# Mixed Quantitative Aptitude Questions Set 106

Directions(1-5): Find the missing term “?” of the following series.

1. 27,40,66,105,?,222
142
150
147
157
140
Option D
+13*1
+13*2
+13*3
+13*4
+13*5
? = 157

2. 230,240,260,?,380,540
300
220
310
280
200
Option A
+10
+20
+40
+80
+160
? = 300

3. 57,?,63,69,77,87
59
42
40
44
50
Option A
+2,+4,+6,+8,+10
? = 59

4. 35,36,74,225,?,4525
904
950
888
910
890
Option A
+1*1
+2*2
+3*3
+4*4
+5*5
? = 904

5. 350,349,341,314,?,125
200
250
210
245
230
Option B
-1^3, -2^3, -3^3, -4^3, -5^3
? = 250

6. Karan invested a sum of Rs.4800 partially in two schemes A and B in the ratio of 2:x resp. Scheme A and scheme B is offering simple interest of 8% and 6% per annum resp. If the simple interest earned from scheme A after 3 years is equal to the simple interest earned from scheme B after 8 years , then find the value of x?
3
2
4
5
1
Option E
Amount invested in scheme A = 2/(2+x)*4800 = Rs.9600/(2+x)
Amount invested in scheme B = x/(2+x)*4800 = Rs.4800x/(2+x)
Now, 9600/[2+x]*8%*3 = 4800x/[2+x]*6%*8
=> x = 1

7. 720 litres of milk and water in the ratio of 5:3 resp. If (x+5)% of this mixture is taken out and is mixed with 6 litres of water in a bucket such that the quantity of water in the bucket is 60 litres, then find the value of x ?
10
15
12
13
16
Option B
Quantity of milk in the solution = (5/8)*720 = 450 litres
Quantity of water in the solution = 720 – 450 = 270 litres
Now, (x+5)% of 270 + 6 = 60
=> x = 15

8. The total time taken by a boatman to travel a distance of (x+60) km upstream and (x-30) km downstream is 26 hours. If the boat speed and speed of stream is 12 km/hr. and 3 kmhr. resp. find the time taken by the boatman to travel (x+42) km upstream.
18 hours
16 hours
14 hours
13 hours
10 hours
Option A
Downstream speed of boat = 12+3 = 15 km/hr.
Upstream speed of boat = 12- 3 = 9 km/hr.
Therefore, (x+60)/9 + (x-30)/15 = 26
=> (10x + 600 + 6x – 180)/90 = 26
=> x = 1920/16 = 120
Required time = (120+42)/9 = 18 hours

9. The length of the cuboidal room is equal to the length of side of square of area is 576 m^2. If the breadth and height of the cuboidal room is 12 m and 8 m resp. find the maximum length of a stick that can be placed inside the room.
25 m
20 m
28 m
23 m
22 m
Option C
Length of the cuboidal room = (576)^1/2 = 24 m
Height = 8 m
Required length of the stick = (24^2+12^2+8^2)^1/2
= 28 m

10. A student bought a pen and notebook for Rs. 200. He sold the notebook at a profit of 20% and the pen at a loss of 30%. If in the whole transaction, he made a profit of Rs.15 find the cost price of notebook.
160
140
100
150
130
Option D
Let the CP of notebook be x.
CP of pen = (200 – x)
Now, 0.2x – 0.3(200 – x) = 15
=> 0.2x – 60 + 0.3x = 15
=> x = 150