What is the monthly income of Jitu ? I. Jitu spends 85% of his income on various expenses and remaining amount he saved. II. Monthly saving of Jitu are rs.7500. III. Out of total money spent by Jitu in a month, one-fifth is spent on rent and remaining amount of rs.34000 on other items.
Only I and II sufficient
Only II and III sufficient
Only I and II sufficient
Neither I nor II and III is sufficient
Any of the two statements is sufficient
Option E Let income of Jitu = rs.x from I and II, 15% of x = 7500 x = 7500 * 100/15 = 50000 From I and III, x * 85/100 * 4/5 = 34000 x = 50000 from I and III 4/5 th of expenditure = 34000 expenditure = 42500 income = 42500 + 7500 = 50000 thus, answer can be find out by any of two given statement
How much time will require the train to reach from point X to point Y ? I. The train will pass the other train of equal length of 400m running opposite in direction in 16 secs II. Distance between point X and Y is 252 km. III. The 400m long train crosses a signal pole in 20sec.
Only I and II is sufficient
Only II and III is sufficient
Neither of any statement is sufficient
All statements are sufficient
Only I and III is sufficient
Option B Statement I is not required to get answer from statement III, Speed of train = 400/20 = 20 m/sec speed( in km) = 20 * 18/5 = 72 km/hr from statement II, time = 252/72 = 3.5 hr statement II and III required to get answer.
What is the length of a running train A crossing another running train B ? I. A and B two train take 18secs to cross each other, while running opposite direction. II. The length of train B is 180m
Only I and II is sufficient
Only II is sufficient
Either I or II statement
Neither I nor II is sufficient
Only I sufficient
Option D Length of train A = l meters from I, time taken by train to cross each other = 18secs let speed of train A and B = x and y respectively relative speed of A and B = (x + y) m/s from II, length of train B = 180 meters 180 + l/x + y = 18 thus, we can not calculate answer by using these two statements.
What will be respective ratio of saving of A and B. I. Income of A is 4% less than that of C and also expenditure of A is 12.5% less than that of C. B spend 3/5 th of his income. II. C save rs. 7000 and A save rs.7400. Income of B is rs.1000 more than that of C.
Only I is sufficient
Only II is sufficient
Either I or II statement
Neither I nor II is sufficient
Only I and II is sufficient
Option E Let income of C = 25x income of A = 25x * 96/100 = 24x let expenditure of A = 7y expenditure of C = 8y B spend 3/5 th of his his income from II saving of C = 7000 saving of A = 7400 Income of B is 1000 that of C from I and II, expenditure of A = 24x – 7y = 7400 expenditure of C = 25x – 8y = 7000 by solving two equations, x = 600 and y = 1000 income of B = 25 * 600 + 1000 = 16000 saving B = 16000 * 2/5 = 6400 Ratio = 7400 : 6400 = 37 : 32 statement I and II is required
What is the CI on a sum at the end of 3 years ? I. CI at the end of two years is rs.110 II. Difference between CI and SI at the end of two year is rs.100 and rate of percent is 10%.
Only I is sufficient
Only II is sufficient
Either I or II statement
Neither I nor II is sufficient
Only I and II is sufficient
Option B From I, Sum can not be find out as rate is not given From II, Difference PR^2/100^2 100 = P *100/10000 P = 10000 only statement II is sufficient.
I. x^2v- 41x + 348 = 0 II. y^2 – 20y + 99 = 0
X < Y
X > Y
X ≥ Y
X ≤ Y
X = Y or no relation.
Option B I. x^2 – 29x – 12x + 99 = 0 x = 29, 12 II. y^2 – 11y – 9y + 99 = 0 y = 11, 9
I. 2x^2 – 2x _ 24 = 0 II. 3y^2 – 8y + 4 = 0
X < Y
X > Y
X ≥ Y
X ≤ Y
X = Y or no relation.
Option E I. 2x^2 – 8x + 6x – 24 = 0 x = 8, – 6 x = 4, -3 II. 3y^2 – 6y – 2y + 4 = 0 3y = 6, 2 y = 2, .67
I. 5x^2 – 28x + 15 = 0 II. 3y^2 – 29 y + 68 = 0
X < Y
X > Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option E I. 5x^2 – 25x – 3x + 15 = 0 5x = 25, 3 x = 5, .6 II. 3y^2 – 17y – 12y + 68 = 0 y3y = 17, 12 y = 5.66, 4
I. x^3 = 4913 II. y^2 = 225
X < Y
X > Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option B I. x^3 = 4913 x = 17 II. y^2 = 225 y = 15, -15
I. 2x^2 – 20x + 48 = 0 II. y^2 – 15y + 56 = 0
X < Y
X > Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option A I. 2x^2 – 12x – 8x + 48 = 0 2x = 12, 8 x = 6, 4 II. y^2 – 8y – 7y + 56 = 0 y = 8, 7
