- P1 and P2 are the two pockets were made by mixing chilli powder and turmeric powder in the ratio 3:5 and 5:9 respectively.If 60 grams of P1 and x grams of P2 are mixed to get pocket P3, then fid out the value of x , if the ratio of chilli and turmeric in the new pocket P3 is 35:61?
70g56g98g84g112gOption D

In x gram of P2

chilli = 5x/14

turmeric= 9x/14

in 60 gm in P1

chilli=60 * 3/8= 45/2

turmeric=60 85/8=75/2

and =>(45/2 +5x/14) / (75/2+9x/14) = 35/61

=>x= 84g - Rakesh bought a loan Rs.3,00,000 in a newyear scheme which gives r% per annum at Compound interest and this scheme doubles the loan in 72/r years which is double of the rate of interest given by the scheme.Find the total amount paid by Rakesh at the end of 48 years?
12lac34lac45lac48lac64lacOption D

given 72/r= 2r

=> r=6%

So the loan amount double in 12 years.

=>6,00, 000= 3,00,000 ( 1+ r/100 ) ^12

=>1+ r/ 100 ) ^ 12= 2

So required loan amount to pay = 3,00,000 ( 1+ r/100 ) ^ 48 = 3,00,000 *2^ 4 = Rs. 48,00,000 - karthik and kathir’s current age is 7: 5 and 3 years back their ages were 16:11. So what is the age of kathir after 5 years?

1525304023Option C

let their ages be 5x and 7x .

so 7x-3/5x-3 = 16/11

=> x= 5

Hence the age of kathir = 5* 5+ 5= 30 years - Person 1 started a business y investing Rs. A after 4 months person 2 also joined with the investment of Rs. x+ 10,000. But the end of the year their profit are same. Then what is the amount invested by person 2?
20,00014,00015,00045,00030,000Option E

p1 P2

investment x x+10,000time 12 8

12x 8x+ 80,000

12x= 8x + 80,000

=>x=20,000

hence person 2 investment = 30,000 - An house is on sale is said to 50% above its original price. But after the seller gives discount and gets only 20% profit. Find the percentage of discount ?
10%20%30%40%50%Option B

let the original price of the house = 100x

Then said price= 100x * 150/100= 150x

SP= 120x

discount% = 30x/150x * 100 = 20% - If the sum of the speed of a boat upsteam and down stream is 36kmph and speed of the stream is 1/3 of the speed of the boat. Find the time taken to travel 108 km upstream and 96km downstream by the boat?
10 hrs11 hrs12hrs13hrs14hrsOption D

speed of boat =36/2= 18kmph

speed of stream = 1/3 * 18 = 6kmph

Time = 108/18-6 + 96/ 18+ 6

=13hrs - Person A and Person B are 10 km apart. A can walk at an average speed of 2 km/hr and B at 3 km/h. If they start walking towards each other at 5:30 pm, when they will meet?

7:30 pm7:30 pm10:30 pm9:30 pm6:30 pmOption A

Suppose they will meet after T hours.

Distance = Speed x Time

Sum of distance traveled by them after T hours

3T + 2T = 10 km

T = 2 hours.

So they will meet at 5:30 pm + 2 hours = 7:30 pm - Find the greatest possible length of scale which can be used to measure the iron bar 8m 3cm, 8m 34cm and 9m 30cm exactly.
63cm64cm61cm62cm60cmOption D

Required measure of scale = HCF of 803, 834 and 930

= 62 cm - A seller marked an article at Rs 500 and sold it allowing 20% discount. If his profit was 25%, then the cost price of the article was

Rs.310Rs.300Rs.320Rs.280Rs.330Option C

∵ Marked price of an article = 500

∴ SP of an article = 500 x (100 – 20)/100

= (500 x 80)/100

= 400Hence, cost price of an article = (400 x 100)/(100 + 25)

= (400 x 100)/125

= 320 - Kajal traveled 12000 km by plane1 which formed (1/5) of his trip. One-third of the whole trip he traveled by plane2 And the rest of the journey he performed by plane3. The distance traveled by plane3 was ?
20,000 km15,000 km18,000 km24,000 km28,000 kmOption E

Let the total distance be y km.

Then, 1y / 5 = 12000

⇒ y = (12000 x 5) /1= 60000 km.Distance traveled by plane 2

= (1/3 X 60000) = 20,000 km.Distance traveled by plane3

= [60000- (20000 + 12000) ] km.

= 28,000 km.