8
D) 12
View Answer
Option C
Solution :
Pencils produced in may = 70000
suitable to sale = 80% = 56000………total CP ( including defected produce) = 70*2000 = 140000
MP = Re. 3 per pencil ..discount 10 % so SP =Re. 2.7
Total SP. 2.7*56000 = 151200 ..Profit = 11200..profit % = 11200*100/140000 = 8
- In how many months scales manufactured are greater than average scales manufactured over the given months?
A) 3 months
B) 5 months
C) 2 months
D) 4 months
View Answer
Option D
Solution :
Average production over the given months (scales) 265000/6 = 44000(appx)
jan ,april , may and june are the months .
- If in July production of markers increases by 20% , scales by 15% and sharpeners by 12% over the previous month , then What is the total production of all the three products in july ?
A) 115950
B) 114950
C) 119450
D) 115490
View Answer
Option B
Solution :
In june markers produced = 20000 ..increase in july – 20% i.e 4000
scales produced in june = 45000 …increase in july – 15% i.e 6750
sharpeners in june = 35000…….increase in july -12% i.e 4200
total in june ..1,00,000 ….increase in july ……..14950 >> increased production = 114950
- By how much is the the production of all the items in june less than the production in april (in rupees) ?
A) 198500
B) 189500
C) 158900
D) 185900
View Answer
Option A
Solution :
production in april……….june ……change…….amount ( in CP)
. Â Â pencils……..45………….65………..(-20)………..(-40)
. Â Â Â erasers…….30…………35………..(-5) …………..(-7.5)
. Â Â markers……60…………20…………(+40)………….(+240)
. Â Â Â scales………45…………..45…….no change
. Â Â Â sharpeners.40…………..35………….(+5)………….(+6)
total change …………………….246- 47.5 = 198.5 *1000 = 198500 rupees
- What is the total revenue generated if all the items produced in February are sold (assume MP to be SP here) ?
A) 945000
B) 949000
C) 995400
D) 954000
View Answer
Option B
Solution :
revenue from pencils = 40*3 = 120
revenue from erasers = 35*2.4 = 84
revenue from markers = 70*9 = 630
revenue from scales = 35* 2 = 70
revenue from sharpeners= 30*1.5 = 45
total = 949 ….multiply by thousand = Rs. 949000
Directions (6-10):Â Read the below data carefully and answer the following questions :
The line graph indicates the no. of days taken by six boys to complete a work.
The chart below shows the number of days taken by six girls to complete a work.
- If pulkit and paras started to work and after 2 days they were replaced by neha, ruhi and happy then they stopped , how much work is still left ? (Neha, Ruhi and Happy worked for 2 days together)
A) 1/10
B) 1/6
C) 1/9
D) 1/12
View Answer
Option B
Solution :
Let work = 180 units
pulkit’ 1 day’s work ……….20 ( work/ no. of days taken)
paras’s 1 day’s work ……..20
neha’s 1 day’s work……….7.5
happy’s 1 days work……..7.5
ruhi’s 1 day’s work ……..20
paras and pulkit worked for 2 days…..(20+20)*2 = 80…remaining work = 100
now for 2 days ( 7.5+7.5+20)*2 = 70 …..remaining work = 30 ..so 30/180 = 1/6
- If all the boys work together then time taken by them will be how much less than the time taken by purvi, hema , neha and happy together to do the work ?
A) 2 * 2/5 days
B) 2 * 3/5 days
C) 2 * 1/5 days
D) 2* 4/5 days
View Answer
Option C
Solution :
total days taken by boys to do the work = 180/100 = 9/5 days
days taken by 4 girls = 180/45 = 4 days …difference = 4-9/5 = 11/5 days
- Pradeep and Nikku started work. Pradeep worked at 120% of his efficiency and Nikku at 5/6 of his normal routine work. They started work on alternate days starting with Pradeep. How many days will be taken by them to complete the work?
A) 10* 4/5 days
B) 10* 5/6 days
C) 10* 3/4 days
D) 11 days
View Answer
Option B
Solution :
Pradeep’s one day’s work ………..180/12 = 15 units
N one day’s work…………….180/10 = 18 units
now, Pradeep works at 120% of 15 = 18 units
Nikku at 5/6 of 18 = 15 units
Pradeep + Nikku’s 2 days’ work = 33
In 10 days ……………….33*5 = 165 units
Remaining ………15 units ….Pradeep does…18 days a day so to do 15 units He will take 5/6 days therefore total time taken = 10* 5/6 days
- How many days will it take to complete the work if Punit does the 25% of the work alone and 10% is done by Nikku alone and the remaining is done by Suman ??
A) 19 days
B) 16 days
c) 13 days
D) 17 days
View Answer
Option D
Solution :
Punit’s 1 day’s work ………15 units so to do 25% work ( assumed total work = 180) = 45 he will take 3 days
to do 10% work..i.e 18 units nikku will take 1 days …noe remaining work = 180-63 = 117
to do 117 , suman will take 117/9 = 13 days ( suman’s 1 day’s work = 180/20 = 9 units)
Total days = 3+1+13 = 17 days
- Ashu started working alone at his normal efficiency but after 5 days of starting he found that he has done only 25% work so to complete the remaining work on time by how much percentage he should increase his efficiency?
A) 12.5%
B) 15%
C) 10%
D) 20%
View Answer
Option A
Solution:
Ashu’s 1 day’s work …180/15 = 12 units
In 5 days he should have done …60 units
but he did……………….180/4 = 45 units
so remaining work = 135 units so complete it in 10 days he should do 135/10 = 13.5 units per day
therefore increased efficiency … 13.5 – 12 = 1.5 >> 1.5*100/12 = 12.5%
yes we ll make that also
thanku mam :))
Thankyou so much 🙂
total work 180 units kaise aaya
LCM taken of no. of days taken by all
ok….thanx mam
mam mera total work unit 360 aa rha hai
yaa u can take that
hi batman sir,…..:))
Q6
pulkit-9days
paras-9days
neha-24
ruhi-9
happy-24
ma’am 180 not 72?
yess i have taken 180 ..72 is where ???
lcm of 9,9,24,9,24 = 72?
is the number of days taken by me are correct?
yes yes its correct but u didn’t consider all the 12 people
okkk…its a single wrk completed by all of them. i took it as individual no. of days taken by all of them to do work individually..
ohkk
thank you ma’am 🙂
yes it is single work .
yup..i interpreted it wrong
it happens sometime Dear .:
🙂
ohkk but 72 can’t be taken for 15 na …i have taken 180 for all including boys and girls
15?
15 for ashu and 15 for hema too …72 can’t fit here na so 180 taken
u can take any number u want
it is correct dear ..where you get problem
got it knw..i understood ques wrong
yup this is where i gt stuck..wen 4 persons are working we take lcm of those 4 only why here everyone’s work in being taken into account?
but mod says its a single work done by all of them and the number of days is indicative of days individual person worked for those many days on the same work…not the individual person takes days to complete the whole work.
no but if u take LCM of these 5 people as 72 then too the answer will come as 1/6
it won’t make any difference …it is my method of doing ques ..if u feel comfortable doing traditional method u can go for that too
https://uploads.disquscdn.com/images/26a7b2b944b5cfb847140925f37d2cdecba0d5ceabec5a14bd13c11f3d048f4a.jpg
yes right :))
hope it helps everyone nw 🙂
yess i ll keep in mind to give a more elucidated solution next time 🙂
@Alice thankyou dear
in 2 DI .first qo ,you should place an extra info ,qo looks more appropriate
If pulkit and paras started to work and after 2 days they were replaced by neha, ruhi and happy they were work for 2 days then they too stopped , how much work is still left ?
yess it is like that only..typo
i know .the sense by which you made this qo but seems it looks improper,many are stuck on that point
yes 🙂
no prblm 🙂
true
yes it is edited now.. refresh the page once
Yup :
i got the same doubt
u can take any LCM u want but answer will remain always the same
heeeheee…:)
🙂 how is that possible ??
??????
see above
problm????
if in question 1st ,if it is only asking about the 4 people pulkit paras neha ruhi happy
then in that case there is no need to find out the lcm of whole , right?
but problem is , answer is not coming same from both the cases, which is supposed to be same , isn’t?
6th que??
hmm
qo is correct .
yes it is but i think they r not getting the method ..
1/6 ans is comming?? whers the pblm
what rearrangement ???
make work equal if not getting i think thats only otherwise its correct…..:))
——————–
ohkk…but still answer will be same na
efficiency = 100/no. of days
yesss off course for better undestanding i meant to say i did it that way only now when i saw the comment then i checked the soln posted in that heheheheh….:)))
:))
yup..its same..perfectly fine 🙂
now everything clear ???
yes ma’am 🙂
it ws already wen u explained last time..i took it wrong
no pblm 🙂
keep learning 🙂
explain ur solution i ll check that
answer is coming
by LCM approach .without knowing the whole work how could you find out the their efficiency of per day,so it is necesry
it means he has to complete whole work in the specified time only
he did 45 in 5 days but he was supposed to do 60 units so to compensate this 15 units’s deviation he will have to work more in next days to complete the work in time.
so remaining work = 135 and time 10 days so he should do 135/10 = 13.5 units per day now
and change is 13.5 – 12 = 1.5 and % = 1.5/12 *100 = 12.5
What is the total revenue generated if all the items produced in February are sold (assume MP to be SP here) ?
A) 945000
B) 994000
C) 995400
D) 954000
View Answer
Option D
Solution :
revenue from pencils = 40*3 = 120
revenue from erasers = 35*2.4 = 84
revenue from markers = 70*9 = 630
revenue from scales = 35* 2 = 70
revenue from sharpeners= 30*1.5 = 45
TOTAL=949 INSTEAD OF total = 954
RE-CHECK QO NO 5/
949 ans aa rha hai mera
YES ,You are Rite then,. correct Option is not there…
next di mae total work unit aapka kya aa rha hai?
yes you can take 180 or 360 .both are correct here ,we take such value which is minimum possible value of that given no.
ok wait i ll check
yes my mistake ..we ll edit thankyou
Anytym >Miss
@@imvendetta:disqus Hey , i didn’t get the question number 10th’s answer from second last line
would you like to explain dear?
so remaining work = 135 units so complete it in 10 days he should do 135/10 = 13.5 units per day
therefore increased efficiency … 13.5 – 12 = 1.5 >> 1.5*100/12 = 12.5%
Didn’t get this?
sure .let me explain
Ashu started working alone at his normal efficiency but after 5 days of starting he found that he has done only 25% work so to complete the remaining work on time by how much percentage he should increase his efficiency?
A) 12.5%
B) 15%
C) 10%
D) 20%
Ashu’s 1 day’s work …360/15 = 24 units
In 5 days he should have done=120 units
but he did 180/4 = 90 units
so remaining work = 270 units he has to complete it in 10 days
he should do 270/10 = 27 units per day
therefore increased efficiency …27-24 ==3==3*100/24 = 12.5%
@@imvendetta:disqus Thankyou so much bro 🙂
i think you were stuckd in decimal values.sometimes it complicates values that y i took 360
you got it right buddy
thanks again:)
Qo no=6
Let total work=LCM of All members=360
Pulkit 1 Day work=360/9=40
Paras 1 day work=360/9=40
2 day they work togeather=(40+40)*2=160
Neha 1 day work=360/24=15
Ruhi 1 day work=360/9=40
happy 1 day work=360/24=15
N+R+H worked for 2 days ,=(15+40+15)=70*2=140
total work completed by them=160+140=300
left work=60/360=1/6
how do you get lcm 360 explanation please
9……10………12…….15…….20……..24.. are the number of days taken by all
360 is assumed total work which is LCM of all these figures.
ty
anyone tell me 7?
yess
how 100?
how 45?
yes just 5 mint plz
see i have taken the total work to be 180 units
so to get one day’s work we ll divide no. of days taken by a person by 180
so one day’s work of punit will be …..180/12 = 15 units
similarly we ll get …ashu’s 1 day’s work .. 12 units …………nikku’s work………..18 units
paras’s 1 day’s work ……………….20 units…..pulkit too ….20 units and …pradeep …15 units
adding all we get …20+20+15+15+12+18 we get 100
similarly for girls we ll get 45
ty got it my mistake
BOYS-12……15……10…9….12…..9
………………………..180……………
…………15…….12….18…20..15….20
15+12+18+20+15+20=100
180/100=9/5
GIRL-10…..15…..24……24
…………………120………
……..12………8…….3…….3
12+8+3+3=30
120/30=4
LESS=4-9/5=11/5
superb mod
ty 🙂
Q6–PUL…PAR….NEHA……RUHI……HAPPY
…..9………9………..24………9………….24
……………………….72……………………..
8……………8……….3………8…………….3
PUL+PAR=16*2=32
32/72=4/9 WORK DONE
REST=1-4/9=5/9
N+R+H=14*2=28
28/72=7/18
5/9-7/18==3/18=1/6
qs 10
complete it in 10 days ??
yes jo normal time wo le rha hai usme hi complete karna hai
5 days me 60 karna tha na but hua kitna – 45 to remaining 10 days me wo 135 krega (180-45 ) = 135
abhi bhi ni aaya 10 days ?
normal time kita leta wo 15 days na
first 5 days me usne total work (180) ka 25 % kiya means 45
left work = 135 and days left = 10 days (15-5 )
in ques 1st why we not take total cp = 56×2000 ??
we ll have to take cost of defected products too…. only then we ll able to get real profit
ok thank u
Bcoz ,we need the total cp there..not only the one which are eligible for sale
que 4 xplain pls
production in June and production in April difference ( in rupees )
Mam, I weak in quant..how to solve DI with new pattern questions…pls suggest me
You people are doing wonderful job…unique one…if possible make di on various miscellaneous chaptrs..like time and distance…boat n stream…pipe n cristen….patnershp…si/ci….n etc all other topic…..take one topic n make various di on that chaptrs..i know u ppl are doing….its jus my suggestion looking to ibps po
yes we ll 🙂
keep giving suggestions !!
Thank you
done .thnxx
If in July production of markers increases by 20% , scales by 15% and sharpeners by 12% over the previous month , then What is the total production of all the three products in july ?
A) 115950
B) 114950
C) 119450
D) 115490
View Answer
Option B
Solution :
In june markers produced = 20000 ..increase in july – 20% i.e 4000
scales produced in june = 45000 …increase in july – 15% i.e 6750
sharpeners in june = 35000…….increase in july -12% i.e 4200
total in june ..1,00,000 ….increase in july ……..14950 >> increased production = 114950
bro isme 20000*120/100 kiu ni hua….cz increase hua h na?
pura Question bathoo
DI k question without diagram k smj m nhi aate
@@disqus_sqmL5JaJJZ:disqus how you can assume total work is 180 units…any idea behind?
u can assume any figure u feel easy doing calculations with
I have taken a common multiple of all the values given
Mam in que 10 .. where it is given that work should be completed in 10 days..
see it is given that
the work is to be done in the prefixed time that is 15 days
he has worked for 5 days already and completed 25% work
so in the remaining 10 days he have to do remaining 75% work
Okk ty mam?
pls post daily ambi…cz DI mein bhut work krna h…so for alll…pls do post on regular basis.. nd take each topic…pls…mah request
yes sure 🙂
we ll post .
in q-4 y u need the cost price?? only diff of prodction of manufacturd are required.
Mam plz explain question 4th the value is increasing from 45 to 65 then why d change is negative ?
thnk u ambi sis…
Tq
in Q10, how 10days is considered?
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