Mixed Quantitative Aptitude Questions Set 106

Directions(1-5): Find the missing term “?” of the following series.

1. 27,40,66,105,?,222
   142
   150
   147
   157
   140
   Option D
   +13*1
   +13*2
   +13*3
   +13*4
   +13*5
   ? = 157

    

2. 230,240,260,?,380,540
   300
   220
   310
   280
   200
   Option A
   +10
   +20
   +40
   +80
   +160
   ? = 300

    

3. 57,?,63,69,77,87
   59
   42
   40
   44
   50
   Option A
   +2,+4,+6,+8,+10
   ? = 59

    

4. 35,36,74,225,?,4525
   904
   950
   888
   910
   890
   Option A
   +1*1
   +2*2
   +3*3
   +4*4
   +5*5
   ? = 904

    

5. 350,349,341,314,?,125
   200
   250
   210
   245
   230
   Option B
   -1^3, -2^3, -3^3, -4^3, -5^3
   ? = 250

    

6. Karan invested a sum of Rs.4800 partially in two schemes A and B in the ratio of 2:x resp. Scheme A and scheme B is offering simple interest of 8% and 6% per annum resp. If the simple interest earned from scheme A after 3 years is equal to the simple interest earned from scheme B after 8 years , then find the value of x?
   3
   2
   4
   5
   1
   Option E
   Amount invested in scheme A = 2/(2+x)*4800 = Rs.9600/(2+x)
   Amount invested in scheme B = x/(2+x)*4800 = Rs.4800x/(2+x)
   Now, 9600/[2+x]*8%*3 = 4800x/[2+x]*6%*8
   => x = 1

    

7. 720 litres of milk and water in the ratio of 5:3 resp. If (x+5)% of this mixture is taken out and is mixed with 6 litres of water in a bucket such that the quantity of water in the bucket is 60 litres, then find the value of x ?
   10
   15
   12
   13
   16
   Option B
   Quantity of milk in the solution = (5/8)*720 = 450 litres
   Quantity of water in the solution = 720 – 450 = 270 litres
   Now, (x+5)% of 270 + 6 = 60
   => x = 15

    

8. The total time taken by a boatman to travel a distance of (x+60) km upstream and (x-30) km downstream is 26 hours. If the boat speed and speed of stream is 12 km/hr. and 3 kmhr. resp. find the time taken by the boatman to travel (x+42) km upstream.
   18 hours
   16 hours
   14 hours
   13 hours
   10 hours
   Option A
   Downstream speed of boat = 12+3 = 15 km/hr.
   Upstream speed of boat = 12- 3 = 9 km/hr.
   Therefore, (x+60)/9 + (x-30)/15 = 26
   => (10x + 600 + 6x – 180)/90 = 26
   => x = 1920/16 = 120
   Required time = (120+42)/9 = 18 hours

    

9. The length of the cuboidal room is equal to the length of side of square of area is 576 m^2. If the breadth and height of the cuboidal room is 12 m and 8 m resp. find the maximum length of a stick that can be placed inside the room.
   25 m
   20 m
   28 m
   23 m
   22 m
   Option C
   Length of the cuboidal room = (576)^1/2 = 24 m
   Breadth = 12 m
   Height = 8 m
   Required length of the stick = (24^2+12^2+8^2)^1/2
   = 28 m

    

10. A student bought a pen and notebook for Rs. 200. He sold the notebook at a profit of 20% and the pen at a loss of 30%. If in the whole transaction, he made a profit of Rs.15 find the cost price of notebook.
    160
    140
    100
    150
    130
    Option D
    Let the CP of notebook be x.
    CP of pen = (200 – x)
    Now, 0.2x – 0.3(200 – x) = 15
    => 0.2x – 60 + 0.3x = 15
    => x = 150