Mixed Quantitative Aptitude Questions Set 212

  1. P1 and P2 are the two pockets were made by mixing chilli powder and turmeric powder in the ratio 3:5 and 5:9 respectively.If 60 grams of P1 and x grams of P2 are mixed to get pocket P3, then fid out the value of x , if the ratio of chilli and turmeric in the new pocket P3 is 35:61?
    70g
    56g
    98g
    84g
    112g
    Option D
    In x gram of P2
    chilli = 5x/14
    turmeric= 9x/14
    in 60 gm in P1
    chilli=60 * 3/8= 45/2
    turmeric=60 85/8=75/2
    and =>(45/2 +5x/14) / (75/2+9x/14) = 35/61
    =>x= 84g

     

  2. Rakesh bought a loan Rs.3,00,000 in a newyear scheme which gives r% per annum at Compound interest and this scheme doubles the loan in 72/r years which is double of the rate of interest given by the scheme.Find the total amount paid by Rakesh at the end of 48 years?
    12lac
    34lac
    45lac
    48lac
    64lac
    Option D
    given 72/r= 2r
    => r=6%
    So the loan amount double in 12 years.
    =>6,00, 000= 3,00,000 ( 1+ r/100 ) ^12
    =>1+ r/ 100 ) ^ 12= 2
    So required loan amount to pay = 3,00,000 ( 1+ r/100 ) ^ 48 = 3,00,000 *2^ 4 = Rs. 48,00,000

     

  3. karthik and kathir’s current age is 7: 5 and 3 years back their ages were 16:11. So what is the age of kathir after 5 years?
    15
    25
    30
    40
    23
    Option C
    let their ages be 5x and 7x .
    so 7x-3/5x-3 = 16/11
    => x= 5
    Hence the age of kathir = 5* 5+ 5= 30 years

     

  4. Person 1 started a business y investing Rs. A after 4 months person 2 also joined with the investment of Rs. x+ 10,000. But the end of the year their profit are same. Then what is the amount invested by person 2?
    20,000
    14,000
    15,000
    45,000
    30,000
    Option E
    p1 P2
    investment x x+10,000

    time 12 8
    12x 8x+ 80,000
    12x= 8x + 80,000
    =>x=20,000
    hence person 2 investment = 30,000

     

  5. An house is on sale is said to 50% above its original price. But after the seller gives discount and gets only 20% profit. Find the percentage of discount ?
    10%
    20%
    30%
    40%
    50%
    Option B
    let the original price of the house = 100x
    Then said price= 100x * 150/100= 150x
    SP= 120x
    discount% = 30x/150x * 100 = 20%

     

  6. If the sum of the speed of a boat upsteam and down stream is 36kmph and speed of the stream is 1/3 of the speed of the boat. Find the time taken to travel 108 km upstream and 96km downstream by the boat?
    10 hrs
    11 hrs
    12hrs
    13hrs
    14hrs
    Option D
    speed of boat =36/2= 18kmph
    speed of stream = 1/3 * 18 = 6kmph
    Time = 108/18-6 + 96/ 18+ 6
    =13hrs

     

  7. Person A and Person B are 10 km apart. A can walk at an average speed of 2 km/hr and B at 3 km/h. If they start walking towards each other at 5:30 pm, when they will meet?
    7:30 pm
    7:30 pm
    10:30 pm
    9:30 pm
    6:30 pm
    Option A
    Suppose they will meet after T hours.
    Distance = Speed x Time
    Sum of distance traveled by them after T hours
    3T + 2T = 10 km
    T = 2 hours.
    So they will meet at 5:30 pm + 2 hours = 7:30 pm

     

  8. Find the greatest possible length of scale which can be used to measure the iron bar 8m 3cm, 8m 34cm and 9m 30cm exactly.
    63cm
    64cm
    61cm
    62cm
    60cm
    Option D
    Required measure of scale = HCF of 803, 834 and 930
    = 62 cm

     

  9. A seller marked an article at Rs 500 and sold it allowing 20% discount. If his profit was 25%, then the cost price of the article was
    Rs.310
    Rs.300
    Rs.320
    Rs.280
    Rs.330
    Option C
    ∵ Marked price of an article = 500
    ∴ SP of an article = 500 x (100 – 20)/100
    = (500 x 80)/100
    = 400

    Hence, cost price of an article = (400 x 100)/(100 + 25)
    = (400 x 100)/125
    = 320

     

  10. Kajal traveled 12000 km by plane1 which formed (1/5) of his trip. One-third of the whole trip he traveled by plane2 And the rest of the journey he performed by plane3. The distance traveled by plane3 was ?
    20,000 km
    15,000 km
    18,000 km
    24,000 km
    28,000 km
    Option E
    Let the total distance be y km.
    Then, 1y / 5 = 12000
    ⇒ y = (12000 x 5) /1= 60000 km.

    Distance traveled by plane 2
    = (1/3 X 60000) = 20,000 km.

    Distance traveled by plane3
    = [60000- (20000 + 12000) ] km.
    = 28,000 km.

     

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