A shopkeeper X sold an article for rs.850 at a profit of 25%. Another shopkeeper Y sold the another article and earned 30% more profit than the profit earned by X. If the selling price of article Y is three-fifth of selling price of article X, then find the profit percent of article Y ?
64 2/17%
76 8/17%
52 3/34%
52 3/8%
78%
Option B SP of article X = 850 CP of article X = 850 * 100/125 = 680 profit = 170 profit of article Y = 170*130/100 = 221 SP of article Y = 850 * 3/5 = 510 CP = 510 – 221 = 289 profit percent = 221/289* 100 = 76 8/17%
Mixture A contains milk and water in the ratio of 3 : 2 respectively, while mixture B contains water and milk in the ratio of 4 : 3 respectively. If the quantity of water in mixture B is twice the quantity of water in mixture A, then find the quantity of milk in mixture A is what percent quantity of water in mixture B ?
68%
60%
82%
75%
56%
Option D Quantity of milk and water in mixture A = 3x and 2x according to questions, quantity of water in mixture B = 2*2x = 4x quantity of milk in mixture B = 4x/4 *3 = 3x required percentage = 3x/4x*100 = 75%
340 liters of mixture of milk and water is contained in a container having milk and water mixed in the ratio of 3 : 1 respectively. 76 liters of this mixture is taken out from the container and replaced with (x + 7) liters of milk so that the ratio of water to milk is 6 : 11. What is the value of ‘x’ ?
42
48
38
35
52
Option D Quantity of milk in the container = 340 * 3/4 = 255 quantity of water in the container = 340*1/4 = 85 76 liters of mixture is taken out and (x + 7) liter of water is added. (255 – 57) / 85 – 19 + (x + 7) = 11/6 198/(73 + x) = 11/6 11x = 385 x = 35
A can do a piece of work in 30days while B and C together can complete the work in 20 days and A and C together can complete the work in 24 days. If B is worked in two-fifth of his efficiency, then in how many days A and B together complete half of the work ?
8 days
6 days
8 1/3 days
5 days
10 days
Option E LCM of 30 , 20 and 24 = 120 efficiency of A = 120/30 = 4 efficiency of B and C = 120/20 = 6 efficiency of A and C together = 120/24 = 5 efficiency of C = 5- 4 = 1 efficiency of B 6- 1 = 5 two-fifth of efficiency B = 5 * 2/5 = 2 time required to complete half of the work = 60/2 + 4 = 10 days
Rohan and Sivan started a business together with initial investments of rs. 1500 and rs.1800 respectively. If after 2.5 years profit share of Rohan and Sivan are rs(x + 80) and (x + 120) respectively, then find the difference between profit of Rohan and Sivan ?
180
120
320
130
340
Option B Profit sharing ratio of Rohan and Sivan = (1500 * 2.5) : (1800 * 2.5) = 5 : 6 x + 80/x + 120 = 5/6 6x + 480 = 5x + 600 x = 120
Directions : In each of these questions given below two equations. You have to solve both the equations and give answer. I. x^2 – 7√3 + 36 = 0 II. y^2 – 6√2 + 16 = 0
X > Y
X < Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option E I. x^2 – 4√3 – 3√3 + 36 = 0 x = 4√3 , 3√3 II. y^2 – 4√2 – 2√2 + 16 = 0 y = 4√2, 2√2
I. x^2 + √2x – 12 = 0 II. y^2 – 8√3 + 48 = 0
X > Y
X < Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option B I. x^2 + 3√2 – 2√2 – 12 = 0 x = -3√2, 2√2 II. y^2 – 4√3 – 4√3 + 48 = 0 y = 4√3, 4√3
I. x^2 – 36 = 0 II. y^2 – 15y + 36 = 0
X > Y
X < Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option E I. x^2 = 36 x = 6, -6 II. y^2 – 12y – 3y + 36 = 0 y = 12, 3
I. y^2 = 144 II. 2x^2 – 12x + 16 = 0
X > Y
X < Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option E I. y^2 = 144 y = 12, -12 II. 2x^2 – 8x – 4x + 16 = 0 2x = 8, 4 x = 4, 2
I. x^2 – 2x – 195 = 0 II. y^2 – 24y + 128 = 0
X > Y
X < Y
X ≤ Y
X ≥ Y
X = Y or no relation.
Option E I. x^2 – 15x + 13x – 195 = 0 x = 15, -13 II. y^2 – 16y – 8y + 128 = 0 y = 16, 8
