**Directions(1-10):** Find the approximate value of the following questions.

- 52.012% of 749.75 + 22.05 * ? = 874.07
1510252227Option D

52.012% of 749.75 + 22.05 * ? = 874.07

=>52% of 750 + 22*? = 874

=> 390 + 22*? = 874

=>? = 22 - 38.78^2 – 77.73*8.99 – 25.08*12.04 = ?
400500200300100Option B

38.78^2 – 77.73*8.99 – 25.08*12.04 = ?

=>40^2 – 80*10 – 25*12 = ?

=>1600 – 800 – 300 =?

=>? = 500 - 24.05*11.86 – 416.05/16.98 – 108.56 = ?
140152120133148Option B

24.05*11.86 – 416.05/16.98 – 108.56 = ?

=> 24*12 – 416/16 – 110 = ?

=>288 – 26 – 110 = ?

=>? = 152 - 22.25% of 29.69% of 48.12% of 4260 = 50.08% of ?
220245261258240Option D

22.25% of 29.69% of 48.12% of 4260 = 50.08% of ?

=>20% of 30% of 50% of 4300=50% of ?

=>? = 258 - (3100/124)*(8^3 /32) = ?^2
1030402050Option D

(3100/124)*(8^3 /32) = ?^2

=>?^2 = 25*(512/32)

=>?^2 = 25*16

=>? = 20 - At what rate of interest an amount of Rs.16000 will become Rs.25000 in 2 years if the rate is compounded annually.
27%22%25%15%20%Option C

25000 = 16000{1+r/100}^2

r = 25% - Five years ago, Rahul was 20 years elder than Raj. After 15 years, the ratio of their ages is 2:3. Find the average of their present ages.
32 years25 years20 years30 years35 yearsOption E

Let the present ages of Rahul and Raj be x and y resp.

x = y +20 —-(1)

And (y+15)/(x+15) = 2/3 —-(2)

On solving both the equations, we get

x = 45 years

y = 25 years

Average = 70/2 = 35 years - A shopkeeper marked his goods 60% above cost price and gave a discount of 25%. Find the profit percentage of shopkeeper.
30%25%20%15%10%Option C

Profit% = {(120-100)/100}*100 = 20% - A boat can cover 36 km upstream in 6 hours, and 84 km downstream in 7 hours. Find the ratio of speed of boat in still water to speed of stream.
3:42:53:14:13:2Option C

Required ratio =(12+6)/2 : (12-6)/2

= 3:1 - A 260 ml mixture contains water and acid in the ratio 6:7 resp. How much acid should be added to the mixture so that the ratio of water and acid changes to 3:5 resp.
30 ml60 ml20 ml50 ml40 mlOption B

Quantity of water = 120 ml

Quantity of acid = 140 ml

Now,

120/(140+x) = 3/5

=> x= 60 ml