Quantitative Aptitude: Data Interpretation Questions Set 40

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams. Casellete based Data Interpretation Set IBPS PO 2017

Direction (1-5): Study the following information and answer the questions that follow:

Vishal and Shekhar have some toffees initially. Everyday Vishal and Shekhar buy a fixed number of toffees. The number of toffees that they buy each day is different from other’s number. After 4 days, they have equal number of toffees. After 12 days Vishal has 8 (16/23)% more toffees than Shekhar. After 13 days, Sunidhi who has no toffee initially, took 6 toffees from Vishal and 3 toffees from Shekhar, as a result now Vishal has 6 toffees more than Shekhar. After 15 days, they all clubbed together their toffees and divided equally among the three. Now each of them has 71 toffees. Based on this information answer the questions that follows.

  1. How many toffees Vishal had initially?
    A) 50
    B) 48
    C) 56
    D) 52
    E) 64
    View Answer
    Option D
    Solution
    :
    Let Vishal has V toffees initially and he buys A toffees each day
    Let Shekhar has S toffees initially and he buys B toffees each day
    After 4 days, they have equal number of toffees.
    hence V+4A = S+4B
    => V-S=4(B-A) —- (i) After 12 days Vishal has 8 (16/23)% =200/13% more toffees than Shekhar
    V + 12A = (S+ 12 B)* (1+2/23)
    => V+12A =25/23 * (S+12B) —– (ii) After 13 days, Sunidhi who has no toffee initially, took 6 toffees from Vishal and 3 toffees from Shekhar, as a result now Vishal has 6 toffees more than Shekhar.
    Toffees with Vishal after 13 days = V+13B ; when 6 toffees given to Sunidhi now he has V+13A-6
    Toffees with Shekhar after 13 days = S +13B; when 3 toffees given to Sunidhi now he has S+13B -3
    also ;
    V+13A-6 = (S+13B -3) + 6
    =>V+13A = S+13B+9
    =>V-S=13(B-A)+9 ———– (iii)
    After 15 days, they all clubbed together their toffees and divided equally among the three. Now each of them has 71 toffees.
    All the toffees that they have after 15 days is due to Vishal and Shekhar, as Sundihi had 0 toffees initially
    So V+15A + S+15B=3*71=213 —- (iv)
    Equate eq (i) and (iii) for V-S = V-S in each equation , so we have now
    4(B-A)= 13(B-A)+9
    We get A-B= 1
    A=1+B—-(v)
    put this in eq (i)
    S-V=4
    S=V+4— (vi)
    Put A=1+B and S=V+4
    in eq (ii) and (iv) to get two equations with two variable
    we will get
    V+12B=88
    and
    V+15B=97
    solve and get
    B=3 and V=52
    hence
    A=4 and S=56
    so now we have all the required value; keep them handy
    V=52; A=4
    S=56; B=3
    So Vishal has 52 toffees initially
  2. How many toffees Shekhar buys everyday?
    A) 2
    B) 3
    C) 4
    D) 5
    E) 6
    View Answer
    Option B
  3. After 14 days how many toffees did Shekhar and Sunidhi had in total?
    A) 101
    B) 104
    C) 107
    D) 110
    E) 113
    View Answer
    Option B
    Solution
    :
    After 14 days Shekhar had 56+14*3 -3 =95 toffees (as 3 toffees have been taken by Sunidhi)
    Sunidhi has 9 toffees
    total=95+9=104
  4. By what percent the number of toffees that Shekhar had was less than that of Vishal after 11 days?
    A) 7.90%
    B) 8.24%
    C) 9.27%
    D) 6.24%
    E) 7.29%
    View Answer
    Option E
    Solution
    :
    After 11 days
    Vishal=52+11*4=96
    Shekhar=56+11*3=89
    Required % = (96-89)/96 *100 =
  5. If Vishal and Shekhar keeps on buying toffees in same manner, then the number of toffees they will have in total after 50 days is?
    A) 402
    B) 503
    C) 387
    D) 457
    E) 458
    View Answer
    Option C
    Solution
    :
    After 15 days they had 71 toffees each
    So After 50 days
    71+71+(50-15)*4 + (50-15)*3= 387

Direction (6-10): Study the following information and answer the questions that follow:

In a bilateral cricket series between India and Australia, the probability that India wins the first game is 0.4. If India wins any game, the probability that it wins the next game is 0.3; otherwise the probability is 0.2.

  1. Find the probability that India wins the first two games.
    A) 0.08
    B) 0.32
    C) 0.18
    D) 0.12
    E) None of these
    View Answer
    Option D
    Solution
    :
    P(Win first game)* P(Win second game)= 0.4*0.3=0.12
  2. Find the probability that India wins at least one of the first two games.
    A) 0.48
    B) 0.32
    C) 0.56
    D) 0.52
    E) 0.58
    View Answer
    Option D
    Solution
    :
    P(won at least 1 game)= 1- P(won no games)
    =1- [P(lost 1st game)*P(lost second game)] =1- [(1-0.4)*(1-0.2)] (0.2) in the second bracket because after losing the first game the probability of wining the second match is 0.2. So 1-0.2 is the probability of losing that game too.
  3. Find the probability that India wins the first three games.
    A) 0.028
    B) 0.030
    C) 0.032
    D) 0.036
    E) 0.044
    View Answer
    Option D
    Solution
    :
    0.4*0.3*0.3= 0.036
  4. Find the probability that India wins exactly one of the first three matches.
    A) 0.416
    B) 0.396
    C) 0.096
    D) 0.404
    E) 0.214
    View Answer
    Option D
    Solution
    :
    This problem can be solved in three parts
    Part 1- India wins first game and loses second and third
    part 2= Lose + Win + Lose
    Part 3= Lose + Lose+ Win
    P (Part 1)= India wins first game * India loses second game* India loses third game
    = 0.4 * (1-0.3)* (1-0.2)= 0.4*0.7*0.8 = 0.224
    P (Part2)= India loses first game * Wins second game * Loses third game
    = (1-0.4)* 0.2 * (1-0.3)= 0.6*0.2*0.7= 0.084
    P (Part 3)= L*L*W = (1-0.4)* (1-0.2) * 0.2= 0.6*0.8*0.2= 0.096
    P= P1+P2+P3= 0.404
  5. Find the probability that India wins exactly one of the first two games.
    A) 0.20
    B) 0.40
    C) 0.44
    D) 0.36
    E) 0.28
    View Answer
    Option B
    Solution
    :
    Part 1= Won first * Lost Second= 0.4* (1-0.3)= 0.4*0.7=0.28
    Part 2= Lost First* Won second = (1-0.4)*0.2= 0.6*0.2=0.12
    P= 0.28+0.12=0.40

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28 Thoughts to “Quantitative Aptitude: Data Interpretation Questions Set 40”

  1. Alice

    superb ques 🙂

  2. Misha

    MAM 5th question not getting understand….

    1. Suraj

      question or solution?

        1. Suraj

          ok
          The questions asks, if Both Vishal and Shekhar buy the toffee at the same rate for 50 days, then how many toffees in total they will have after 50 days
          See this line in the passage After 15 days, they all clubbed together their toffees and divided equally among the three. Now each of them has 71 toffees.
          It means now each of Vishal, Shekhar and Sunidhi have 71 toffees.
          means Vishal and Shekhar till 15 days have = 71 +71 toffees in total
          TO calculate for rest of the days i.e 50-15=35 days, we have to multiply this 35 days with the number of toffees that vishal and shekhar buy every day
          vishal buys 4 toffee every day, shekhar 3 toffees every day
          So total we have
          71 + 71 +35*4 + 35*3

          1. Misha

            thanK U SIR

          2. Misha

            sir in probability questions i’ve always doubt…what should i do for that topic…

          3. Suraj

            for probability you must know permutation and combination also. So take any book of quants, give some time to these three chapters, Permutation, Combination and then probability,, first leran the concept and practice some solved questions. Then solve lots of questions without seeing the solution,, spend some time on these topics,, u can ask any doubts after that here on our doubt page: http://aspirantszone.com/discussion-zone-doubts-page-1

      1. mimi

        sir in probability qn it is written – If India wins any game, the probability that it wins the next game is 0.3; otherwise the probability is 0.2.
        this means what? what i unstd is probability of winning first game is 0.4
        winning 2nd game is 0.3
        n loosing 2nd game is 0.2
        am i right??
        if it is so then why in qn 7,9 and 10 it is written that loosing 2nd game is (1-0.3)
        sir plz explain this .. asap

        1. Suraj

          if india wins any game then the probability to win the next game is 0.3
          if india loses any game then the probability to win next game is 0.2

          1. mimi

            The game India wins or loses is the first game??

          2. Suraj

            which ques?

          3. mimi

            Sir m talking about ur prv reply to my qn

          4. Suraj

            Not necessarily.. for the first game win the prob is given 0.4
            Prob for win just after another win is 0.3 .
            Means prob of a person winningfirst three games is 0.4×0.3×0.
            see that even for 3rd game we have taken 0.3 .. because prob for win just after another win is 0.3 .
            0.4 is only for 1st game

          5. mimi

            oh .. tq sir..
            sir plz update daily with di , reasoining and eng quizzes..
            these are very gud collection

          6. study time;)

            1))6 1/2 (2)4 hour

          7. study time;)

            4))32//5))13 1/5

          8. <>>>>>>>>>>>>>

            sir,plz explain it.

          9. study time;)

            sir plz provide di based on pipe and cistain

      2. AMAZON

        After 12 days Vishal has 8 (16/23)% =200/13% more toffees than Shekhar
        V + 12A = (S+ 12 B)* (1+2/23)
        => V+12A =25/23 * (S+12B)

        @@surajskt:disqus sir can you explain this step?

        1. Suraj

          It is given 8 (16/23)% more = 200/23 %
          or (100 + 200/23)/100
          = 1 + 2/23

  3. Sneha Dubey

    sir, probability ke questions bhut achhe h…please provide more questions on probability..

  4. cActi

    @surajskt:disqus ??

  5. Richard Parker

    thank you AZ for these good questions

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