Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams. Casellete based Data Interpretation Set IBPS PO 2017

**Direction (1-5): Study the following information and answer the questions that follow:**

Vishal and Shekhar have some toffees initially. Everyday Vishal and Shekhar buy a fixed number of toffees. The number of toffees that they buy each day is different from other’s number. After 4 days, they have equal number of toffees. After 12 days Vishal has 8 (16/23)% more toffees than Shekhar. After 13 days, Sunidhi who has no toffee initially, took 6 toffees from Vishal and 3 toffees from Shekhar, as a result now Vishal has 6 toffees more than Shekhar. After 15 days, they all clubbed together their toffees and divided equally among the three. Now each of them has 71 toffees. Based on this information answer the questions that follows.

- How many toffees Vishal had initially?

A) 50

B) 48

C) 56

D) 52

E) 64

View Answer

**Option D**

Solution:

Let Vishal has V toffees initially and he buys A toffees each day

Let Shekhar has S toffees initially and he buys B toffees each day

After 4 days, they have equal number of toffees.

hence V+4A = S+4B

=> V-S=4(B-A) —- (i) After 12 days Vishal has 8 (16/23)% =200/13% more toffees than Shekhar

V + 12A = (S+ 12 B)* (1+2/23)

=> V+12A =25/23 * (S+12B) —– (ii) After 13 days, Sunidhi who has no toffee initially, took 6 toffees from Vishal and 3 toffees from Shekhar, as a result now Vishal has 6 toffees more than Shekhar.

Toffees with Vishal after 13 days = V+13B ; when 6 toffees given to Sunidhi now he has V+13A-6

Toffees with Shekhar after 13 days = S +13B; when 3 toffees given to Sunidhi now he has S+13B -3

also ;

V+13A-6 = (S+13B -3) + 6

=>V+13A = S+13B+9

=>V-S=13(B-A)+9 ———– (iii)

After 15 days, they all clubbed together their toffees and divided equally among the three. Now each of them has 71 toffees.

All the toffees that they have after 15 days is due to Vishal and Shekhar, as Sundihi had 0 toffees initially

So V+15A + S+15B=3*71=213 —- (iv)

Equate eq (i) and (iii) for V-S = V-S in each equation , so we have now

4(B-A)= 13(B-A)+9

We get A-B= 1

A=1+B—-(v)

put this in eq (i)

S-V=4

S=V+4— (vi)

Put A=1+B and S=V+4

in eq (ii) and (iv) to get two equations with two variable

we will get

V+12B=88

and

V+15B=97

solve and get

B=3 and V=52

hence

A=4 and S=56

so now we have all the required value; keep them handy

V=52; A=4

S=56; B=3

So Vishal has 52 toffees initially

- How many toffees Shekhar buys everyday?

A) 2

B) 3

C) 4

D) 5

E) 6

- After 14 days how many toffees did Shekhar and Sunidhi had in total?

A) 101

B) 104

C) 107

D) 110

E) 113

View Answer

**Option B**

Solution:

After 14 days Shekhar had 56+14*3 -3 =95 toffees (as 3 toffees have been taken by Sunidhi)

Sunidhi has 9 toffees

total=95+9=104

- By what percent the number of toffees that Shekhar had was less than that of Vishal after 11 days?

A) 7.90%

B) 8.24%

C) 9.27%

D) 6.24%

E) 7.29%

View Answer

**Option E**

Solution:

After 11 days

Vishal=52+11*4=96

Shekhar=56+11*3=89

Required % = (96-89)/96 *100 =

- If Vishal and Shekhar keeps on buying toffees in same manner, then the number of toffees they will have in total after 50 days is?

A) 402

B) 503

C) 387

D) 457

E) 458

View Answer

**Option C**

Solution:

After 15 days they had 71 toffees each

So After 50 days

71+71+(50-15)*4 + (50-15)*3= 387

**Direction (6-10): Study the following information and answer the questions that follow:**

In a bilateral cricket series between India and Australia, the probability that India wins the first game is 0.4. If India wins any game, the probability that it wins the next game is 0.3; otherwise the probability is 0.2.

- Find the probability that India wins the first two games.

A) 0.08

B) 0.32

C) 0.18

D) 0.12

E) None of these

View Answer

**Option D**

Solution:

P(Win first game)* P(Win second game)= 0.4*0.3=0.12

- Find the probability that India wins at least one of the first two games.

A) 0.48

B) 0.32

C) 0.56

D) 0.52

E) 0.58

View Answer

**Option D**

Solution:

P(won at least 1 game)= 1- P(won no games)

=1- [P(lost 1^{st} game)*P(lost second game)]
=1- [(1-0.4)*(1-0.2)]
(0.2) in the second bracket because after losing the first game the probability of wining the second match is 0.2. So 1-0.2 is the probability of losing that game too.

- Find the probability that India wins the first three games.

A) 0.028

B) 0.030

C) 0.032

D) 0.036

E) 0.044

View Answer

**Option D**

Solution:

0.4*0.3*0.3= 0.036

- Find the probability that India wins exactly one of the first three matches.

A) 0.416

B) 0.396

C) 0.096

D) 0.404

E) 0.214

View Answer

**Option D**

Solution:

This problem can be solved in three parts

Part 1- India wins first game and loses second and third

part 2= Lose + Win + Lose

Part 3= Lose + Lose+ Win

P (Part 1)= India wins first game * India loses second game* India loses third game

= 0.4 * (1-0.3)* (1-0.2)= 0.4*0.7*0.8 = 0.224

P (Part2)= India loses first game * Wins second game * Loses third game

= (1-0.4)* 0.2 * (1-0.3)= 0.6*0.2*0.7= 0.084

P (Part 3)= L*L*W = (1-0.4)* (1-0.2) * 0.2= 0.6*0.8*0.2= 0.096

P= P1+P2+P3= 0.404

- Find the probability that India wins exactly one of the first two games.

A) 0.20

B) 0.40

C) 0.44

D) 0.36

E) 0.28

View Answer

**Option B**

Solution:

Part 1= Won first * Lost Second= 0.4* (1-0.3)= 0.4*0.7=0.28

Part 2= Lost First* Won second = (1-0.4)*0.2= 0.6*0.2=0.12

P= 0.28+0.12=0.40

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