Mixed Quantitative Aptitude Questions Set 164

Directions(1-10): Find the approximate value of the following questions.

1. 52.012% of 749.75 + 22.05 * ? = 874.07
15
10
25
22
27
Option D
52.012% of 749.75 + 22.05 * ? = 874.07
=>52% of 750 + 22*? = 874
=> 390 + 22*? = 874
=>? = 22

2. 38.78^2 – 77.73*8.99 – 25.08*12.04 = ?
400
500
200
300
100
Option B
38.78^2 – 77.73*8.99 – 25.08*12.04 = ?
=>40^2 – 80*10 – 25*12 = ?
=>1600 – 800 – 300 =?
=>? = 500

3. 24.05*11.86 – 416.05/16.98 – 108.56 = ?
140
152
120
133
148
Option B
24.05*11.86 – 416.05/16.98 – 108.56 = ?
=> 24*12 – 416/16 – 110 = ?
=>288 – 26 – 110 = ?
=>? = 152

4. 22.25% of 29.69% of 48.12% of 4260 = 50.08% of ?
220
245
261
258
240
Option D
22.25% of 29.69% of 48.12% of 4260 = 50.08% of ?
=>20% of 30% of 50% of 4300=50% of ?
=>? = 258

5. (3100/124)*(8^3 /32) = ?^2
10
30
40
20
50
Option D
(3100/124)*(8^3 /32) = ?^2
=>?^2 = 25*(512/32)
=>?^2 = 25*16
=>? = 20

6. At what rate of interest an amount of Rs.16000 will become Rs.25000 in 2 years if the rate is compounded annually.
27%
22%
25%
15%
20%
Option C
25000 = 16000{1+r/100}^2
r = 25%

7. Five years ago, Rahul was 20 years elder than Raj. After 15 years, the ratio of their ages is 2:3. Find the average of their present ages.
32 years
25 years
20 years
30 years
35 years
Option E
Let the present ages of Rahul and Raj be x and y resp.
x = y +20 —-(1)
And (y+15)/(x+15) = 2/3 —-(2)
On solving both the equations, we get
x = 45 years
y = 25 years
Average = 70/2 = 35 years

8. A shopkeeper marked his goods 60% above cost price and gave a discount of 25%. Find the profit percentage of shopkeeper.
30%
25%
20%
15%
10%
Option C
Profit% = {(120-100)/100}*100 = 20%

9. A boat can cover 36 km upstream in 6 hours, and 84 km downstream in 7 hours. Find the ratio of speed of boat in still water to speed of stream.
3:4
2:5
3:1
4:1
3:2
Option C
Required ratio =(12+6)/2 : (12-6)/2
= 3:1

10. A 260 ml mixture contains water and acid in the ratio 6:7 resp. How much acid should be added to the mixture so that the ratio of water and acid changes to 3:5 resp.
30 ml
60 ml
20 ml
50 ml
40 ml
Option B
Quantity of water = 120 ml
Quantity of acid = 140 ml
Now,
120/(140+x) = 3/5
=> x= 60 ml