Mixed Quantitative Aptitude Questions Set 177

  1. The L.C.M of 4/2, 2/6, 8/9 is
    5/3
    6/3
    7/3
    8/3
    10/3
    Option D
    L.C.M= L.C.M of numerator/H.C.F of denominator
    =L.C.M of 4,2,8/H.C.F of 3,6,9=8/3

     

  2. The ratio between two number is 6:5 if their HCF is 10. Then the numbers are.
    10,20
    40,50
    60,50
    50,70
    30,80
    Option C
    Let the number be 6x, 5x
    HCF of 6x,5x=x
    ie) x=10(given)
    Then the numbers are 6x,5x=60,50

     

  3. Find the average of first 14 natural number.
    105
    109
    111
    134
    156
    Option A
    average of first n natural number=n(n+1)/2
    here n=14
    average=14(14+1)/2=7×15=105

     

  4. The sum of ages of three sister born of the intervals of 2 years each is 42 years. What is the age of the youngest sister ?
    11
    12
    13
    14
    15
    Option B
    x+(x+2)+(x+4)=42 (given the intervals are 2 years)
    3x+6=42  x =36/2=12
     Age of the youngest sister=12 years

     

  5. Cost of a mobile is Rs .5000 and selling price is Rs. 7000.What is the profit percent?
    30
    35
    40
    45
    50
    Option C
    Profit % = p/c.p x 100
    =2000/5000 x 100
    P%=40

     

  6. Ganesh can do a task in 4days . Prem can do a task in 3 days. How long if will take if both Ganesh &Prem work together?
    2 d 3 hr
    4d 6 hr
    6 d 7 hr
    1 d 5 hr
    4 d 3 hr
    Option D
    Ganesh 1day work=1/4
    Prem 1day work =1/3
    (Ganesh+Prem) =1/4+1/3=7/12
    So Ganesh& Prem will complete in 12/7=1 5/7=1day 5hrs together.

     

  7. If a boat travels with a speed 25km/hr in still water and the speed of stream is 5km/hrs . What would be the time taken by boat to go 40 km upstream?
    2
    4
    6
    8
    10
    Option A
    Upstream speed = x-y km/hr
    =25-5=20 km/hr
    T=distance/speed
    T=40/20=2hrs

     

  8. what is the simple interest on Rs 60000 at 5 ½% per annum for 2 years?
    5900
    6600
    7700
    6800
    7800
    Option B
    S.I = P X R X T/100=60000 x 5 ½ x 2/ 100
    S.I=Rs 6600

     

  9. Ram deposits Rs .20,000 for 2years with 5% compound interest. What amount will be get at last?
    22050
    45000
    13500
    26500
    24000
    Option A
    Amount= P x (1+r/100)n
    =20000 X (1+5/100)2
    =20000 x 105/100)2
    =20000x 105×105/10000
    =Rs .22050

     

  10. A florist choose one rose at random from the basket which have rainbow colors of roses. what is the probability of choosing yellow color rose?
    1/8
    1/7
    1/9
    1/5
    1/6
    Option B
    S=(rainbow color roses)
    S=(V,I,B,G,Y,O,R)=N(S)=7
    P(Yellow rose)=P(S)/N(S)=1/7 (Only one yellow rose)

     

  11. How many multiples of 2 are there in 10 to 80?
    42
    40
    38
    36
    48
    Option D
    Multiples of 2 =>last digits must be 0, 2, 4, 6, 8
    And first digit 1,2 ,3,4,5,6,7,
    So there are 7 choices for the first number and 5 choices for the second number.
    So there are 5x 7 =3 5 + 1= 36 (include 80) multiples of 2 in between 10 and 80.

     

  12. In a shop two partners invested in the ratio 10:20 and they got the profits in the ratio 5:4.If the first partner invest the money for 10 months the how many months the second partner invested?
    12
    14
    16
    18
    20
    Option C
    Investment ratio: 10:20
    Profit ratio :5:4
    First partner invested 10 months.
    Second parner invested x (take) months.
    So 10 x 20 / 10 x x = 5/4
    20/x = 5/4
    x = 16 months

     

  13. Two glasses of equal capacity contains sand and color powder.The ratio of the mixing is 2:3 and 5:4 respectively. These mixture are transferred into a big bowl.Then what is the ratio of sand and color powder in the bowl?
    1:4
    5:7
    2:9
    7:7
    4:5
    Option D
    Ratio= 2 + 5 : 3+4 = 7: 7

     

  14. The population of mosquitoes in a certain colony doubles every two hours. If 4 hours ago there were 1,000 mosquitoe in the colony, in approximately how many hours will the colony population exceed 250,000 mosquitoe?

    6
    8
    10
    12
    14
    Option D
    4 hrs ago= 1000
    now = 4000
    12 hrs= 2,56,000 So approximately 12 hrs.

     

  15. A boy can work equal to 2 days of girl in a day. One child can work one-third of the work done by a girl in 1 day. If an company owner hires 52 pairs of hands of boys, girls and children in the ratio of 6 : 5 : 2 and pays them in all Rs.1060 at the end of the work, then what will be the daily wages (in rupees) of a child?
    4
    5
    6
    7
    8
    Option B
    1 boy = 2 girl and 1 girl = 3 children
    Work done by 1 boy= work done by 2 girls= work done by 6 children
    Ratio of their efficiency = 6 : 3 : 1
    Let an estate-owner hires boys, girls and children as 6x, 5x and 2x respectively.
    Given,
    6x+5x+2x= 52
    Or x=4
    Number of boys = 24
    girls=20 and children = 8
    As wages are proportional to the amount of work done, then
    Wages divided into ratio of = = 36 : 15 : 2
    Share of children=1060/53 *2 = 40
    Share of 1 child = 40/8=5

     

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