**Directions(1-5): **What approximate value will come in place of question mark ‘?’ in the following questions.

- [30% ๐๐ {(80% ๐๐ 850) รท 34}] = ?
1198614Option D

[30% ๐๐ {(80% ๐๐ 850) รท 34}] = ?

? = [ 30/100 ร {( 80/100 ร 850) รท 34}] = [ 30/100 ร {680 รท 34}] = [ 30/100 ร 20] = 6 - 65% ๐๐ 240+ ?% ๐๐ 150 = 210
4036445852Option B

65% ๐๐ 240+ ?% ๐๐ 150 = 210

=65/100 ๐๐ 240 + ?/100 ๐๐ 150 = 210

โ 156 + 1.5 ร? = 210

=>? = (210โ156)/1.5 = 36 - ? % of 800 = 293 โ 22% of 750
2018101612Option D

? % of 800 = 293 โ 22% of 750

=>800 ร? /100 = 293 โ (750 ร 22)/100

โ 8 ร ? = 293 โ 165 = 128

โ ? = 128/8 = 16 - 1425 + 8560 + 1680 รท 200 = ?
99939120900391919009Option A

1425 + 8560 + 1680 รท 200 = ?

=> ? = 1425 + 8560 + 1680 รท 200

= 1425 + 8560 + 1680 200

= 9985 + 8.4 = 9993.4 == 9993 - 555.05 + 55.50 + 5.55 + 5 + 0.55 = ?
660622600616624Option B

555.05 + 55.50 + 5.55 + 5 + 0.55 = ?

=> ? = 555.05 + 55.50 + 5.55 + 5 + 0.55

= 621.65 == 622 - If Aโs salary is 25% higher than Bโs salary, then how much per cent is Bโs salary lower than Aโs?
50%40%30%20%60%Option D

A = B + 25% of B

โ ๐ด = ๐ต + ๐ต/ 4 = 5๐ต/ 4

โ ๐ต = 4/5 ๐ด = ๐ด โ 1/5 ๐ด

= ๐ด โ 20% ๐๐ A = 20% - The sides of a triangle are in the ratio of 1/2 โถ 1/3 โถ 1/4 . If the perimeter is 52 cm, then the length of the smallest side is:
1016122013Option C

Sides of a triangle are in ratio 1/2 โถ 1/3 โถ 1/4 ,

i.e., 6 : 4 : 3. Let the sides be 6K, 4K and 3K, respectively.

13K = 52

โ K = 4

Sides of the triangle are 24 cm, 16 cm and 12 cm, respectively - Ravi sells an article at a gain of 12(1/2)%. If he had sold it at Rs. 22.50 more, he would have gained 25% The cost price of the article is:
180120140190160Option A

12 (1/ 2) % = Rs 22.50

โ C.P. = Rs 180 - A certain job was assigned to a group of men to do it in 20 days. But 12 men did not turn up for the job and the remaining men did the job in 32 days. The original number of men in the group was:
3530313233Option D

Suppose x = original number of men in the group (x- 12) men did the job in 32 days

20x = 32(x โ 12)

=>x = 32 - A vessel contains liquid P and Q in the ratio 5 : 3. If 16 litres of the mixture are removed and the same quantity of liquid Q is added, the ratio become 3 : 5. What quantity does the vessel hold?
6050708040Option E

Let, the quantity of liquid P and Q be 5x and 3x litres respectively.

Quantity of P removed = 5/( 5+3) ร 16 = 10 litres

Quantity of Q removed = 3/(5+3 )ร 16 = 6 litres

Now, 5๐ฅโ10/(3๐ฅโ6+16) = 3/5

โ 25๐ฅ โ 50 = 9๐ฅ + 30

โ 16๐ฅ = 80

โ ๐ฅ = 5

Quantity that vessel hold = 8 ร5 = 40 litres