Mixed Quantitative Aptitude Questions Set 222

  1. While we add 4 to the numerator of the fraction and increases denominator by 50% then both become equal. When the numerator is increased by 5 and denominator is doubled then it becomes equal to the original fraction. What will be two times of that fraction ?
    2/5
    5/3
    2/7
    4/5
    4/3
    Option B
    Let the numerator and denominator of a fraction be x and y respectively.
    ATQ, x + 4 = 3y/2
    x + 5/2y = x/y
    by solving two equations,
    x = 5, y = 6
    original fraction = 5/6
    required fraction = 5/6 * 2 = 5/3

     

  2. Two dices are rolled together, then find probability of getting a number of one dice greater than the number on other dice ?
    2/3
    7/6
    5/6
    2/5
    4/7
    Option C
    total number of cases = 6 * 6 = 36
    total cases of getting same number = (1,1), (2,2), 3,3), (4,4), (5,5), (6,6) = 6
    probability = 1 – 6/36 = 5/6

     

  3. P, Q, R are three inlet pipes. Time taken by P and Q together to fill half of the tank is same as time taken by pipe R alone to fill one-sixth of the tank. If P, Q, R together can fill the tank in 9 hours, then find time taken by pipe R alone to fill the tank ?
    34 hours
    42 hours
    24 hours
    36 yours
    40 yours
    Option D
    ATQ, 2(P+Q) = 6R
    P + Q = 3R
    P + Q + R = 1/9
    4R = 1/9
    R = 36 hours

     

  4. A man cuts a square field of maximum possible area from his circular field. Find the area of the remaining circular field, if the cost of grass cutting of the square field at rs. 4 per m^2 is rs.882 ?
    154 m^2
    126 m^2
    200 m^2
    348 m^2
    180 m^2
    Option B
    Let side of square be = a meters
    radius of circle = r meters
    area of the square field = 220.5 m^2
    diagonal of the square field = 21 m
    radius of the circular field = 10.5 m
    area of the circular field = 346.5 m^2
    area of the remaining circular field = 126 m^2

     

  5. Rohit invested rs.1600 on CI for two years at the rate of R% p.a and gets amount of rs.2304. If man invested same sum on SI for same period of time at the rate of ( R – 8)%, then find interest he will get ?
    450
    384
    420
    640
    260
    Option B
    ATQ,
    2304 = 1600 ( 1 + R/100)^2
    48/40 = ( 1 + R/100)
    R = 20%
    New rate = (20 – 8) = 12%
    required interest = 1600 * 12 * 2/100 = 384

     

  6. directions : What will be come in place of questions marks (?) in the following questions given below ?
    428, 434, 446, 466, 496 ?
    620
    538
    580
    650
    940
    Option B
    The series is, +(2 * 3), +(3 * 4), +(4 * 5), +(5 * 6), +(6 * 7)

     

  7. 187, 193, 205, ?, 277, 373
    198
    229
    240
    350
    270
    Option B
    The series is (+6), (+12), (+24), (+48), (+96)

     

  8. 144, 72, 108, 270, ?, 4252.5
    320
    620
    825
    945
    480
    Option D
    The series is, (* .5), (* 1.5), (* 2.5), (* 3.5), (* 4.5)

     

  9. 81, ? 76, 92, 67, 103
    73
    85
    65
    76
    84
    Option B
    The series is, (+ 2^2), (- 3^2), (+ 4^2), (- 5^2), (+ 6^2)

     

  10. 11, 13, 22, ?, 115, 241
    48
    56
    75
    50
    82
    Option D
    the series is, +(1^3 + 1), +(2^3 + 1), +(3^3 + 1), +(4^3 + 1), + (5^3 + 1)

     

Related posts

Leave a Comment